Hey, thanks for the videos. I have a homework problem that is similar to this one, was wondering if you could help me out with it. Here it is: An infinite slab of dielectric of finite thickness 2a has permittivity , and is charged uniformly with charge density ρ. While doing the problem, please, assume that the slab is in the x − y plane (z-axis being perp to it), and the origin is right in the middle of the slab. a) (10 points) Find the electric field inside and outside the slab b) (15 points) Determine the bound charges appearing in the slab.
"A rectangular slab of volume charge density 𝜌𝑣0 in 𝐶/𝑚3 is infinite in the y-z direction and bounded by 𝑥 < 𝑎, 𝑥 > −𝑎. Find the E-field vector in all space." This should follow the same procedure, just along the y-axis?
I believe this is because there are two areas of the Gaussian pillbox that we need-one in the positive y direction and one in the negative y direction. These areas are equal and can be represented by 2A.
very good explanation but you have to speak louder.
Hey, thanks for the videos. I have a homework problem that is similar to this one, was wondering if you could help me out with it. Here it is:
An infinite slab of dielectric of finite thickness 2a has permittivity , and is charged uniformly with
charge density ρ. While doing the problem, please, assume that the slab is in the x − y plane (z-axis
being perp to it), and the origin is right in the middle of the slab.
a) (10 points) Find the electric field inside and outside the slab
b) (15 points) Determine the bound charges appearing in the slab.
"A rectangular slab of volume charge density 𝜌𝑣0 in 𝐶/𝑚3
is infinite in the y-z direction and bounded by 𝑥 < 𝑎, 𝑥 > −𝑎. Find the E-field vector in all space." This should follow the same procedure, just along the y-axis?
Yhyh
What is E(2A)? A is area and E is the magnitude of e-field I suppose, but where does the 2 on the left side come from?
I believe this is because there are two areas of the Gaussian pillbox that we need-one in the positive y direction and one in the negative y direction. These areas are equal and can be represented by 2A.
What if I take y instead of 2y?
great answers to all problems. wonderfully explained but what the hell is asmr physics!! you could be louder:) thanks
Thank you, but is there someone sleeping next to you? we barely hear you
Volume!!😩
why aren't you taking the cylinder in x direction????
Next time Khana khakar aao
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