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Kinda Sorta ASMR Physics
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Griffiths Electrodynamics Problem 5.24: Current Distribution from Vector Potential
Problem from Introduction to Electrodynamics, 4th edition, by David J. Griffiths, Pearson Education, Inc.
Просмотров: 9 620
Видео
Fiber Optic Steampunk Squid Lamp
Просмотров 9867 лет назад
I have an Instructable that describes some of the building process. www.instructables.com/id/Fiber-Optic-Steampunk-Squid-Lamp/
Spherical Capacitor Two Halves with Different Dielectrics
Просмотров 21 тыс.8 лет назад
A spherical capacitor of two concentric conducting shells is divided into two halves, in which the space between the shells is filled with a dielectric of a specific dielectric constant. Calculate the electric and displacement fields in each half, as well as the capacitance of the entire capacitor.
Lagrangian of Two Particles with Central Force
Просмотров 11 тыс.8 лет назад
A) Find the Lagrangian of two particles whose potential depends only on the separation between them. B) Transform to the Center of Mass coordinate and the relative coordinate of the two particles, and show how the reduced mass enters the equations of motion. C) Find the equations of motion.
Ideal Gas Law from Quantum Arguments
Просмотров 5 тыс.8 лет назад
Derive the Ideal Gas Law (PV=NkT) from quantum mechanical arguments.
Ideal Gas Law from Classical Arguments
Просмотров 1,5 тыс.8 лет назад
Derive the Ideal Gas Law (PV=NkT) from classical arguments.
Magnetic Field In Wire With Hole
Просмотров 24 тыс.8 лет назад
A) Calculate the magnetic field within a wire carrying a current I uniformly distributed throughout the wire. B) A circular hole is now drilled through the wire, offset from the wire's center. Calculate the magnetic field inside the hole.
Atwood Machine Lagrangian and EoM
Просмотров 1,5 тыс.8 лет назад
Find the Lagrangian and equation of motion for two masses connected by a string over a pully. The pully has mass and can be modelled as a hoop.
Average Length of Two-State Chain
Просмотров 3218 лет назад
A mass is suspended by a chain whose links are ellipsoidal and can be oriented either vertically or horizontally. Find the average length of the chain.
Why Heating a Room Doesn't Change the Total Energy of the Air in the Room
Просмотров 2458 лет назад
Why Heating a Room Doesn't Change the Total Energy of the Air in the Room
Infinite Resistor Ladder
Просмотров 4,4 тыс.8 лет назад
Find the resistance of an infinite resistor ladder.
Griffiths Electrodynamics Problem 1.3: Angle Between Body Diagonals of Cube
Просмотров 12 тыс.8 лет назад
Problem from Introduction to Electrodynamics, 4th edition, by David J. Griffiths, Pearson Education, Inc.
Griffiths Electrodynamics Problem 1.2: Is Cross Product Associative?
Просмотров 36 тыс.8 лет назад
Problem from Introduction to Electrodynamics, 4th edition, by David J. Griffiths, Pearson Education, Inc.
Griffiths Electrodynamics Problem 1.4: Cross Product to Find Normal Vector
Просмотров 9 тыс.8 лет назад
Problem from Introduction to Electrodynamics, 4th edition, by David J. Griffiths, Pearson Education, Inc.
Griffiths Electrodynamics Problem 1.7: Separation Vector
Просмотров 4,6 тыс.8 лет назад
Problem from Introduction to Electrodynamics, 4th edition, by David J. Griffiths, Pearson Education, Inc.
Wave Equation From Maxwell's Equations
Просмотров 27 тыс.8 лет назад
Wave Equation From Maxwell's Equations
Griffiths Electrodynamics Problem 1.8: Rotation Matrices
Просмотров 7 тыс.8 лет назад
Griffiths Electrodynamics Problem 1.8: Rotation Matrices
Griffiths Electrodynamics Problem 1.11: Some Gradients
Просмотров 6 тыс.8 лет назад
Griffiths Electrodynamics Problem 1.11: Some Gradients
Griffiths Electrodynamics Problem 2.16: Electric Field of Long Coaxial Cable
Просмотров 13 тыс.8 лет назад
Griffiths Electrodynamics Problem 2.16: Electric Field of Long Coaxial Cable
Griffiths Electrodynamics Problem 2.17: Electric Field of Infinite Slab of Uniform Charge Density
Просмотров 9 тыс.8 лет назад
Griffiths Electrodynamics Problem 2.17: Electric Field of Infinite Slab of Uniform Charge Density
Griffiths Electrodynamics Problem 2.14: Electric Field Inside Solid Sphere Nonuniform Charge Density
Просмотров 13 тыс.8 лет назад
Griffiths Electrodynamics Problem 2.14: Electric Field Inside Solid Sphere Nonuniform Charge Density
Griffiths Electrodynamics Problem 2.12: Electric Field Inside Solid Sphere Uniform Charge Density
Просмотров 9 тыс.8 лет назад
Griffiths Electrodynamics Problem 2.12: Electric Field Inside Solid Sphere Uniform Charge Density
Projectile Hitting Spring Embedded in Mass on Frictionless Plane
Просмотров 1918 лет назад
Projectile Hitting Spring Embedded in Mass on Frictionless Plane
Griffiths Quantum Mechanics Problem 1.7: Time Derivative of Expectation Value of Momentum Ehrenfest'
Просмотров 15 тыс.8 лет назад
Griffiths Quantum Mechanics Problem 1.7: Time Derivative of Expectation Value of Momentum Ehrenfest'
Griffiths Quantum Mechanics Problem 2.14: Harmonic Oscillator with Quadrupled Spring Constant
Просмотров 2,9 тыс.8 лет назад
Griffiths Quantum Mechanics Problem 2.14: Harmonic Oscillator with Quadrupled Spring Constant
Griffiths Quantum Mechanics Problem 2.18: Trigonometric Functions and Complex Exponentials
Просмотров 1,3 тыс.8 лет назад
Griffiths Quantum Mechanics Problem 2.18: Trigonometric Functions and Complex Exponentials
Griffiths Electrodynamics Problem 2.1: Force From Symmetric Charge Arrangement
Просмотров 12 тыс.8 лет назад
Griffiths Electrodynamics Problem 2.1: Force From Symmetric Charge Arrangement
Griffiths Quantum Mechanics Problem 1.2: Standard Deviation of Probability Distribution
Просмотров 5 тыс.8 лет назад
Griffiths Quantum Mechanics Problem 1.2: Standard Deviation of Probability Distribution
Griffiths Quantum Mechanics Problem 1.16: Time Derivative of Inner Product
Просмотров 3,9 тыс.8 лет назад
Griffiths Quantum Mechanics Problem 1.16: Time Derivative of Inner Product
Thanks a lot!😁
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Respect from the other side of Earth...!
I could not believe that this video was 8 years ago, yet very clear in explaining.
Thank you, man!
i love you
really good explanation for a homework problem I am stuck on in my Undergrad 3rd year Classical Mechanics course
Weldon
looking at the comments u understand that its not only u who are struggling with phy😆😆😆
from where did the minus sign come from in 9:29
you are seriously saving me from failing this class
Hands down the best solution for this problem in yt.
I detested equations in school but when I watch the calculations in this setting, it's much easier to understand. Thank you sir.
thanks!!
Could you do this for U=U(T,V)
Is that partial derivative or normal derivative?
💌
Very helpful. Thank you!
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For those who are wondering about the voltage and why the signs change at the end: We know that the capacity can not be negative. The problem here is that we calculated the V(b)-V(a) which is negative. But at the end, we put V(a) -V(b) or the absolute value of the prevoius.
you just took the pain out of me, I was not knowing how to calculate the inside E,
Thanks for solution
absolutely amazing video! I feel so bad hearing you cough, please feel better \(ᵔ ᵕ ᵔ)/
This was amazingly helpful, thanks a million 🙏🏻💐✨
Thank you this was not confusing and well explained 👌
Thank you 🙏🏻
This is the only video example I can find on a problem like this and I can't hear
Thank you so much
Shouldn't the magnitude be divided by 2 because they make half a parallelogram?
This is why physicists are smarter than Mathematicians. However, this also shows why Mathematicians are smarter than Physicists.
I just wanted to say, I have a big dicc. I was able to solve this problem before watching the solution.
Pure physics 👌 👏
Just got this in my midterm, did not go well
Upload the video for Example 2.15
Sir your voice is not able to hear clearly
Really thank you!
I couldn't find legit solutions to this problem the text doesn't give info about the electric field inside the solid sphere. I was a lot confused with this problem and I tried to compare it with the spherical shell one which would only work for the inside of the sphere. I just felt really dumb for not being able to solve this. Thank you for the video, it's a bit long but it starts right where I want it from. Making mistakes is ok because it makes the viewers aware of not repeating the same errors.
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Sir, there is something I have not yet understood. Why is there only radial component of electric field?
magnetic field due to rd one is in negative z direction coz it cirls around each current wire. thus net magnetic field is toward negatie z. please correct me if m wrong
Thanks a lot!
hey thanks :)
This is the only thing I got correct from my homework xD.
i guess, we could also solved it by applying Conservation of angular momentum in the point of contact as there is no torque applied? btw nice video sir
get a better microphone. can barely hear you even with my volume up at 100%
why aren't you taking the cylinder in x direction????
great answers to all problems. wonderfully explained but what the hell is asmr physics!! you could be louder:) thanks
Nice work!
Top notch explanation! Thanks a lot. Specially helped me when you clarified that "z" and ¨r" are treated as constants here!