I go to Tidewater Community College in the Hampton Roads area and they have a really good program. This is the closest thing I have found to how we are taught. Nice work!
if one of the voltage source is in the middle of the circuit which is in series with 12 Ohm of resistor, then it will have 1 clockwise-loop and 1 anti-clockwise-loop of currrent?
"Which source do you want to pick? - I don't care which one you want to do first because Im going to do the 54 volt first." This professor would make a great character in Dora the explorer Haha
+ahmed waheed You are quite correct in your thinking, and you would be actually correct if you were working out the individual voltages of resistors in a series circuit, as it is essentially a "ratio calculation", but remember it is a little different when working with currents in parallel. Even though all paths in the branch add up to the source current, the current always takes the path of least resistance. So based on your outcome, you just have your current values in the opposite resistors. So if you have a 2 ohm resistor in parallel with a 4 ohm resistor (Draw this), and your source current is 9A, the 9 Amperes branches off into their respective paths - the LARGER portion of the current will go through the SMALLER value resistor. So 6 Amperes will travel through the 2 ohm, and 3 amperes will travel through the 4ohm. Current is INVERSELY PROPORTIONAL to resistance, meaning that as the current increases, the resistance is decreased. Don't confuse this with series circuits where larger resistors experience the larger voltage drop.
+samuelade Instead of wasting space on the internet that could've been filled with a more intelligent comment, why don't you attempt to contribute? Or is that too hard?
No!!! I = 9*(12/12+6)= 6A..This is called the Current Divider Rule which Is Different Than The Voltage Divider Rule You are Trying To Find The Current Through The 6 ohm resistor so You use the adjacent Resistor on the top part of the equation which is 12 ohms
Technically he didn't leave out a step. If your watching a video on superposition, its assumed you know how to calculate the resistance for a parallel or parallel-series circuit.
why the fina I(12) is equal to I''(12) - I'(12)? and why the result is 2,17? 2.67 - 5 = - 2.33A... Also i have an other question why I(12) must going up i thought it should be going down becouse I''(12) < I'(12)
u didnt explian how u got the 8 u just went on u need to explain every step by step i seen how u did the other side with like a hr trying to figure it out as for the red side u lost me dont know how u got the 8 EXPLAIN BETTER
Great instructions but please quit leaving out steps! How did you get the 12 and 4 ohms = 3.. I got it but i had to figure it out! That's like me telling you theres three rocket ships outside only one one has enough fuel to reach the moon safely. Now go to the moon!
Man, youtube videos make it so much easier to understand than class.
The most simplified explanation ever. Award deserving. Nice one Jim!
Crazy to think this guy has helped over thirty thousand people. Well done sir.
I go to Tidewater Community College in the Hampton Roads area and they have a really good program. This is the closest thing I have found to how we are taught. Nice work!
how do you work out the way the current flows??
lets say we had multiple voltage sources, do we short circuit them one by one and loop the same procedure?
Please use the new updated DC Superposition Theorem online lecture at ... ruclips.net/video/19Ft6CzdHHU/видео.html
if one of the voltage source is in the middle of the circuit which is in series with 12 Ohm of resistor, then it will have 1 clockwise-loop and 1 anti-clockwise-loop of currrent?
Doesn't current flow positive to negative out of the voltage source? Should the arrows have been reversed?
How are the 12 and 4 parallel since they dont share the same nodes?
Min 5:20
Thanks Jim for the course refresher. It's very helpful
Thank you very much Jim Pytel , it's very useful Lesson , i just want to know how did you Calculate the current through R1 its I1=A*(R1/Rt) isn't it ?
"Which source do you want to pick? - I don't care which one you want to do first because Im going to do the 54 volt first."
This professor would make a great character in Dora the explorer Haha
Hello, if the currents i' and i'' are opposite direction , but they have the same current, does that mean the current is equal to 0?
how to get the 3? i managed to get 3.2
why the i2=6 in the the second circuit ?
it should be i=9*(6/12+6) = 3A
Right ?
+ahmed waheed do u even maths bruh
+ahmed waheed You are quite correct in your thinking, and you would be actually correct if you were working out the individual voltages of resistors in a series circuit, as it is essentially a "ratio calculation", but remember it is a little different when working with currents in parallel. Even though all paths in the branch add up to the source current, the current always takes the path of least resistance. So based on your outcome, you just have your current values in the opposite resistors.
So if you have a 2 ohm resistor in parallel with a 4 ohm resistor (Draw this), and your source current is 9A, the 9 Amperes branches off into their respective paths - the LARGER portion of the current will go through the SMALLER value resistor. So 6 Amperes will travel through the 2 ohm, and 3 amperes will travel through the 4ohm. Current is INVERSELY PROPORTIONAL to resistance, meaning that as the current increases, the resistance is decreased.
Don't confuse this with series circuits where larger resistors experience the larger voltage drop.
+samuelade Instead of wasting space on the internet that could've been filled with a more intelligent comment, why don't you attempt to contribute?
Or is that too hard?
dannyboyinxs u mad bro?
No!!! I = 9*(12/12+6)= 6A..This is called the Current Divider Rule which Is Different Than The Voltage Divider Rule You are Trying To Find The Current Through The 6 ohm resistor so You use the adjacent Resistor on the top part of the equation which is 12 ohms
Technically he didn't leave out a step. If your watching a video on superposition, its assumed you know how to calculate the resistance for a parallel or parallel-series circuit.
ahh but jim pytel has been quite the powerful maaan in my life, yiiiiiissssss.
I didn`t get it why the final current
5A - 2.67A = 2.33A
Thank You for a Most Excellent Explanation of Superposition
Wonderful video. Got the general understanding
why the fina I(12) is equal to I''(12) - I'(12)? and why the result is 2,17?
2.67 - 5 = - 2.33A... Also i have an other question why I(12) must going up i thought it should be going down becouse I''(12) < I'(12)
can you please make a video involving dependent sources? thanks :)
how did you end up with 2.17 A? 2.67-5 = -2.33
could you explain this pls?
yeh thanks m8 spotted it eventually lol
clear teaching... thank you very much...
how i got 3 i (4x12)+24=72 then 72/24=3
u got max power trnasformed at R=100ohms,,,,,,,,bt it shud be R=Rth????????????
it's 2.67 - 0.5. many people just use dot to write it.
I don't think 4 and 12 in parallel is 3
Thanks a lot :) this was so clear !!!
thanks .... learned a lot......
It's 0.5A not 5A.
GOOD
very well explained, thank you it helped a lot.
sorry i see its 0.5 A
Your amazing
well explained!
your making this alot more complicated then it should be
Thank you so much for this
thanks mate!!!!
Thanks
u didnt explian how u got the 8 u just went on u need to explain every step by step i seen how u did the other side with like a hr trying to figure it out as for the red side u lost me dont know how u got the 8 EXPLAIN BETTER
Best Explanation!
slowwwww and niceeeeee!
im here cause of impractical jokers
Great instructions but please quit leaving out steps! How did you get the 12 and 4 ohms = 3.. I got it but i had to figure it out! That's like me telling you theres three rocket ships outside only one one has enough fuel to reach the moon safely. Now go to the moon!