Can you solve this? | iota maths problem | Oxford entrance exam questions

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  • Опубликовано: 30 окт 2024

Комментарии • 9

  • @phillipmaxwellastrology2978
    @phillipmaxwellastrology2978 19 часов назад

    Elegant! I wanted to multiply out top and bottom completely with a similar pairing trick to what you used but you showed that that would be cumbersome and unnecessary extra work!

  • @NewsTopThe
    @NewsTopThe 21 час назад

    Good solution 4:39

  • @에스피-z2g
    @에스피-z2g 3 часа назад

    P=given formula
    P=[(1+i)/(1-i)]^2024(1-i)
    (1+i)/(1-i)=i
    i^2024=1
    P=1-i

  • @popodori
    @popodori 2 часа назад

    Answer = 1-i, (1+i)^4 = -4, (1-i)^4 = -4i, (1+i)^2024 / (1-i)^2023 = (-4)^506*(1-i)/(-4i)^506 = (1-i)

  • @ghamoz
    @ghamoz 4 часа назад

    Ma perché scrivete sempre i problemi ditti notevoli? Dovrebbero essere contenti sciuti se fai la n test d'entrata e se non li sai è giusto che stai fuori

  • @user-오리지날
    @user-오리지날 14 часов назад

    풀이가 틀렸다.
    답이 1+¿될려면 분모가 1+¿가 되어야 한다.