This seriously cannot be a 11 min video. It cannot. Is it? really? There's a mistake i guess! I mean thanks a lot LEAH, you cover so much theory in a video which looks so small. Every sentence you speak, has an important note and a deep theory inside. You edit it, so that we can skip to the most important parts. That is the reason, why it covers an entire lecture in 11 min video. THANK YOU!
Please at 3:42 why is there a methyl on carbon 3? Ok I see a pattern...when there is no H attached(ketone) there's an extra methyl added in the product, I hope I am right.
Yes, I think you have it. The methyl on carbon 3 was the same methyl group in the original ketone, that was opposite the phenyl group. Each molecule reacting brought two carbons that were outside of the benzene ring.
Thanks ma'am. This video was very helpful. But is there anyway we can tell which product is going to be major or are they just formed in equal proportional if we take equal moles if reactants?
Glad you found the video helpful, but I'm sorry. I don't offer tutoring over RUclips comments. For more help with this, I recommend joining the orgo study hall. Full details: leah4sci.com/join
@leah4sci or anyone who can help! When you have a ketone, how do you tell what "#2" is? How can you tell which carbon is the alpha carbon? Is it the presence of a hydrogen atom that is needed? Also, whichever "R" group on the ketone that is less sterically hindered will be preferred?
The alpha carbon is the one adjacent to the carbon of the carbonyl group. I'm unsure of exactly what you're asking in regards to R groups. Less bulky R groups will facilitate the reaction due to steric effects.
I'm sorry, but I don't offer tutoring over social media. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
I'm sorry, but I don't offer tutoring through RUclips comments. For help with questions like this and more, I recommend you join the organic chemistry study hall. Details: leah4sci.com/join
Seriously this is magic you cover two hours lectures within 11 minutes.thanks a lot
Too funny about it being magic! You're very welcome :)
May God bless you, Leah. I thought for sure I was going to fail this topic. You made it easy to understand, and your examples were comprehensive.
Always happy to help! Thanks for watching. :)
Wow this is beautiful, you just made it simple and straight forward. SIMPLICITY
Thank you so much!
This seriously cannot be a 11 min video. It cannot. Is it? really? There's a mistake i guess!
I mean thanks a lot LEAH, you cover so much theory in a video which looks so small.
Every sentence you speak, has an important note and a deep theory inside. You edit it, so that we can skip to the most important parts. That is the reason, why it covers an entire lecture in 11 min video. THANK YOU!
Oh wow, thanks so much for all of your kind words, I'm beyond happy to help
really like how you explain everything so easy!!☺
Glad you enjoyed it!
thank you so much. ive been struggling to get this down
Glad to help!
you saved my life .. ur techniques are amazing ! I love your videos ! my exam is coming up
Yay, so happy to help!
Please at 3:42 why is there a methyl on carbon 3?
Ok I see a pattern...when there is no H attached(ketone) there's an extra methyl added in the product, I hope I am right.
Yes, I think you have it. The methyl on carbon 3 was the same methyl group in the original ketone, that was opposite the phenyl group. Each molecule reacting brought two carbons that were outside of the benzene ring.
@@Leah4sci thank you
Very helpful and right to the point.
Glad the video helped! Thanks!
Iam form Egypt Finally I understoooooooood I will tell you thanks in Arabic [شكرا]
Yay, glad you understand now!
your videos are far batter than coaching classes for engineering ug entrance in India thanks mam
It's my pleasure!
Really awesome video !!
Thank you!!
This was great, thank you!!!!
You're so very welcome!
Thanks ma'am. This video was very helpful. But is there anyway we can tell which product is going to be major or are they just formed in equal proportional if we take equal moles if reactants?
Glad you found the video helpful, but I'm sorry. I don't offer tutoring over RUclips comments. For more help with this, I recommend joining the orgo study hall. Full details: leah4sci.com/join
Thank you very much Dr.Leah Fisch
Not a Dr, but you're very welcome :)
Thank you so much, you're the best fr😊
Aww you're very welcome!
Thank you madam i understood ❤
You're welcome!
@leah4sci or anyone who can help! When you have a ketone, how do you tell what "#2" is? How can you tell which carbon is the alpha carbon?
Is it the presence of a hydrogen atom that is needed? Also, whichever "R" group on the ketone that is less sterically hindered will be preferred?
The alpha carbon is the one adjacent to the carbon of the carbonyl group. I'm unsure of exactly what you're asking in regards to R groups. Less bulky R groups will facilitate the reaction due to steric effects.
hellow teacher
if we have (acetone + 2,2-di methy propanal ) also we have 4 product ?
I'm sorry, but I don't offer tutoring over social media. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
Thanks a lot dear teacher .
See you in haven, Leah
Haven? CT?
OMGOD T?HIS TICK IS SOOO GOOD
Glad you like it!
I don't know when you number the ketone first or the aldehyde first in the reaction how do you tell? That is the only thing I get wrong. Thank you.
At which part of the video?
How do we do it with benzaldeyhyde and 1 phenyl Ethanone
I'm sorry, but I don't offer tutoring through RUclips comments. For help with questions like this and more, I recommend you join the organic chemistry study hall. Details: leah4sci.com/join
Crossed aldol reaction trick? More like "Cool videos, and your presentation style is slick!" 👍
Thanks!!!