Hi my friend,thanks alot for solving the problem,you know what that strange minus appeared in you final equation???simply cause you assume the potential energy to be zero at the connecting point of the spring that way constant l gets a minus value cause it's measured from some where higher than the mass 😊😉
I believe you need to replace the cos(theta) with (1-cos(theta)) . otherwise you are treating the height as the distance between the pivot point and the vertical displacement of the bob. this also explains the unexpected minus sign as it will give the same motion, only opposite
This is excellent , no one explained the reason for the potential equation having a different length from a simple pendulum
is the spring pendulum is same as the pendulum suspended by a rubber band...plz responce
Hi my friend,thanks alot for solving the problem,you know what that strange minus appeared in you final equation???simply cause you assume the potential energy to be zero at the connecting point of the spring that way constant l gets a minus value cause it's measured from some where higher than the mass 😊😉
At 15:30, u move -(l+X)mgsin theta but u kept the -ive
I believe you need to replace the cos(theta) with (1-cos(theta)) . otherwise you are treating the height as the distance between the pivot point and the vertical displacement of the bob. this also explains the unexpected minus sign as it will give the same motion, only opposite
His reference is set at the pivot so cos(theta) is right.
Too slow
You need to be intellectually honest about your result. Start over so that the result come out clean, without the nagging minutes sign.