Thermodynamics - Test 1 Problem 1 - Multifluid manometer

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  • Опубликовано: 24 дек 2024

Комментарии • 80

  • @darrenquaye7197
    @darrenquaye7197 2 года назад +4

    This is hands-down the best video I have watched on manometer problems

  • @zaraakkuly1861
    @zaraakkuly1861 4 года назад +21

    Wow, thank you so much! You have no idea how much of a life saver you are. I couldn't figure out why you sometimes minus and other times add pgh until I came across your video. You saved me hours of grief.

  • @diskar-Tip3553
    @diskar-Tip3553 2 года назад

    Thank you your lesson are much easier to understand, your slow talking makes easily process the information

  • @MrAnon73
    @MrAnon73 Год назад +1

    Also thank you from NZ, I spent all day trying to get my head around this reading from a text book, fluid start to fluid end, end up=Pa(- )/end down=Pa(+) very helpful, I just could see it, can now thanks.

  • @jakobrassi9816
    @jakobrassi9816 4 года назад +5

    Hey thanks for this video, it is very consistent and affective. It's better than other videos. The last video I watched had 100k+ views or something but had a contradiction within it which made it confusing. I wish I came across this video first hopefully you got more views, I appreciate the content thank you.

  • @PonquecitoMortal
    @PonquecitoMortal 4 года назад +5

    Thank you!, I am so happy to find videos like this: completly clearly and don´t need to go around and around the problem to solve and to understand what to do. ^--^

  • @buragayedrians.7233
    @buragayedrians.7233 4 года назад +4

    Thank you for this well explained steps in solving pressure. You helped a lot. Keep it up, sir.

  • @H-cranky
    @H-cranky 2 года назад

    I have a test tomorrow and this is the exact question i have in my workbook but couldnt solve it. thank you man you came in clutch

  • @lifefan1
    @lifefan1 2 года назад +1

    Your students are lucky 😪. Thank you for the video!

  • @shashikantdas6983
    @shashikantdas6983 3 года назад +1

    Thanks sir. very nice concept, from back to first. I was doing always first to last. back to first is easy to understand in some problem

  • @syedmuhammadqasim1494
    @syedmuhammadqasim1494 4 года назад +3

    Thanks a lot for the clear and precise explanation!!!

  • @aqanni
    @aqanni 4 года назад +1

    Thank you you are already a legend ❤️. Keep it up.

  • @MutammimChowdhury
    @MutammimChowdhury 4 года назад +1

    Thank you, I finally understand this topic!!!

  • @manaralhamoud1941
    @manaralhamoud1941 9 месяцев назад

    Thank you so so so much you made this SUPER EASY

  • @Darwin-bg1pm
    @Darwin-bg1pm 4 года назад +2

    I just checked out your thermo google file and its pretty good. hopefully you put some more for thermo 2 (ch 9 and up). I also dont know how this problem is thermo, this is more like fluid mechanics problems xD but cool thanks!

    • @engineeringdeciphered
      @engineeringdeciphered  4 года назад

      darwin ! I don’t have any Thermo 2 videos :( I’ve never taught that class.

  • @kareliasilvestrini6671
    @kareliasilvestrini6671 4 года назад +7

    Loved this! I was having a major struggle with this guy!
    By any chance, could you share the unit’s conversion sheet?

  • @aniruthdinesh9156
    @aniruthdinesh9156 3 года назад +1

    Alas' the saviour shows up making the fog of the minus and plus lift up.

  • @roycechisala8444
    @roycechisala8444 3 года назад

    You're the best 👏🏾👏🏾

  • @frankcampos1251
    @frankcampos1251 Месяц назад

    Very good explanation. It all works out beautifully using SI units. However, it is not so clear (to me) when using English unit. How do you account for the density of water being 62.4 lbm/ ft3? The equation requires lbf/ ft3 in order to work. Can you please help understand what I am missing?

  • @tisamusonda8799
    @tisamusonda8799 Год назад

    Thank you so much.. nicely explained

  • @muhdafif8329
    @muhdafif8329 2 года назад

    Thanks bro helped me a lot

  • @Lovee_MRK
    @Lovee_MRK 3 года назад +2

    Sir for my problem, at the end of the question they stated that the local atmospheric pressure to be 95.5 kPa. They still asked to determine the gage pressure though. So is this value just meant to throw the students off or am I to consider P2 as 95.5 kPa?
    Edit: This was a past assignment and just stumbled upon it while reviewing. I do not know if I actually got it right as I considered P2 as 95.5 kPa.

    • @engineeringdeciphered
      @engineeringdeciphered  3 года назад +1

      You were right to begin with. You don’t need that value to calculate the gage pressure. You would need it to calculate the absolute pressure.

    • @Lovee_MRK
      @Lovee_MRK 3 года назад

      @@engineeringdeciphered Thank you sir

  • @tac-anchristiang.5305
    @tac-anchristiang.5305 Год назад

    good day, i just want to ask if can we have a copy of the pdf conversion file of yours? thank you

  • @sunmichoi6888
    @sunmichoi6888 3 года назад

    Thank you so much!

  • @HABF4
    @HABF4 4 года назад +1

    thank you so much

  • @kafee_Alqahtani
    @kafee_Alqahtani 4 года назад +1

    thank you so much

  • @ninyomangitamurti3408
    @ninyomangitamurti3408 3 года назад +1

    Thanks for the explanation but may i know from which book you got this question?

    • @engineeringdeciphered
      @engineeringdeciphered  3 года назад

      Don’t remember, but probably Cengel and Boles’ Thermodynamics textbook.

    • @ninyomangitamurti3408
      @ninyomangitamurti3408 3 года назад

      @@engineeringdeciphered Okay, thank you very much. Sorry but may i request a conversion factor file?

    • @engineeringdeciphered
      @engineeringdeciphered  3 года назад

      @@ninyomangitamurti3408 I’m having trouble copying and pasting from my phone. But it’s in a different comment on this video. Hopefully you can see it.

    • @ninyomangitamurti3408
      @ninyomangitamurti3408 3 года назад

      @@engineeringdeciphered I found it in the comments. Thank you very much

  • @calozanhielchristianssaliv4537
    @calozanhielchristianssaliv4537 4 года назад +1

    Thank you

  • @leeroymajoni3451
    @leeroymajoni3451 3 года назад

    Can you please explain why you didn't subtract P(atm) from each term as you did for P2.

  • @adlymuhd4590
    @adlymuhd4590 4 года назад +1

    thank you sir

  • @TopNotchVideosYT
    @TopNotchVideosYT 2 года назад

    thank you

  • @jonnym610
    @jonnym610 2 года назад

    You are a god

  • @iantheodorejesalva8170
    @iantheodorejesalva8170 3 года назад

    sir is it still correct if i got the same answer but it is negative? I started finding out the gage in point 1.

  • @fareskamalfares6076
    @fareskamalfares6076 2 года назад

    Omg you 😍 amazing 👏

  • @teyeon1852
    @teyeon1852 Месяц назад

    then what is the use of given Patm?

  • @kritiko1795
    @kritiko1795 4 года назад +1

    thanks bro!

  • @jim2395
    @jim2395 Год назад

    why is going up negative and going down positive? is there an explanation for this? great video btw!

  • @elmerarts9124
    @elmerarts9124 Год назад

    What book is this from sir?

  • @OmarKhaled-mg2ok
    @OmarKhaled-mg2ok 9 месяцев назад

    i have a question : to use or apply the rule that we all know that any point at the same horizontal plan has the same pressure ;; is the point has to be in the same material or liquid?? or it could be different???

  • @jeffersonumara2371
    @jeffersonumara2371 4 года назад +2

    just before the test i came up to this, lucky me

  • @diplomchee
    @diplomchee Год назад

    Thanks brother

  • @emti69
    @emti69 10 месяцев назад

    sir can you me the link of the conversion pdf

  • @megathadif6892
    @megathadif6892 3 года назад

    but in our version it gave us the atm pressure value. do we need to take into account?

    • @engineeringdeciphered
      @engineeringdeciphered  3 года назад +2

      Yes, if it is asking for the absolute pressure. You would have that value where I have the 0. But if it is asking for gage pressure, you wouldn’t use that, even if it is given.

  • @danzzz3869
    @danzzz3869 3 месяца назад

    Hi thanks for the tutorial. Can I have a copy of that conversion and derived units you have pleaseee. 😁

  • @Darwin-bg1pm
    @Darwin-bg1pm 4 года назад

    My problem specified that P2=Patm so Im good. but what if it didnt specify or didnt put gauge pressure instead, it says "determine air pressure" instead of gauge pressure, would P2 = Patm ?

    • @engineeringdeciphered
      @engineeringdeciphered  4 года назад

      Correct, if it is open, the pressure at that open area would be the atmospheric pressure.

  • @Shampoo2004
    @Shampoo2004 2 года назад

    I have the same exact equation in my lectures

  • @naeem6583
    @naeem6583 4 года назад

    Wouldnt the water be 'down' too?

    • @engineeringdeciphered
      @engineeringdeciphered  4 года назад +1

      No, I’m starting at P2 and the going to the left. If you were to start at P1 and go to the right then yes, water would be down.

    • @naeem6583
      @naeem6583 4 года назад

      @@engineeringdeciphered I rewatch the vid and now I understand. I thought that you're referring to the position of the oil column when you say it's up but actually it's the h and where it's headed

  • @Ghostahmad
    @Ghostahmad 2 года назад

    Isn't P(gage) =P(abs) - P(atm)?
    Why p(atm)=0

  • @ahmedroshdy7270
    @ahmedroshdy7270 Год назад

    bro i need this conversion sheet so bad pls give it to me + why gage = zero

  • @kylecatman7738
    @kylecatman7738 3 месяца назад

    It's opened to the ATM, you can't discount it in this case.

    • @engineeringdeciphered
      @engineeringdeciphered  3 месяца назад

      If we were calculating absolute pressure, you would be correct. But in this problem we are calculating gage pressure, so the atmospheric pressure is zero (gage).

  • @omarjallad2001
    @omarjallad2001 3 года назад +1

    This is not Thermo dynamic , it's fluids mechanic !!

    • @lifefan1
      @lifefan1 2 года назад

      Yeah, but I learn this problem in Biothermodynamics course.

    • @omarjallad2001
      @omarjallad2001 2 года назад

      @@lifefan1 ok .

  • @raileehhh1039
    @raileehhh1039 Год назад

    hey give me unit conversion

  • @loudnotes8409
    @loudnotes8409 Год назад

    Patm= 101Kpa

  • @teyeon1852
    @teyeon1852 Месяц назад

    th

  • @nnadonador3038
    @nnadonador3038 2 года назад

    Can u add arabic translation 🙂

  • @fraciashiebadraper1967
    @fraciashiebadraper1967 2 года назад

    thank you

  • @ashokch1246
    @ashokch1246 3 года назад

    Thank you sir