What do you mean by "solving" this expression? If I poke the expression into a calculator, and crunch the numbers, have I "solved" it? Is 0.000025508902624 a valid solution?
On a serious note, I tried to apply Pascal's triangle. Buah...I ended up using ChatGPT to spew out the solution. It works, but I must say, Pascal's triangle at n=12 is a nightmare. The provided solution is definitely more elegant.
Hmmm, if I use my calculator to actually calculate the value, I'm faster typing in (sqrt(2)-1)^12, so I truly wonder if the solution is a 'solution' :-D (well, the expression (sqrt(2)-1)^12 looks certainly more pleasant !!!
I solved this directly, cubing then squaring twice. Just as simple and got the same answer.
What do you mean by "solving" this expression? If I poke the expression into a calculator, and crunch the numbers, have I "solved" it? Is 0.000025508902624 a valid solution?
On a serious note, I tried to apply Pascal's triangle. Buah...I ended up using ChatGPT to spew out the solution. It works, but I must say, Pascal's triangle at n=12 is a nightmare. The provided solution is definitely more elegant.
Hmmm, if I use my calculator to actually calculate the value, I'm faster typing in (sqrt(2)-1)^12, so I truly wonder if the solution is a 'solution' :-D (well, the expression (sqrt(2)-1)^12 looks certainly more pleasant !!!
...as we have supposed x = sqrt(2)-1, not x^12. Otherwise nice solve.
Tout à fait d'accord
D(2 ➖ 1)3^4 (2 ➖ 1)^3^2^2 (1 ➖ 1)^3^1^2 ()^3^2 (x ➖ 3x+2).
What's the point? Just boring arithmetic, and you would assume your students could do that. Or perhaps it wasn't a maths exam?