Uniform Circular Motion Class 11
HTML-код
- Опубликовано: 21 окт 2024
- Uniform Circular Motion Class 11
Our Website: bit.ly/2KBC0l1
Android App: bit.ly/3k48zdK
CBSE Class 10 Courses: bit.ly/363U55V
CBSE Class 9 Courses: bit.ly/39Pm7mM
CBSE Class 8 Courses: bit.ly/3bJByzB
ICSE Class 10 Courses: bit.ly/2MaXpFo
ICSE Class 9 Courses: bit.ly/3iFV7dl
ICSE Class 8 Courses: bit.ly/3boM5OB
IGCSE Courses: bit.ly/2YNwQcn
Artificial Intelligence: www.manochaaca...
Python Coding: bit.ly/3nX0s2y
Java Coding: bit.ly/3chHTAK
Facebook page: bit.ly/2s6VYhf
Uniform circular motion in physics refers to the motion of an object traveling in a circular path at a constant speed. Several key characteristics define uniform circular motion:
1. Constant Speed: In uniform circular motion, the object moves around the circle with a constant speed. This means that the magnitude of the object's velocity remains the same throughout its motion.
2. Circular Path: The object follows a circular trajectory, which means it travels along the circumference of a circle.
3. Centripetal Force: To maintain its circular path, the object must experience a centripetal force directed toward the center of the circle. This force is responsible for keeping the object from moving in a straight line and causing it to continuously change direction.
4. Tangential Velocity: Although the object's speed remains constant, its velocity is not constant in direction. The velocity vector is always tangent to the circle at the point where the object is located, and its direction changes as the object moves around the circle.
5. Angular Velocity: Uniform circular motion is often described in terms of angular velocity, denoted by the Greek letter omega (ω). Angular velocity represents the rate of change of angular displacement and is measured in radians per second (rad/s). The relationship between linear speed (v), radius (r), and angular velocity (ω) is given by v = ωr.
6. Period and Frequency: The time it takes for the object to complete one full revolution around the circle is called the period (T), while the number of revolutions per unit of time is referred to as the frequency (f). These are related by the equation f = 1/T.
Uniform circular motion is a fundamental concept in physics and can be found in various real-world scenarios, such as the motion of planets in their orbits, the rotation of wheels, and objects moving in circular tracks or roller coasters. Understanding uniform circular motion is essential for analyzing and predicting the behavior of objects undergoing this type of motion and for solving problems related to centripetal forces and accelerations.
In circular motion, there can be three types of acceleration involved:
1. Linear or Tangential Acceleration
2. Centripetal Acceleration
3. Angular Acceleration
At Manocha Academy, learning Science and Math is Easy! The school coursework is explained with simple examples that you experience every day! Yes, Science & Math is all around you! Let's learn every day from everyday life!
For LIVE Classes, Concept Videos, Quizzes, Mock Tests & Revision Notes please see our Website/App
👉Our Website: bit.ly/2KBC0l1
👉Android App: bit.ly/3k48zdK
I am from ethiopia I really appreciated you you are helping us alotif you can continue to us grade 11 we were happy
Aw btam
CSPS ?
👍
From Zambia !!
From milky way 😅........
I have already completed circular motion, but still came here to watch your interesting way of teaching , Lots of love Sir❤
Thanks! Great to hear you like the videos 🙂
25:29 linear velocity =2.2m/s
Centripetal acceleration=69.14m/s²
Bro how??
@@shanumfathima1366 i am in class 9 and I also solved the question
how is acceleration greater then velocity
a=v^2/r
a=2.2 x 2.2 /7
a=0.6914ms-2
@@gamersuperstrike4847 yay?
In a Uniform Circular Motion, the speed v remains constant.
If the object makes n revolutions (cycles) in a time t, then it travels a distance s:
s = 2 • 𝜋 • r • n
and
v = s / t = (2 • 𝜋 • r • n) / t
Since v = ω • r, then
ω • r = (2 • 𝜋 • r • n) / t.
This implies that
ω = (2 • 𝜋 • n) / t
If
ω = 2 • 𝜋 • f
where f is the frequency, then
2 • 𝜋 • f = (2 • 𝜋 • n) / t.
This implies that
f = n / t
where n is the number of revolutions, n is dimensionless, n has unit rev/rev = 1.
Since the period T = 1 / f, then
T = t / n.
Since the period T is the time it takes for the object to complete one revolution (one cycle), then the unit of T is:
s/(rev/rev) = s
equal to seconds per number of revolutions (second per number of cycles).
Since the frequency f is the number of revolutions (cycles) per unit time (usually seconds), the unit of f is:
(rev/rev)/s = Hz = 1/s
equals the number of revolutions (number of cycles) per second [nrps = (rev/rev)/s, if you want to keep the custom], and not in revolutions per second (rps).
The unit hertz (Hz) replaced the unit cycles per second, which is actually the number of cycles per second.
Finally, it is understood that in the formula
ω = 2 • 𝜋 • f
the unit conversion is
1 (rad/rad) = 2 • 𝜋 • (rev/rev).
This confirms the unit of angular velocity ω which is (rad/rad)/s = 1/s.
I have a very simple but question.
Why doesnt the object collapse into the point.
Since the centripetal force is an acceleration is increasing with time it should get to a point where its high enough to pull the object towards its centre.
For example:
The electron in an atom if not for its stationary state it should be pulled towards the nucleus since the proton and nucleus attract but what keeps it moving in a circular path is the fact that they have fixed energy called stationary States so they can't lose energy.
But objects in the real world dont have fixed energy level so what keeps them in circular path?
Another example is that if we change the mechanics occurring on the body interms of force, The centripetal force will be the F=m×a but converting the objects tangential velocity into force its F=0 since it has no acceleration.Resolving the 2 forces the object is supposed to move towards the center so why does it still move circular
Centripetal force is constant. Unless the radius or mass is changed
If the applied force is constant then the acceleration will be also constant ❤❤❤
the odds of it happening that i was just studying this chapter when you uploaded this! 😂 I've been following you since my 9th grade, and now I'm in 11th and preparing for jee!! Props to you, you are awesome, one day i would love to meet you when i reach college ❤
Wow what a coincidence 😀 Great to hear you have been watching our videos! Do share our channel with your friends!
Same here 😂
Answer -
Linear Velocity = 2.199 m/s
Centripetal Acceleration = 69.08 m/s²
The answer is wrong my brother the real ans is v=1.4πm/s
And Ac=14π^2m/s^2
@@embibelite9221 bro you didn't solved pie his answer is almost correct
m = 5 kg
Diameter = 14cm = 0.14m
Radius =0.07m
f = 300/60= 5hz
v = rw = r x 2πf
= 0.07x2x22/7x5
= 0.088m/s
a = w²r=69.14 m/s²
Linear velocity = 2.2m/s not 0.088m/s
Itne confidence se galat answer kyun likha hai
Sirf linear velocity toh nikalna tha so why. Didn't we simply use the formula v=rw???
I am from Nigeria I really appreciate it sir
Learning from you since 9th...in 11th now....Thanks a lot for playing an important role in strengthening my science concepts...😊
Such an amzing teacher .you are the brightest light for me in physics . Never get bored after watching your videos
Sir I am a student of class 11. Can you please make videos on calculus especially on integrations, because I am facing a lot of difficulty in learning calculus
Crystal clear❤... U r method of teaching must appreciating.... God bless you for your free services.
Sir I Will be really thankful if you start making solution videos of HC Verma questions, full support from my side❤
We are uploading more videos of Class 11 :) Stay tuned ...
i am from Ghana i really love and appreciate your teaching 👏👏
You name the topic and Manocha Academy is there for you😍😍
Linear velocity 2.19 m/s
Centripetal acceleration 69.18 m/s2
Thank you ...I waiting for ...11& 12th mpc Course... Excellent teaching Sir ...
linear velocity:-219.8m/s
centripetal acceleration=(220*220)/7
Sar you are beter than other teacher
I had already completed circular motion but still I want to listen your classes they are awesome
Such an amazing teacher. sir is very helpful
Thanks l am very happy to watch thise video and please continue calss 11 physics video
Great to hear that you liked the video. We will be uploading more Class 11 videos!
Thanks for this sir. Sir what differentiate circular motion from rotational motion?
Epic Video Sir!!! I was introduced to betals by you, And I LOVE it! 😆(Yellow Submarine is my Fav)
Sir I have a doubt in 2:26 in that the displacement must be zero. But how you consider 360 degree
Best video to understand this topic
May be
Linear velocity:43.96
Centripetal force:1.12
LINEAR VELOCITY = 2.2m/s CENTRIPETAL ACCELERATION= 69.14m/s^2
This really helps a lot Sir ❤❤❤❤
Linear velocity is 2.189 radian per second
Centripetal acceleration is 690.17 radian per second square
Sir pls answer
Is tungsten a conductor of electricity or insulator ?
Conductor
Sir, I'm in 11th now. Could you please upload videos on your website for physics and chemistry (class 11)?
Your physics videos helped me prepare for my boards in 10th.
Now, I've also enrolled for the Python course. Love it ❤️
Why suddenly 2pie radian becomes 2pie only where is radian in formula
Angle is dimension less quantity. Just a number.
Most Underrated video my dear sir your concept are very helpful 🙏 thanks love from utter pardesh
I'm from gambella Ethiopia I highly appreciate you for your great job, just no more, continue 🙏🏿
Thank you so much sir
Uniform circular motion has no acceleration. There is no linear vector(except in the imagination), therefore no centripetal acceleration or force. The only force acting on the coin is away from the centre and is called the centrifugal force, that at sufficient speed of the table, will cause the overcoming of stiction and then a complete change of mechanism occurs. There are centrifuges manufactured but no centripetal machine exists.
Linear velocity = 219.8 m/s
Centripetal acceleration= 6901 m/s^2
Sir am i correct or not
I think centripetal acceleration is 6815
Linear velocity is 4.4m/s
1 rev = 2pie rads(2×3.142)
300rpm=(300×2×3.142)/60since me want to change minute to seconds.
300rpm=31.42rads/s
Velocity = radius×angular vel.
=7× 31.42
=219.94cm/s
Or we change 14cm to m to get it in m
7cm=0.07m
Velocity=0.07×31.42
=2.2m/s
Centripetal acceleration will be 69.14m/s^2
Angular acceleration and tangential acceleration are both zero 24:52
Why?
@@ROHIT-yi5dt Only centripetal acceleration exists in a body that is moving in uniform circular motion
thank you sir. very clear explanation.
Lovely sir appreciating your hard work behind each video ❤❤
I understand physics by your brief explanation am following from grade 8 to10 i am really happy if you make a video on"vector"please
thankyou so much for making it simpler to understand 🌸✨
My fav youtube teacher
Thanks 😊
sir, your explanation is far much better than my school teacher
Please sir what is the difference between circular uniform motion and periodic motion
I really do appreciate your videos. Thanks a lot. My answer is v=7916.8
I have been watching your videos for about 2 years still they are very good
Linear velocity=2.2 m/s
Centripetal acceleration=6.9m/s^2 approx
Hi
Give me full slove answer
Please
May i know the answer of the question that you give us in the end of the video
Please
Thank you 😢
I think v bar = omega ×r not r×omega ......is it right please check.....
Good job sir
Thanks
Nice video, sir. Thank you so much, sir
That's what we want to see ❤❤❤
You are amazing sir, thank you for this wonderful explanation ❤😊
Thank you So much sir for making physics videos of class 11
Hi sir will this video help me with my A2 class?
Sir please provide videos based on the syallabus of neet and jee.
Excuse me sir ,
where are you from sir
😊
14:20
Love you sir from Afghanistan! ❤️
Here pie means 180 know sirr
Yes, Pi radians is 180 degrees
Sir pls share the answer of the numerical with us....
Thankyou sir❤❤
Does it rotational motion
Hello Sir Have Phisics question can I Send you
pls can you also do videos for class 12🙃 pls i pass class 11 and it is with your help thanks and pls 😍
Sir, screen par text English me rahne dijiye but Hindi me samjhaya kijiye please
Many people wonder why radians do not appear when we have radians*meters.
Here is an attempt at an explanation:
Let s denote the length of an arc of a circle whose radius measures r.
If the arc subtends an angle measuring β = n°, we can pose a rule of three:
360° _______ 2 • 𝜋 • r
n° _______ s
Then
s = (n° / 360°) • 2 • 𝜋 • r
If β = 180° (which means that n = 180, the number of degrees), then
s = (180° / 360°) • 2 • 𝜋 • r
The units "degrees" cancel out and the result is
s = (1 / 2) • 2 • 𝜋 • r
s = 𝜋 • r
that is, half of the circumference 2 • 𝜋 • r.
If the arc subtends an angle measuring β = θ rad, we can pose a rule of three:
2 • 𝜋 rad _______ 2 • 𝜋 • r
θ rad _______ s
Then
s = (θ rad / 2 • 𝜋 rad) • 2 • 𝜋 • r
If β = 𝜋 rad (which means that θ = 𝜋, the number of radians), then
s = (𝜋 rad / 2 • 𝜋 rad) • 2 • 𝜋 • r
The units "radians" cancel out and the result is
s = (1 / 2) • 2 • 𝜋 • r
s = 𝜋 • r
that is, half of the circumference 2 • 𝜋 • r.
If we take the formula with the angles measured in radians, we can simplify
s = (θ rad / 2 • 𝜋 rad) • 2 • 𝜋 • r
s = θ • r
where θ denotes the "number of radians" (it does not have the unit "rad").
θ = β / (1 rad)
and θ is a dimensionless variable [rad/rad = 1].
However, many consider θ to denote the measure of the angle and for the example believe that
θ = 𝜋 rad
and radians*meter results in meters
rad • m = m
since, according to them, the radian is a dimensionless unit. This solves the problem of units for them and, as it has served them for a long time, they see no need to change it. But the truth is that the solution is simpler, what they have to take into account is the meaning of the variables that appear in the formulas, i.e. θ is just the number of radians without the unit rad.
Mathematics and Physics textbooks state that
s = θ • r
and then
θ = s / r
It seems that this formula led to the error of believing that
1 rad = 1 m/m = 1
and that the radian is a dimensionless derived unit as it appears in the International System of Units (SI), when in reality
θ = 1 m/m = 1
and knowing θ = 1, the angle measures β = 1 rad.
In the formula
s = θ • r
the variable θ is a dimensionless variable, it is a number without units, it is the number of radians.
When confusing what θ represents in the formula, some mistakes are made in Physics in the units of certain quantities, such as angular speed.
My guess is that actually the angular speed ω is not measured in rad/s but in
(rad/rad)/s = 1/s = s^(-1).
Appload more lecture plz
Beautiful
Amazing!
v=2.1980 m÷s , ač=69.017200 m÷s²
Yooo. You would look really cool with a beard man
❤❤❤
good
I am also in 11th from Pakistan
Almost everyone is in 11th i guess after reading these comments
1st😅
Thanks for watching!
Kash me 11th me hota😊😊😊
Aa na pata chalega😊
😊😊 ek baar aja Bhai boht maza ayega
Sir i want to translate your words in Bengali please
The answer for the question:
Vt= 2.19 radm/sec and ac= 69.02 rad/sec2
How
Mera bhi same aaya😎
Sir is this acedmy not make videos for bs students of physics
English , physical science, chemistry
Yr vector relation is wrong
Second
Thanks for watching so fast!
But I from Ethiopia and I need multiple questions with answers
Wow SIR!! This is truly amazing!!
Really Great You are receiving these from RUclips!!!
Hats off! An amazing Video! Loved the explanation!
JUST AMAZING!!!~
I am from Nigeria sir I really appreciate it
Thank you sir