Calculating the intercept and position line - Moon celestial body

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  • Опубликовано: 31 янв 2025

Комментарии • 10

  • @kvthustler3715
    @kvthustler3715 5 лет назад +1

    Thank you very much Sir !
    Had my navigation final exams yesterday and whole of the semester I've been trying to find a way to understand and solve intercept and position line questions until I watched this video a night before my final exams... and I did it 🙂 Now I know where to look for a better understanding in Navigation ... Again Thank You very much Sir !

    • @SteeringMariners
      @SteeringMariners  5 лет назад +1

      I am so happy that the videos helped you. well done on your exams. Thank you for your kind feedback:)

  • @nandintini3240
    @nandintini3240 4 года назад +1

    Thank you

  • @muskanheera2126
    @muskanheera2126 2 года назад

    Hello sir.
    What if Ht. Of eye is 30m ?
    What will be the correction?
    Zero itself or what to do? Please please please respond. It's urgent.

  • @sarathsankar1077
    @sarathsankar1077 3 года назад

    17:10 if the lat is 00'0.0' there is no name N/S then how will we put +/- in the equation

    • @AakibKhan-ns6bh
      @AakibKhan-ns6bh Год назад +1

      gentleman you write the formula first. the side beyond +/- has sin lat which will make it zero so no problem if you use +/- sign in finding CZX

  • @joshuaintila2638
    @joshuaintila2638 3 года назад

    Where came from is the HP 55.6? Thanks

  • @saifullaaleem5006
    @saifullaaleem5006 2 года назад

    Is v correction is always additive?

  • @ashwanikhalon6450
    @ashwanikhalon6450 5 лет назад

    My 2001 almanac doesn’t have the moons altitude correction table :(

  • @sarathsankar1077
    @sarathsankar1077 3 года назад

    Intercept moon exercise - 26 question no 1