its funny that when you write "Boring leactures about fluid statics" you get the most intresting, most enjoyable , most helpful video . Thank you so much for these videos
It can’t be understated how useful your videos are. I genuinely appreciate your channel more than you’ll ever know and wish you all the best, thank you.
At 2:09 the horisontal pressure P*sin(theta) should act on the projected surface perpendicular to it. So Py * delta z * delta x = P * sin(theta) * delta s * cos(theta) * delta x Py * delta z = P * sin(theta) * delta z Py = P * sin(theta) And by same procedure Pz = P * cos(theta)
5:10 you say “in that direction” ( assuming acc.going in the same direction as the force ) but then you draw it facing the opposite direction. Then once it’s in the tube , the acc. moves in the same direction as the force. Can you you clarify it for me please?
CORRECTION: At 10:15, the first term after P_outside, should have h3, not h1.
It doesn't matter... you've earned my Sub👍
You are wrong
Why do you times all the pressure values by 10*m/s^2 btw? what's the reasoning for that as I thought the values was already in Kg/m^3
its funny that when you write "Boring leactures about fluid statics" you get the most intresting, most enjoyable , most helpful video . Thank you so much for these videos
It can’t be understated how useful your videos are. I genuinely appreciate your channel more than you’ll ever know and wish you all the best, thank you.
WOW thank you so much for your work! Now I know when the pressures at the same height would equal to each other!
At 2:09 the horisontal pressure P*sin(theta) should act on the projected surface perpendicular to it.
So Py * delta z * delta x = P * sin(theta) * delta s * cos(theta) * delta x
Py * delta z = P * sin(theta) * delta z
Py = P * sin(theta)
And by same procedure Pz = P * cos(theta)
5:10 you say “in that direction” ( assuming acc.going in the same direction as the force ) but then you draw it facing the opposite direction. Then once it’s in the tube , the acc. moves in the same direction as the force. Can you you clarify it for me please?
the value for p(hg)gh should be. (13600) (10) (1), btw nice video and really helpful
please add the example videos too
have seen some mistakes:
1) the gravity value is 9.81
2)you used the density of water for the mercury part at the end which made it wrong
I believe a mistake was made on the manometer equation written in black at 10:15. The first column of mercury should use h3 not h1, right?
Correct, thank you!
Thank you, You are amazing
I wonder what would be the result if at 8:54 that solid obstacle was a piston.
The density of mercury should be 13600 kg/m^3 right?
Why is it 1000 kg/m^3 in your solution?
Pressure vector 0:26 seriously.....pls guide
You gotta post the examples my man😩
still waiting your example
hindi me padhane me dikkat hai kya bhai
nc