How enjoyable you make the learning journey. You cannot begin to imagine how much respect I have for you. I would post a long, heartfelt 'thank you' message under each and every one of your posts, if not for holding myself back so as not to waste your time reading them all. But sometimes, I just can't. Once again, thank you so much for your time and effort Michel, and your wife, the unsung hero who I'm sure is just as big a part of these videos as you are. The world is such a better place with you two in it. Thank you!
I would like to thank you for all of these lectures you provide. As an electrical engineering student, you are allowing me to do my classes at a pace and quality my professors' lectures cannot hope to match. Cheers to the future and stay well.
Simply Beautiful, Professor! Thank you very much indeed for your time and creating this wonderful electrical and electronic tutorial series. I’ve watched many so far and they’re all clear, concise and fun with informative problem solving on crucial topics. Invaluable for students. Kindest regards. Craig.
Sorry sir i wanna ask, why on the I1 the inductor become sort?, *ps still new at learning inductor conductor stuff and sorry for my bad english since its not my first language
When there is a steady state voltage source (in this case the 8V source) the inductor offers no impedance to a steady state current and acts like a short. For an inductor to have impedance, the current needs to change.
Since the two voltage sources are working on different frequencies (4 rad/s for the left source, 0 for the right source), isn't it incorrect to simply add them, with the result being, instead, 0.791cos(4t - 71.57) + 4?
How enjoyable you make the learning journey. You cannot begin to imagine how much respect I have for you. I would post a long, heartfelt 'thank you' message under each and every one of your posts, if not for holding myself back so as not to waste your time reading them all. But sometimes, I just can't. Once again, thank you so much for your time and effort Michel, and your wife, the unsung hero who I'm sure is just as big a part of these videos as you are. The world is such a better place with you two in it. Thank you!
After having put in tens of thousands of hours building this channel my wife and I appreciate comments like yours. Thank you.
I would like to thank you for all of these lectures you provide. As an electrical engineering student, you are allowing me to do my classes at a pace and quality my professors' lectures cannot hope to match. Cheers to the future and stay well.
Glad you found our videos and that they are helping. 🙂
Here again Sir! So thankful for these lectures! They'll be stored for us when we reach our engineering.
Sheer respect Sir!
Simply Beautiful, Professor! Thank you very much indeed for your time and creating this wonderful electrical and electronic tutorial series. I’ve watched many so far and they’re all clear, concise and fun with informative problem solving on crucial topics. Invaluable for students. Kindest regards. Craig.
Craig. Thank you for your upbeat and encouraging words. 🙂
Sorry sir i wanna ask, why on the I1 the inductor become sort?, *ps still new at learning inductor conductor stuff and sorry for my bad english since its not my first language
When there is a steady state voltage source (in this case the 8V source) the inductor offers no impedance to a steady state current and acts like a short. For an inductor to have impedance, the current needs to change.
@@MichelvanBiezen Why dont you do the same in the second circuit? v=10, It has the same form!
Hello, why do you not do the same process in the second circuit? Is the 10 ∠ 0 not considered a steady state voltage source?
The 10 V source is given as 10V (cos 4t) which indicates that it is a time varying source
Since the two voltage sources are working on different frequencies (4 rad/s for the left source, 0 for the right source), isn't it incorrect to simply add them, with the result being, instead, 0.791cos(4t - 71.57) + 4?
If they were on the same branch you could add them up that way. (The 8V source is DC voltage). But since they are not on the same branch you cannot.
"Wonderful Explanation Sir 😄😄😄😄😄😄😄."
Thank you so much 😀
for that 10cost4t voltage, isn't that 10V peak voltage? shouldn't everything be calculated with RMS values when using Ohm's law?
wait nvm, we're not looking for time instantaneous values, rather current through the inductor as a function of time
As it turns out you can use either RMS values or peak values to work out the problems as long as you don't mix them.
@@MichelvanBiezen Oh I see, thanks sir!
cant we use node analysis here
There are 7 different methods of solving circuits and any method can typically be used. It comes down to a personal preference given the choice.
@@MichelvanBiezen maybe when different frequencies are given then only we use superposition....is this true ?
@@MichelvanBiezen and btw how to find power when diff frequencies present..i cant find any video related pls help
Not sure about what you mean by: "when different frequencies are given".
Typically a circuit has a single power source at one particular frequency.
Of course Mr. Biezen, it's magic!!!!!
Thank you. (This method strangely works).
king of the whiteboard!
I like that title! 🙂
I Love Your Style Of Teaching :) 🔥🔥🔥🔥🙏👍✌👌👏😇
Happy to hear that!
I think the value of I1 is wrong.
What do you think it should be?
Magic...
Glad you think so.