Hello - good thought, but the problem is the ship has it's own speed to add to the problem, so it's not a straight addition issue...its a vector addition problem. A good rule to keep in mind is that on a moving ship, the true wind is always on the same side and aft of the relative wind. Truth be told, instead of doing a maneuvering board, the easiest way to get the relative wind off the port bow is to just turn the ship until the anemometer reads "330" and you are good to go :)
Sorry you had to change my mental diaper. Now I have it... IF- Zero(no) surface wind,.. .ANY.. heading (underway at speed) would result in "headwind". But when real life wind exist,( other than 000-360deg. or 180deg. Rel.Brg. per anemometer) ships motion or direction relative to wind, require the vector to include the relationship of both factors and produce the desired result. Thanks for instructing this global classroom.
Q-If T-Wind is from One-Six-Zero... and ship is on course( One-Six-Zero-True)...wind would be "dead ahead". If desired wind is 30deg. off port bow(330-Rel.Brg.)...if ship turns starboard to 0ne-Nine-Zero...would not that bring wind to 30deg. off port bow.??? instead of steering Two-Two-Zero?
Hello - good thought, but the problem is the ship has it's own speed to add to the problem, so it's not a straight addition issue...its a vector addition problem. A good rule to keep in mind is that on a moving ship, the true wind is always on the same side and aft of the relative wind. Truth be told, instead of doing a maneuvering board, the easiest way to get the relative wind off the port bow is to just turn the ship until the anemometer reads "330" and you are good to go :)
Sorry you had to change my mental diaper. Now I have it... IF- Zero(no) surface wind,.. .ANY.. heading (underway at speed) would result in "headwind". But when real life wind exist,( other than 000-360deg. or 180deg. Rel.Brg. per anemometer) ships motion or direction relative to wind, require the vector to include the relationship of both factors and produce the desired result. Thanks for instructing this global classroom.
great now what about a starboard solution? u still add the degrees to true wind.
12 on the 2 to 1 scale equals 12000 yards which is only 6 knots. Please correct me if I am mistaken somehow
Q-If T-Wind is from One-Six-Zero... and ship is on course( One-Six-Zero-True)...wind would be "dead ahead". If desired wind is 30deg. off port bow(330-Rel.Brg.)...if ship turns starboard to 0ne-Nine-Zero...would not that bring wind to 30deg. off port bow.??? instead of steering Two-Two-Zero?
std 30p at 30 kts
You are correct :)