Tricks for Constraint Motion || Laws Of Motion 07 for IIT JEE MAINS / JEE ADVANCE / NEET
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- Опубликовано: 3 окт 2024
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6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021)
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****Test Series for XI & XII****
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sure sir
Last question : 80 N
Sir modern physics chapter per video upload kare please
@@riyamehra23 kya tum explain kar sakte ho kaise hua 80N please😇
Nahi 200N answer hai
I was scared of all these type of questions...i am so glad i came across this video! Thank you!❤
❤❤❤❤❤❤❤❤❤❤❤❤
Tru yaad
Same :)
yeah man
@@arnavsinha834 11th me gaye ho
Behind every Sol of a tough ques there is a physics wallah who is making it a halwa ques
Shi kaha bhai
Sahi hai
Ekdum sahi bhaai
I like it👌👌👌
Sahi pakde hi...😂
For last question
N cos53=ma(acceleration of wedge horizontally )
Since acceleration of wedge=12, mass of wedge=10,and cos 53=3/5
=> N3/5=10*12
=> N=120*5/3
=> N=200
Correct
👍
Its wrong corrrct ans is 120 N
@@insiderswithpraveen6918 How?
@@devtripathi7317 😁😁
The answer of last question is 200N
Solution: As the wedge moves in the shown direction with 12m/s2, the only force acting in that direction is Ncos53. So, NCos53=mass*acceleration
=> N *3/5=10*12
=> N = 200N
Thanks U SIR.
Thank you so much
It should be cos37 right?
@@shivareddy108
No
N= 3/5*120= 72 newtons
wait that was the normal reaction you found. there's no need to use Ncos53
f = ma
=> f = 10 kg x 12m/s
=> f = 120N
There are many teachers who are expert but they dont know how to connect to a students mind...Anddd hereee comes you... Sir how nicely you explain such complex concepts very clearly and simply... You can feel a students mind.. 💙💙 Sir you are blessed from millions everyday.. And we are truely lucky that we all got privilege to learn from you...
Sir simplicity level infinity... 💯💯💯
can you pls tell me that how we will come to know that in which direction the tension is acting???
@@somya8839 You can check sir's first video on NLM. There he clears the concept of tension and its direction
@@sayansarkar9803 yes i check for it...now my doubt is clear ..thx
@@somya8839 welcome
@@somya8839 opposite to the point of contact between mass and string
Till date of 44 years of AGE ,THIS ONE IS MOST EASY WAY OF LEARNING , STUDENTS GRAB IT YAAR.
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SHANTARAM CHAVAN , KALYAN.
GOD BLESS U.
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Must be a teacher?
@@alwinjoseph4682 DEATH NOTE FAN!!!!!!!!
@@hemalatha8351 lololol
@@hemalatha8351 army as well lmao I saw your comment
Force of alakh sir's video subtratcts tension of students which is equal to awesome results ✨✨🤞🏻🤞🏻
💙
F=St-T=Ar
true
🙂
Nice one!
13:50 yahi to mera aim hai..God bless you sir..We all with you no matter what's situation...
Sir ,you became an inspiration for all the students. We are glad enough to have a teacher like you, thankyou sir for your sacrifice. We are with you ❤❤❤❤ .
Force by wedge on rod is the NORMAL REACTION on it ,
Mass of wedge = 10kg
Accleration = 12m/s^2
F=120N
Also Ncos53 provides accleration 12m/s^2
So the F must be equal to Ncos53
N×3/5 = 120
N = 200N
Same answer here🙂
Yep it's 200N
Correct 👍👍
Ncos53= ma(a=acceleration of wedge =12)
N=ma/cos53
By solving
N=200N
Thanks a lot😄
Last ans will be 200N...the block is moving due to component of Normal (N)along horizontal...so
Fnet=ma
Ncos53=10*12
N=(120*5)/3=200N
Note:
Normal due to block =normal due to inclined plane(Newton's 3rd law)..so N in both the cases will be 200N...and that is the force which is causing the inclined block to move
Thnx bro. I was not getting it
@@shivapandey7018 you're welcome
Mera bhi 200 N aya
👍🏼😁
But vertical equillibrium ki wajah se
Ncos37=mg
N=125 AARA H
In case anyone wanted to check out the song in the beginning...
It's called "Present Moment --- Eldar Kedem."
thnq...i was actually looking for it😅😅
thanks bro
Thanks.....I really wanted to know.
Well in this case you don't know it's 'You and me' from same singer
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Abhishek yadav can i ask from where u r
@@anjali8254 i am from varanasi
Me too
@@AbhishekYadav-zj2jm is it chakiyan in varanasi
Last question answer is 200N✌🏻,
Process: Ncos53 = Mass of wedge x acc of wedge
N= 120 /cos 53 =120 x 5/3 = 200N
Many many thanks bhai🙂
Yes for me also the same..
Sorry brother but you are wrong ans is 80 N
Bcs N=Mgcos37⁰
N = 10*10*4/5
N=80N
Same bruh
Sahi hai bhai 200 aayega
I am taking coaching for jee in the institution but the teaching of alakh sir is so good as compared to our institution teachers. The way of solving the questions is so awesome and this is so helpful for us
Sahi kaha
You talk right
When I started to seee ur lectures I love to develop good theroy
Sir you made such a difficult topic a "HALWA TOPIC"
Thankyou Sir
#PhysicsWallahIsGreat
can you pls tell me that how will come to know that in which direction the tension is acting???
@@somya8839 as tension is a pull force it will act always in opposite direction to any mass
@@uttkarshranjan8321 Ohh thx
opposite to the points
(Here,point : mass,pulley,m.pulley e.t.c)
What was ur rank and percentile bhaiya
Sir answer of last question
According to newton's law
F = ma
N cos 53 = 10 a
N cos 53 = 10 × 12
N × 3/5 = 10 ×12
N = 5 × 10 × 4
N = 200 newtons😊😊
Sir many new teachers are there on RUclips but you make the studies like fun to us
I am your great devotee and student 😍😍
Thank you Alakh sir ☺☺
Thanks bhai mera bhi vahi answer aya or me sabka comments dekh rah tha ki kishine apna ans dekha to mila hi nathi sirf apka hi mila thank you....
@@yogipatel8531 it's OK bro keep studying...👍👍
overall force will be 120 ....normal reaction will be 200
@@ig_kunala ya i wrote the same thing N=200..
@@ig_kunalahow 120 N
I love the you explain the concepts. Everything becomes clear more than crystal. You are the best physics teacher I have ever seen in my life.
"I love the you explain the concepts" I think you meant "I love that you explain the concepts"
Sir ,great trick, even my coaching teacher don't know ......
Thank you very much.
Hn
Coaching badlo bhai
Ego hurt hogayi😅
And Don't worry I know how to manage my studies ..thq😌
😂
Vese common sense ab kya hi coaching badlenge..
Sir , the answer of H.W question is 200 N . This is the force that applied on the wedge by the rod .
CAN YOU PLZ EXPLAIN HOW
@@aryanshah1698 bhai sun
Acc to hamara 12 N Aara hai
Aur mass of wedge 10 hai
To net force = 120 N
Aur N sin 37 bhi vahi hai so
@@aryanshah1698 equate karke dekho 200 N as jayega
I also got the same
Ans 80 N
Ques halwa ho gya.......👏😛😂😂best dialogue by alakh sir.....
Last question answer:-
Force on block by wedge = Ncos37°
=> 80N
The sound effects are amazing it really refreshes mind😁 and make the study more fun 💚
Sir plzz redox reactions
We are not forcing but please sir
Vote if anyone else wants
Yes, sir please take next chapter as redox reactions......
U known redox hamre school me phele hi ho gya h 2 months phele
Yes sir plz start redox reactions
@@ayushjain8781 organic
@@mymanindia bro organic bhut bada hai usse pahle agar redox ho jAega to maja ayega varna organic hi chalta rahega bhut din aur hamare school me reaa raha hai so plzz
Sir, you are really one in 'A LAKH', You are just GREAT!
Homework Answer - 200N Force is applied on Rod by the Wedge.
Thank You so much Sir for teaching in such an Amazing Way.
Lots Of Respect & Love to you Sir.
Please elaborate
I got 80 newton
@@paridhibhardwajyes it should be 80N
*Starting song*
Song name - Present moment
Singer - Elder kedem
tnq 😐
Wah sir what a explanation of all these concepts...... Really u r a great teacher
Answer is 200N
In order to find the force make components of normal reaction of rod on wedge then take horizontal component ( because it is responsible for acceleration in forward direction ) now make equation N.sin37°= (mass of wedge ) × ( acceleration )
Put values and you'll have the value of N.
Tysm for your valuable reply
Best way of explanation of ans
Thank you
Thq for explaination in better way
But he asked force on rod by wedge right
No,it's wrong we have to find force on rod by wedge ,so we will have to make N by wedge on rod
N=mgcos¢
N=80newton
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Questions dekhne mein jitne bhayankar hai, solutions utne hi easy hai....
All credit goes to our all time favorite Alakh Sir.....
Thanks a Lot sir....
That's why work done in mind set of TENSION is always zero
You are best teacher in the world
Thnk sir
ham to ye diagram dekh kar hi dar jaate the but now we are confident enough to solve these questions...... all thanks to ALAKH SIR
Sir me 10 class me NTSE ke liye preparation kr raha hoon sachi sab kuch samajh aata he or aapse to JEE and NEET wale बच्चे padhte he unko to sabh 100 % samajh aata hoga fir bhi pta nhi baar baar aap ye kui poochte ho ki samajh aa raha he ?? Salut you sir...
lyrics of the song which was played at the beginning:
"i got time,
its clear to see
from up here
the world seems small" it was so relaxing 👌👌😊
Award do koi bhai ko
Yes ,u r true
Gane likh le video kyu dekhta hai
1.Two best teacher alakh sir and 2. ruclips.net/video/Wjuo1eG19oo/видео.html .. ONLYJEE ASPIRANT MUST WATCH
It's not from up here .....it's from a pin😂😂it's from a pin the world seems small....but although great song!!
Who is going to attempt jee in 2026??
Me
attempt? the word should be cracking
@@Kaijinstepanncracking?the word should be rocking and killing it
Me 🔥
Yes
Last Homework Question Ans-
Ncos53= 10×12
= N× 3/5=10×12
So, N= 200N
👍
thnks
Can't we use acc component instead
Controversy is in your personal space ..as a teacher you are always my role model what you did may be wrong ...but it doesn't mean you can't be you are human and everybody makes mistake ...your motive is not wrong , what you did is for a good reason...those 42 lakhs Students of your ..who see you as teacher will be still be there for you..don't worry sir, you are here for a reason and that reason will be fulfilled great people don't get into controversies but they are included and that's totally fine..! We still love you sir ❤️
I want you to sleep with complete satisfaction today , becoz you are able to make change in life's of millions of student
. You are gem with complete genuinty
When i started to see ur videos then i started to love physics
ok
sir joh topics rhe gaye jee ke liye ab tak ke chapters me vo please january me pure kara do ge sir please please like if any one wants this
The final question given by Alakh sir was nothing but an IRODOV question. That's why Alakh sir was smiling
Answer bhi dedo
@@phijiks200N
@@rudrakshrai.11 hi can you please share the question no. So I can search solution from the internet or best if you know the link to solution can you please provide
@@phijiks actually it is not the same which alakh sir gave, it is very similar to it. Irodov Q.77
how bro can u pls explain@@rudrakshrai.11
😢i hope i have seen these videos before ever.... So clear,, ❤ i hope PW would never delete these old vedios or end to free vedios access🥰
I was having zero interest in physics but now i love physics just bcz of u sir .thxx a lot
I was having -100 interest in 11th physics now I have 0 interest slowly it will go to +100 interest
Answer-200 Newton
F cost 53 degree is equal to mass and acceleration
3/5=10×12 =120×5/3 =200 N
How is force Fcos 53°
@IITBOMBAY_CSE2024 okyy
Massive respect to you sir.. because of you we are aceing every difficult concepts with less efforts..
Thank you sir🙏🙏
Force on rod by wedge =72N. Because Normal force will be perpendicular to rod. So we have to take component of acceleration of the wedge in that direction (12cos53) and multiply it with mass. 12*3/5* 10 = 72N.
We are proud of you, sir. U made me understand everything, cleared every concept, thank you sir. Can't ever thank u enough.❤️
your interaction is like friends and ur explanation is like movie which cannot be forget . sir , ur are best physics teacher
Who else is watching Alakh sir' s old videos for revision leaving pace batch classes?
Arjuna2.0 or Raftaar ke Baad bhi kuch samajh nahi aaaya..or ab crystal clear ...mannn gye guru ..
Alakh sir you don't know how much you are helping me and my type of students thankyou so much I promise you sir after achieving something in my life will definitely come to you for giving my thanks
mee too
@@iconic-clicks then we will go together 😅😅😅😅
@@karishmasah2580 yaa sure..
Whenever we have a movable pulley use the concept.
Work done by torque is zero
Therefore summation of
T•x=0 diff wrt time
25:54
T•v=0
T•a=0
Points to be noted in the above expression it is dot product 17:06.
Be careful about the sign of van x
10:23
25:55 This one can be done using application of derivatives as well
ok
How ? Can you show ?
Ans to the hw question..
Ncos 53 = 10 × 12
N= 200N
I loved that intro! It was comforting and felt like it implied 'no worries....you're gonna solve them' coz i got freaked out seeing the thumbnail of this video. Hats off to u sir,....you knowingly or unknowingly provide us what exactly we need. ♥
Who is watching in 2024 ??
Attendance here>>>>>>>>
Ans of last ques is 200 N
I got 80N ... Can you please tell me how did you?
@@closednotebook thanks bro 🙏
Pseudoforce 120N......
80N normal rexn
Kindly see this motivational video examination in life never give up-ruclips.net/video/k4w4pak66V0/видео.html
@@tanishabijwe1502 normal reaction on wegde component form N cos 53=120
Love you & Thank you always Alakh Sir ❤
The answer to the last question ... 200N
For wedge ...
a=12m/s2
Force(F) in the direction of acceleration=Ncos53
mass=10kg
F=ma
Ncos53=10x12
Nx3=5x10x12
N=200N ...... Force on rod exerted by the wedge ...
Correct me if I am wrong ...
@@nightbot487 Kaise.... Please explain ... 🧐
@@edugyangurukul7357 ha Bhai mere se glti ho gyi thi 200N ki hoga
@@nightbot487 Aacha Aacha ... Thik hai 😁
well explained sir and I wish that you become our compass in the journey of JEE/NEET till the end so that even storm strikes we would capable to handle our boat
Kya baat hai 🖋🖋
Wahhh 📖📖
Mashalla 🔭🔭
Superb 🔰🔰
Great 👋👋
Owsom💁💁
Mujhe in question se bohut dar lagta tha aur feel bhi nahi hota tha agar sir padha bhi de toh but jabse alakh sir ye lecture dekha hu toh pura feel aa gyi
Is 200 N the answer for the last question bcuz in wedge the component of N in diretion of a should be equal to 120N , therefore Ncos 53=120 , ==>N=200N
Bhai T kaise kat ja rha hai
👍 correct answer
No bro....N=500/3
@@tanishprabhavat7212 he is right, how the hell did u get 500/3 XD
Tanish it's totally wrong answer is 200N only
Best teacher of my life
when i start watching his videos..i just can't stop watching .. you're very great sir😇😇
Ok
These lectures are 5 yrs old may donot correspond to the jee advanced syllabus of 2024 still these are the most amazing thing on whole RUclips ▶️ thank you Alakh sir
Thanks Alakh Pandey Sir ❤. You have given beautiful concepts. Thanks a lot ❤.
Jee 2025 anyone ..?
I hope anyone will reply nd like 😊
Yes
Which coaching are you enrolled in?
@@7clouds567fiitjee and you??
Yes
@@7clouds567Allen
A very good morning sir , i m Rajveer Mandloi from Ahmedabad. I saw all of ur videos nd absolutely loved them all ur way of teaching is fabulous. I understood everything that u taught us through ur videos nd i was able to solve all the questions which u did in ur videos , but sir when i tried to solve ncert i wasnt able to solve it!! Like i cant relater with that nd i m not able to crack those questions.
Can u please me out with this!?!?
It would be a grt help sir if u could help me out with this with ur suggestion!!
Plsssss do reply sir!!
I hope u’ll help me in this!
Regards
Rajveer
Don't see sirs videos directly without knowing anything about the chapter.. Though sir teaches in a awesome way still u need to first know what u r going to learn rather than getting fully dependent on sir. So first have a quick overlook over the material that u r following, read it try to understand it of Ur own first . That will help u in getting Ur concepts clear and will help u to solve ncert questions which r mostly conceptual ones.If u don't know which book is a good book then take alakh sirs Pdf notes ,read them and then see the lectures . Probably this technique will be more effective. It's because I too faced the same problem that u r facing and I did the same and this technique helped me to improve
নূরুল
Hit like who want sir upload tricks in physics for neet and jee
Me
Mee
yes sir please upload
23:00 as block a moves forward block b moves upward in y drctn
No one can match the understanding level of alakh sir old lectures.🎉❤
Is this for neet also?
@@premranjan-vb2sr of course
I don't saw the previous video of this topic but I understand how to solve this types of questions because of this LEGENDARY teacher
Thank you so much sir your videos helps us a lot ❤❤
Love from Nagpur
Sir thank you for this awesome methods and tricks. previously I was afraid of the complex pulley problems but I now I'm easily solving them. 🔥
35:32 Sir : Kr paye the ye question khud se
Me : sir 2❌ ki speed me pause krne ka muaka nhi mila toh chap liya
sir: boht bdiya
Everyone watch in X2 😂😂
😂
N.cos37=mg
N.4/5=10*10
N=100*5/4
N=25*5
N=125N(ANS)
its 120 due to conservation of momentum
200 N ?
mgcos37°=N
10×10×4/5=N
100×4/5=N
4×20=N
80N=Normal Reaction
I used to watch sir's vedios..in 22 Now I am in IIT Rorkee..thank you so much sir😊😊
do sir video also help in advance
@@poojatyagi727no
For the first time, I solved maximum of answers correct.
Thank you alakh sir.🙏🙏🙏🙏🙏🙏🙏😢😢
If you can't solve Pulley problem
Please visit my chennal
29:19 I solved that in 2 seconds using a different method. If we consider the acceleration a1 to be the perpendicular, and the 3 root 3 acceleratioin to be the base, we can say
tan 30 = a1/3root3 or a1 equals 3 m/s2
Yaa
Yeah...Is this method is correct ?? For all these types of questions 🤔🤔🤔 reply me shaurya vardhan bro
@@daisyrose8392 @Daisy rose because the block 2 is moving as well as block 1 is moving..... Therfore the lengh we take in tan will change and our ans will be wrong
Hope u understand
Regards..
Atharva Saoji
Physics teacher
Kota..
Thank you so much . This made the chapter so much easier to do
5 years later...
still very useful
Actually I am south Indian, I don't know Hindi, but his lecture made me to understand this concept very clearly. His way of teaching is really appreciable.
Same here
Naanumdhan
Same
Naanumdhaan
Aao ma
This video is really very helpful for me thank you very much sir, ❤️ From Arjuna 2024
im dropper in prayas batch
but still here 😅😅😅😅
You are the bestest teacher ever Sir 🙏🙏🙏🙏❤️❤️❤️
Amazing sir . Ekdm achhe se smjh aa gaya😊😊. Thank you sir.😊😊😊
First to see it. Sir you are the beat. Sir I have improved in physics and chemistry after watching your videos
Best*
sagnik to vahi sagnik ghatak he ne jisne surat adajan branch se aakash me admission liye tha . ignore if not .sorry
@@souravyadav3534 bhai , tum maths nhi jaante kya ?
hw ans 200 newton
3:30
8:15
10:04
12:15
14:30
17:00
21:20
23:50
25:50
28:18(important)
33:15(important)
36:20
Love you so much sir ......
Sir ....ye video dekhne ke bad
Sabhi questions ban the hai
Thanks so much sir..
🤗🤗🤗🙏🙏🙏🙏
80N is the answer of the last question given by Sir.
The direction of N is along the x axis for the inclined plane(wedge) and that component is mgcos theta so, N = F = mgcos theta = 10×10×4/5= 80N.
I am in 10th right now. I am preparing with the help of his videos!! Great explanation Sir. Fan ho gya mai to!!!!!
Mera bhi same aya hai.. Best of luck....
@@debasritaprusty6470 Tum kis class mein ho??? All the best to you too!!
Hw ques Ans is 152 N
100cos37 + 10×12cos53
Gravitational force mg is also acting whose cos component will be taken.
Am I correctm?
Little bit doubtfull since others are saying 200N
Sis. ans 200 N hoga
In the diagram from
Ncos53⁰=m.a2
By the way I am also not actually sure that it is the right ans .
@@vivekpatel7452 ohh no problem still thankyou very much 😄 I'm glad at least you tried the ques😊
Okay so, if we go by the basics, normal force is the constraint here, the wedge starts to accelerate with 12m/s² due to the normal force. When the wedge was at rest, it still had mg acting vertically downwards, but it didn't produce any acceleration in the horizontal direction, therefore we don't have to consider gravitational force component along N.
Secondly, again N is the force causing acceleration, 12m/s² is the component of N acting along the x axis, therefore the component of N along x will be equal to 12•m, in your soln, you're taking the component of 12 along the direction of N which is incorrect.
Having that explained,
Ncos53°= 12•10
N= 12•10•5\3
N= 200N
Hope this helps :)
@@ayyajay thankyou very much this cleared a lot😃
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Aapne to Mera physics phobia khatam hi kr Diya
Thanks a ton sir....
May u be blessed with all that your heart desires 😊😊😊
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