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00:03 Understanding Distance and Time concepts in Aptitude 01:27 Calculating time reduction when speed changes 03:30 Calculating time and distance for empty tires 05:20 Calculating cost and distance for empty tires 07:36 Calculating time and distance using speed 10:00 Understanding time, distance, and equation calculation 14:00 Discussion on time, distance, and equality 16:47 Time and distance calculations differ for time units in seconds and minutes Crafted by Merlin AI.
For the 2nd question, the question states that what is the distance that has been covered by each tire. So, the answer should be 8000km itself. 32000km is the distance that is left after the fist tire has covered the journey which is not what the question is asking for.
Ma'am you're no use in introduction you said that students who don't have any knowledge aptitude will learn from basic and while teaching you're doing calculations on your level. You're not explaining how calculations had been done you directly giving final answers and calculations
This is great, the quality of questions you are teaching is amazing. I don't know why there is so much negativity in comments. Your point is quite clear how we can use same formula in different conditions with language twist. Please keep up this good work, Thank you!
no, her explain is best level at all level for which she is making these videoes. These are not for 10th class student or not for those who don't know basic maths.
@@SumitK-n8p wahi na!! basic maths hi nai aa raha toh uske liye alag se video dekho bhai. comments me boht se students ko itni simple cheeze nai aa rahi aur placement ka apti crack krna hai 🤡
My question 3 and why wrong Sure! Here's a detailed step-by-step summary of how you approached and solved the problem: Problem Setup: Total distance to be traveled: 36 km. Two parts of the journey (A and B): Part A: Ram travels at 4 km/h. Part B: Ram travels at 3 km/h. In another scenario: In Part A, Ram travels at 3 km/h. In Part B, Ram travels at 4 km/h. The total time taken in both scenarios is equal. Your Approach: 1. Defining Variables: Let be the distance traveled in Part A and be the distance traveled in Part B. In the optimized case: (distance = speed × time for Part A) (distance = speed × time for Part B) In the non-optimized case: (distance = speed × time for Part A) (distance = speed × time for Part B) 2. Expressing Times in Terms of Distances: 3. Total Time (2T) in Both Scenarios: You said the total time is equal to the sum of all individual times for both parts: 2T = t1 + t2 + t3 + t4 This was rewritten as: 2T = \frac{36 - x}{4} + \frac{34 - x}{3} + \frac{x}{3} + \frac{x}{4} where is the distance covered in Part B. 4. Simplifying the Equation: You combined the fractions into a single denominator (12): 2T = \frac{3(36 - x) + 4(34 - x)}{12} + \frac{4x + 3x}{12} This simplifies to: 2T = \frac{3(36) + 4(34) - 3x - 4x + 4x + 3x}{12} The terms and cancel out. The equation becomes: 2T = \frac{3(36) + 4(34)}{12} 5. Calculating the Final Expression: Now, you multiplied the constants: 2T = \frac{108 + 136}{12} = \frac{244}{12} Simplifying: 2T = 20.33 6. Solving for Time : To find , you divided by 2: T = \frac{244}{24} = 1.1667 \, \text{hours} Conclusion: The time taken for each scenario is 1.1667 hours, which is the total time for both cases when the total distance traveled is 36 km. This time is the same in both scenarios, as per the problem's condition. Let me know if you need any further clarifications!
No proper explanation, she will not teach you step by step she will do the steps in her mind and then she will give you the answer it's not good for learning please avoid this series if you have very less time to study
mam app sikha rahe ho yad kudko sikha rhe rhe aptitude kyuki eak too itna teda meda likh rhe uprse question hame padhne bhi ni arha or app ho kuch step ese kyu kiya bina bole agge badhe jate hii .... kare to kre kya bole to bole kya ji
1st question it will be 25mins and t+30 with 5kmph and t+25 for 6kmph, if total time required is 't', the student took 25mins more and 30 mins more time with different speeds as he is late.
And ps : she gave the correct explanation as well, bcuz if u consider time in first case as t then in second case comparing with t in first case becomes t-25 bcuz he's early as compared to t in first case
You cannot write x/30 or x/20 because 30 min and 20 min are the total time taken to travel from the apartment to the office and not the distance they meet which is X.
X/30 and X/20 are the speeds of old and the young man. Their walking is constant weather they go to the office or the point at which they meet. So it's correct to write this.
wo 6km/h se chal rha h tb 5 min late phunchta h and 5km/h se chlta h tb 30 min late phunchta h (in t time)......to dono k time me reltion likhenge to yhi likhenge na ki baad me phle k comparison me 25 min km time le rha h........so t - 25.....km/h me h speed to 25 min ko bhi convert krna pdega so t - 25/60
another soln for que 1, soln- case 1= agr sahi time ko "t" lete h then eqn hoga 5*(t+30/60).......eq 1 case 2= 6*(t+5/60)............eq 2 on equating 1 and 2 eq we get t=2 hrs putting value of t in any above eq 5(2+30/60) => 5*2.5 =12.5
The expression t-25/60 represents the time taken in Case 2, where the student walks at a speed of 6 km/hr. Here's how it's derived: 1. The student is 25 minutes early when walking at 6 km/hr compared to walking at 5 km/hr. 2. 25 minutes can be converted to hours by dividing by 60, which equals (25/60) hours. 3. So, the time taken in Case 2 is "t" hours (the time taken at 5 km/hr) minus the time gained by being early, which is (25/ 60) hours. This gives us the expression t-25/60 for the time taken in Case 2.
kya explain karna hai usme---> jis time mai wo 3km/hr chala us time mai wo ab 4km/hr chalega or jis time mai wo 4km/hr chala ab us time mai 3km/hr chalega easy
@@next_level-2. Bhaii I don't have any placement drive... And moreover I don't want to... Just giving my opinion... Tujhe samajh raha hai toh bhot achi baat hai Mind your own preparation bastard💀 Or baaki comments bhi read kar liya kar... 90% audience ko nahi samjha hai
she cannot teach you step by step...you are at this point where you have to do these calculations on your own...if you are not able to do this also then don't do it...
. A student walks from hi shouse at 2.5 km/hr and reaches his school late by 6 minutes. Next day he increases his speed by 1 km/hr and reaches 6 minutes before school time. How far is the school from his house? I have doubt in this question.
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Easy solution for question 3:
3x + 4y = 36 and 4x + 3y = 34
Add both eq.
7(x + y) = 70 => x + y = 10
Hence answer is 10
Bdia ... tumne ye question ki practice khn se kri?
@@justauser-r4d bro that is the easy way of thinking. He is not changing the fundamental concept just making the calculation easier by thinking ahead.
@@jothishprabu8 ok 🌞
00:03 Understanding Distance and Time concepts in Aptitude
01:27 Calculating time reduction when speed changes
03:30 Calculating time and distance for empty tires
05:20 Calculating cost and distance for empty tires
07:36 Calculating time and distance using speed
10:00 Understanding time, distance, and equation calculation
14:00 Discussion on time, distance, and equality
16:47 Time and distance calculations differ for time units in seconds and minutes
Crafted by Merlin AI.
For the 2nd question, the question states that what is the distance that has been covered by each tire. So, the answer should be 8000km itself. 32000km is the distance that is left after the fist tire has covered the journey which is not what the question is asking for.
Honestly your explanation is nice , dono why its so much -ve out here
ya same bro
Ma'am you're no use in introduction you said that students who don't have any knowledge aptitude will learn from basic and while teaching you're doing calculations on your level. You're not explaining how calculations had been done you directly giving final answers and calculations
same bro same
As it is a campus placement series you should know the basic algebra.
u should know atleast this much if u r eligible for campus placements
If u understand explain in comment @@Professor-k3n
Bhai agr itna bhi basic ni ata to kese nikaloge campus placement 🤡
mam is cute and just her behaviour while talking is like my sister . Thanks for your time to teach us
hein?
This is great, the quality of questions you are teaching is amazing. I don't know why there is so much negativity in comments. Your point is quite clear how we can use same formula in different conditions with language twist. Please keep up this good work, Thank you!
you explain at your own level…not at our level….it is getting so difficult to understand your point….
i felt the same
If you didn't know these basic things, then science lekr ky jag mara tha?
@@SumitK-n8p basic se hi sikne ay ha expert hote to ate kaya? by the way her first video was fine but this one is like totally confusing.
no, her explain is best level at all level for which she is making these videoes. These are not for 10th class student or not for those who don't know basic maths.
@@SumitK-n8p wahi na!! basic maths hi nai aa raha toh uske liye alag se video dekho bhai. comments me boht se students ko itni simple cheeze nai aa rahi aur placement ka apti crack krna hai 🤡
My question 3 and why wrong
Sure! Here's a detailed step-by-step summary of how you approached and solved the problem:
Problem Setup:
Total distance to be traveled: 36 km.
Two parts of the journey (A and B):
Part A: Ram travels at 4 km/h.
Part B: Ram travels at 3 km/h.
In another scenario:
In Part A, Ram travels at 3 km/h.
In Part B, Ram travels at 4 km/h.
The total time taken in both scenarios is equal.
Your Approach:
1. Defining Variables:
Let be the distance traveled in Part A and be the distance traveled in Part B.
In the optimized case:
(distance = speed × time for Part A)
(distance = speed × time for Part B)
In the non-optimized case:
(distance = speed × time for Part A)
(distance = speed × time for Part B)
2. Expressing Times in Terms of Distances:
3. Total Time (2T) in Both Scenarios:
You said the total time is equal to the sum of all individual times for both parts:
2T = t1 + t2 + t3 + t4
This was rewritten as:
2T = \frac{36 - x}{4} + \frac{34 - x}{3} + \frac{x}{3} + \frac{x}{4}
where is the distance covered in Part B.
4. Simplifying the Equation:
You combined the fractions into a single denominator (12):
2T = \frac{3(36 - x) + 4(34 - x)}{12} + \frac{4x + 3x}{12}
This simplifies to:
2T = \frac{3(36) + 4(34) - 3x - 4x + 4x + 3x}{12}
The terms and cancel out.
The equation becomes:
2T = \frac{3(36) + 4(34)}{12}
5. Calculating the Final Expression:
Now, you multiplied the constants:
2T = \frac{108 + 136}{12} = \frac{244}{12}
Simplifying:
2T = 20.33
6. Solving for Time :
To find , you divided by 2:
T = \frac{244}{24} = 1.1667 \, \text{hours}
Conclusion:
The time taken for each scenario is 1.1667 hours, which is the total time for both cases when the total distance traveled is 36 km. This time is the same in both scenarios, as per the problem's condition.
Let me know if you need any further clarifications!
nice videos with proper explanation!
thank you
Question-2 was really brainstorming
~manan
No proper explanation, she will not teach you step by step she will do the steps in her mind and then she will give you the answer it's not good for learning please avoid this series if you have very less time to study
Go and study from class 5 again.
@@abinashdash876😂yes seriously. Those are really simple to solve.
We didn't understand mam
Ulta sidha padha rahi hai😂
Not we just you
Then don't watch
Samjhne k liye basic math aani chaiye..jais equations bnana , addition , subtraction😂@@SurajKumar-sn2np
Thanks mam for this awesome explanation.
💙
I think some people are expecting to explain 3+2=5...
true LOL
mam app sikha rahe ho yad kudko sikha rhe rhe aptitude kyuki eak too itna teda meda likh rhe uprse question hame padhne bhi ni arha or app ho kuch step ese kyu kiya bina bole agge badhe jate hii ....
kare to kre kya bole to bole kya ji
Not able to understand.....even mam is not so confident when solving questions 🙂
eaxctly
Mam is confident you r dumb
school bus tiffin khane jaata tha kya? itna basic math bhi nahi samjh raha
@@Hexzit tu pdane shuru kr de fer, kya pta smj aa jaye
Superb mam
1st question it will be 25mins and t+30 with 5kmph and t+25 for 6kmph, if total time required is 't', the student took 25mins more and 30 mins more time with different speeds as he is late.
i wasted so much time because of this
It will be t+30 for the second case
Use this
Let dist =x
So t+30 = x/5
t+5=x/6
Now sub the above we get
25/60 = x/5 - x/6
And solve for x
And ps : she gave the correct explanation as well, bcuz if u consider time in first case as t then in second case comparing with t in first case becomes t-25 bcuz he's early as compared to t in first case
You cannot write x/30 or x/20 because 30 min and 20 min are the total time taken to travel from the apartment to the office and not the distance they meet which is X.
X/30 and X/20 are the speeds of old and the young man. Their walking is constant weather they go to the office or the point at which they meet. So it's correct to write this.
mam 1st ques m t-25/60 smj nhi aana
wo 6km/h se chal rha h tb 5 min late phunchta h and 5km/h se chlta h tb 30 min late phunchta h (in t time)......to dono k time me reltion likhenge to yhi likhenge na ki baad me phle k comparison me 25 min km time le rha h........so t - 25.....km/h me h speed to 25 min ko bhi convert krna pdega so t - 25/60
@@sapnasaini851tumne in questions ki practice khn se kri?
Mujh to sb smj aarha h yr .y comments itne negative q h. Btw kl exam h 😂
😍
how in Q3 3y becomes 9y?
bhai lcm
practice exercise m second question kaise solve hoga ?
PnL, %, Mixture, Avg please
another soln for que 1,
soln-
case 1=
agr sahi time ko "t" lete h then eqn hoga 5*(t+30/60).......eq 1
case 2=
6*(t+5/60)............eq 2
on equating 1 and 2 eq
we get t=2 hrs
putting value of t in any above eq
5(2+30/60) => 5*2.5 =12.5
Where we can get extra questions
In third question why 34*3 becomes 17*1
it's because when we will take common from both (4*36) + (34*3) then it becomes 6*(4*6) + (34*(1/2))
@@raghavsharma2922 how in Q3 3y becomes 9y?
Same here
@user-vr9vq6gl8r Took lcm as 3 as the second term is divided by 3 and then 3 went the other side
Sab thik hai par....itna time hai hi nahi solve karne ke liye.....1 min hai bass aptitude round ke per question ke liye
ma’am i didn’t’t understand this part of yours
you don't tell us about the relative speed but in practice question u gave problem about relative speed u should cover all the problems in a topic
The expression t-25/60 represents the time taken in Case 2, where the student walks at a speed of 6 km/hr.
Here's how it's derived:
1. The student is 25 minutes early when walking at 6 km/hr compared to walking at 5 km/hr.
2. 25 minutes can be converted to hours by dividing by 60, which equals (25/60) hours.
3. So, the time taken in Case 2 is "t" hours (the time taken at 5 km/hr) minus the time gained by being early, which is (25/ 60) hours.
This gives us the expression t-25/60 for the time taken in Case 2.
i didn't understand the next step, how the 6(t-25/60) became 6t-25/10?
@@kapillund3629 same doubt here
2nd qs ans is wrong, i think 8000 is the answer...
In question 1 6t. Where did 6 go
complete this lecture on 27/9/24
Nice explanation mama
you have to use black board the white board is irritating us
Angular signal tutorial banao plz
can't u give reply to comment.for those who are having doubts
Your comment almost seems like a demand. It's her channel and her wish to do what she wants, don't watch if you have problems 😂
Questions 3 solution is wrong
I can't understand 1st question
question no 3 me aapne green line se underline to kiya but explain nahi kiya
kya explain karna hai usme--->
jis time mai wo 3km/hr chala us time mai wo ab 4km/hr chalega or jis time mai wo 4km/hr chala ab us time mai 3km/hr chalega easy
thank you
You're welcome
Or bche ka bhi to reply do sirf thanks walo k reply dere ho...
Or explain kro na ache se kuch smj nhi aara kudh hi dikhe jare ho bs.
Mam handwriting samaj nahi aa rahi
Itne time mai to 10 questions banane hote hai ,
my answer is 2.91
2nd question toh bas 40k/5 hi rahega yaar
Mam practice wala 3 qn ka dist=0 Aa Raha hai he mam
How can I report 'learn Advance ChatGPT ad'? I am getting really annoyed bcz of that.
😂
Where is logic
I would not suggest anyone to start their placements preparation from this channel... literally there is no explanation...no calculations
hello bhai placement bhi ho teri or tuje calculation bhi nahi karni hai
@@next_level-2. Bhaii I don't have any placement drive... And moreover I don't want to...
Just giving my opinion...
Tujhe samajh raha hai toh bhot achi baat hai
Mind your own preparation bastard💀
Or baaki comments bhi read kar liya kar... 90% audience ko nahi samjha hai
Can't understand
she cannot teach you step by step...you are at this point where you have to do these calculations on your own...if you are not able to do this also then don't do it...
Why are you rushing with the video?
Why not
you didn't understand the 3rd question either and you really dont know how to teach :(
. A student walks from hi shouse at 2.5 km/hr and reaches his school late by 6 minutes. Next day he increases his speed by 1 km/hr and reaches 6 minutes before school time. How far is the school from his house? I have doubt in this question.
Yes
That answer is false instead of 6*25/60 mam used 25/60 only
@@bijinbinu5994 No! It is correct.
For the first question time will be 2 hours. And not 2.5 hours.
Shi baat ha choriyo m dimag nh h
Mam please close the channel ....🙏🏽🙏🏽🙏🏽
ghanta nahi samjha aarah hai kya bol raha hai
What the logic you are using mam at least tell us🤦
ek kam karo na khud he padhlo hamko padhne ke kya zarurat hai zabardasti video bana ke......
worse course I had ever seen
Very bad way of teaching
Isko padhana nhi aata....sacchi.....kuch samjha nhi rahi....bass esa hoga vesa hoga 😢😢....bakwas hai....band krdo channel
jao pehle basic calc. sikhkr aao
Madame, do you've any contact number to ask any problem please.