Thank you sir ...one single video it cleared my several doubts 👍..and i was solving the same question luckily soo got to match everything very nicely ,thank you
Sir, the value of P that you have used is that of LHA. But i think it should be 360- LHA because the the value of LHA is more than 180 . Please correct me if I am wrong.
Big fan of your videos topics are very amazingly explained. But I have a doubt with the value of P. As LHA is greater than 180 degrees the value of P should be 360-LHA. If the value of LHA is less then 180 then LHA=P. Please confirm.
Please sir answer my question..... During extracting value of A.. you used given lat, i mean which is given in question but during extracting AZIMUTH you used obs lat value...those who didn't do it practically they can't identify it and also it is not instructed inside your lecture.. Can you please make it more clear????
WHY ARE YOU CONFUSING PEOPLE ? PLEASE CONFIRM REGARDING P AND LHA DOUBTS , HOW CAN YOU JUST REPLACE P WITH LHA EVERYWHERE AND MANY PEOPLE HAVE COMMENTED REGARDING THAT PLEASE TELL THE CORRECT WAY
20:27 hello Sir, please can you clarify why DR Lat is used when obtaining value of “A”, but obs. Lat is used when getting azimuth at the end?
Great explanation sir now my doubts are very much cleared after watching your videos sir thumbs up
Thank You so much Faisal. Greatly appreciated:)
Thank you sir ...one single video it cleared my several doubts 👍..and i was solving the same question luckily soo got to match everything very nicely ,thank you
You are most welcome 😊
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Sir, the value of P that you have used is that of LHA. But i think it should be 360- LHA because the the value of LHA is more than 180 . Please correct me if I am wrong.
both will give same answer
How ?@@thecommonist8750
Thank You Sir Perfect Example Of Ex Meridian Too Many Doubt Cleared Sir In This Video 🎥
💙❤💜🙏
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@@discountcuppon Okay Bro 💓
@@Creative_Punjabi93 thanks
Please can you do the videos ex Meridian why it is done when it is taken and what are the limits of it? The explanation will be very helpful.
I have a few videos on ex-meridian calculations. Please check my playlist on celestial navigation:)
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Sir thanks for making such videos but I have a dought when calculating ex meridian sun is not visible to us so how we will obtain altitude of sun?
Sun is still visible, only that the time of meridian passage has passed.
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Can you please also describe about finding the limits of the meridian???
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Sir can you please also share a lacture of latitude by meridian altitude stars
Will you plz make any video on staggered observation
Big fan of your videos topics are very amazingly explained. But I have a doubt with the value of P. As LHA is greater than 180 degrees the value of P should be 360-LHA. If the value of LHA is less then 180 then LHA=P. Please confirm.
Hello friend
For preparation of second mate / DNS/ BSC nautical science/NCV come in #kundanpatna
Sir please make some videos on circumpolar bodies.
Coming soon:)
Jai hind
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Sir, i had doubt that can we use the Observed Latitude for the calculation of " A " or is it necessary to use the DR latitude ?
You can't use observed latitude as you have to calculate it, you have to use DR latitude.
@@SteeringMariners Thank you Sir! 🙏
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@@SteeringMariners sir can u pls show us how to get 12.35 on Tan Lat/Tan P
@@navaskhan8600 he used DR Lat for that calculation. if we use observed lat we will get 12.42. answer at the end would be almost similar
Bro.. waiting for ex.mer. star and planet video's
Which latitude is used to find value of A & Azimuth?
and what is the need of Direction of LHA as the question itself says near the meridian it will always named east.. correct me if wrong
Please sir answer my question.....
During extracting value of A.. you used given lat, i mean which is given in question but during extracting AZIMUTH you used obs lat value...those who didn't do it practically they can't identify it and also it is not instructed inside your lecture.. Can you please make it more clear????
sir,the value of P. As LHA is greater than 180 degrees the value of P should be 360-LHA. If the value of LHA is less then 180 then LHA=P
Sir.
I have a doubt about LHA
For P
If our LHA is 0°-180° (P=LHA)
If our LHA is 180°-360° (P=360°-LHA)
Is this correct sir.
Value of LHA greater than 180 degree then how your LHA will be Equal to P. it will be 360*-LHA sir.
kindly do the correction
In ex meridian i will write obs lat and thqn i will apply pl
While on ship takin morning and noon sight how can we transfer the posn line nad run to get posn
WHY ARE YOU CONFUSING PEOPLE ? PLEASE CONFIRM REGARDING P AND LHA DOUBTS , HOW CAN YOU JUST REPLACE P WITH LHA EVERYWHERE AND MANY PEOPLE HAVE COMMENTED REGARDING THAT PLEASE TELL THE CORRECT WAY
👍