Thank you point out one error. the question text is not clear, I can rewrite it as"In an ideal star-delta (Y-Δ) transformer configuration with a 1:1 turns ratio and no losses, what happens to the phase voltage on the secondary side compared to the primary side?"Thanks
@@himanshupatel1507 In an ideal star-delta transformer with a 1:1 turns ratio and no losses, the phase voltage on the secondary side is equal to the phase voltage on the primary side. This is because the turns ratio determines the relationship between the primary and secondary phase voltages, and a 1:1 ratio means they are the same. the transformer formula is only working on phase voltage. Thanks.
please Answer 39- for star delta configuration how (69 v)
Confirmed the answer is right. Please follow transformer calculation steps to do this calculation. it is hard topic. Thanks.
@@ITOElectrical thanks I got it full answer, your transformer calculation process is very easy.
please confirm answer 32, in Delta phase voltage = line voltage
Thank you point out one error. the question text is not clear, I can rewrite it as"In an ideal star-delta (Y-Δ) transformer configuration with a 1:1 turns ratio and no losses, what happens to the phase voltage on the secondary side compared to the primary side?"Thanks
@@ITOElectrical reduce by 1.732
@@himanshupatel1507 In an ideal star-delta transformer with a 1:1 turns ratio and no losses, the phase voltage on the secondary side is equal to the phase voltage on the primary side. This is because the turns ratio determines the relationship between the primary and secondary phase voltages, and a 1:1 ratio means they are the same. the transformer formula is only working on phase voltage. Thanks.