Introduction to Finite Element Method by Dr. R. Krishnakumar,Department of Mechanical Engineering,IIT Madras.For more details on NPTEL visit nptel.ac.in
@@Akash-xw4wt this is the net displacement of the nodes since 2 ends have different displacements,hence the net displacement has been taken into account
Folks...He is professor at IIT - Premier institute in India. It is very coveted position in India and competition is fierce. Most of the time, these professors complete their PHDs in US and come back. I studied at IIT. Students from IITs go on to have very successful careers due to the solid foundation.
Within the short span of time, Sir you have covered a lot of concepts very effectively. Your students are fortunate to have you as a mentor. Thank you, sir.
I was slightly sceptical of the quality of teaching in the video, but i was proven very wrong. I am a student in Australia and I was super happy with the way that the professor taught. Thank you very much for posting such videos for free.
If you write u1 and u2 instead of ui and uj, and write F1 and F2 instead of Fi, Fj, you can easily interpret the physical meaning that " kij is the force that has to be applied at j in order to have unit displacement at I"
But when we took an element we considered the forces acting on that element, then why in the end while forming matrices we took F2 = 0 (why we take only external forces, while when were analyzing we had considered the forced on single element????)
Question : at the end of the day isnt the fixed point just having an equivalent force to the opposite side of the force ? Why can't we put the force there ?
He clearly stated that only the external forces are considered in the force matrix. (bcz internal forces are created and balanced itself by the system)
there are no external forces applied at nodes 1 or 2 - fr this reason f1 and f2 will both be 0. the only external force is applied at node 3 which is why f3=p
Ui & Uj have taken based on one end fixed condition - @ 11:50 And @13:20, professor took a force matrix, for stepped shaft and told the above forces to be super positioned, If we apply super position principle Ui & Uj have to take positive as they are not resistive displacements. Can anyone please explain clearly? Thanks
The Fj he showed by arrow is the force on the node 2 by the element. But the Fj he mentions is the reaction force by the wall on the node 2 (opposite direction)
Sorry all, i know my question doesn´t fit FEM matter but what is the name of the song at the beginning?. My Indian Yoga teacher was used to sing it at the beginning and at the end of all lesson.
Because node 1 was fixed so there could be zero displacement in position of node 1. So displacement u becomes 0 and when u solve the matrix 1st row and column do get multiplied with 0 that gives the ans 0 only. So to save time we just eliminate the row n column as it's no use to continue with them
This lecture directly went into my brain , thank you sir, now i understand why IIT professors are so great.
I understood from this Mr. In one hour, what I didn't understand from my professor in one semester
may be now your basic concept is strong now than you had during your semester classes
@@abhishekchakrabarty2930 at 12:55 why we is doing (Ui-Uj)
@@Akash-xw4wt this is the net displacement of the nodes since 2 ends have different displacements,hence the net displacement has been taken into account
@@abhishekchakrabarty2930 thank you so much.
@@Akash-xw4wt welcome
Holy shit. This is one of the best lectures on the topic I have ever seen. No wonder India pumps out some great engineers.
jobless engineers
😂😂Lol..
@adi saha he is not talking about you.
Folks...He is professor at IIT - Premier institute in India. It is very coveted position in India and competition is fierce. Most of the time, these professors complete their PHDs in US and come back. I studied at IIT. Students from IITs go on to have very successful careers due to the solid foundation.
What is your Full name and in which IIT have you studied, which branch have you taken ?
Explained in a way that's easy to understand and a pace thats easy to follow.
Thank you very much for this lectures. I am from Brazil and it is helping me a lot.
Great
Within the short span of time, Sir you have covered a lot of concepts very effectively. Your students are fortunate to have you as a mentor. Thank you, sir.
I was slightly sceptical of the quality of teaching in the video, but i was proven very wrong. I am a student in Australia and I was super happy with the way that the professor taught. Thank you very much for posting such videos for free.
J
they are not free, but taken and posted here from a paid correspondence service/course..
Great class ! Here from Brazil. It's helping me a lot. Congratulations to the Professor Dr. R. Krishnakumar and the NPTEL.
Greetings from Bulgaria! Great lecture series, thank you so much for sharing it!
this is by far the simplest video for a very complicated topic in Engineering.. Hats off to you PRoff..
i like this guy ! better then my lazy technology orinetated lecturers half snoring as they sit down and click away on powerpoint.
Half snoring :D
If you write u1 and u2 instead of ui and uj, and write F1 and F2 instead of Fi, Fj, you can easily interpret the physical meaning that " kij is the force that has to be applied at j in order to have unit displacement at I"
i wanna give u abig thanks , i have an exam and i have not understand any word from the teacher , u make it too simple to me ^ - ^
I really love Indians Profs...the best to explain well and in easy way...
this professor is really good
Thank you for the video. FIVE stars to this man he is the best teacher.....
Congrats on the outstanding way of teaching! Very noble professional
YES IT IS MOST LIKELY TO HAVE YOUR LECTURE
Excellent lecture. I appreciate the effort put to explain the essence of the formulas rather than simply writing them down. Thanks a lot.
Thanks , I 'm from Colombia and send you my regards.
EXCELLENT, OUTSTANDING..........
Clear, comprehensive and easy-to-understand. Very nice job, thank you
35:17 why they are doing k1+k2 at middle of matrix. pls explain
@@Akash-xw4wt
For getting a global stiffness matrix we add the local stiffness matrices
Awsome didactic .... thk u nptel ... thk u ... governement of India for this attitude ..
thanks for your teaching which helps me a lot~
the best ... spreading the last knowledge
This dude speak best English in Indian lecture.:D
Fantastic teaching !
very clear and in a lucid manner.
Easy to understand FEA.
Very good lecturing...
First
Nptel video jo samaj mai aagyi🙏🙏🙊
Genius level teaching. Thank you
Awesome video! Thank you!
Thank you sir for this invaluable lecture
practical , simple well explaineed
Excellent, clear, step by step lecture
Out standing explanation 🙌🙌
What an amazing teacher ❤
Excellent explanation
Very well explained. Thank you.
A very informative lecture.
thanks for your lecture sir..
Greetings from ksa ! Great lecture series, thank you so much for sharing it!
Thank you...nice explanation
Well explained. Thank you
thanx alot well explained
Thank so much Dr. Could you more clearly explain the position that you add the second stiffness matrix into the first stiffness matrix?
good lecture i understant alot
Heck of a lot better than my prof :p
Sir, I have seen today first. Really good for anyone. I want to attain all of your lecture one by one.
Now he works in Deep Learnning .
Amazing, thank you so much!
35:17 why they are doing k1+k2 at middle of matrix. pls explain
please can you help to find out extreme value of the function for a given equation
Very Nice Lec.
very intersting tutorial
I'm just here for that sweet sitar music. In all seriousness, this man is a very good lecturer.
Excellent !!
What he did first is the stiffness method to resolve hiperstatic estructures?
How to make sure that convergence is maintained in FEM analysis ?
Very interesting lecture
very well explained
I'm tackling this subject on my own efforts..its brutal
thank you very much sir
best. thanks sir
Thank you sir 🙏🏻❤️
Very interesting.
very good lecture
nice video.....
I am facing a problem in assembly. If we add then won't the force F2 double?
Excellent
very simple
At 6:53 how did you combined both the Fi and Fj ?
Nice information
GOOD JOBS
This video is giving me PTSD. FEA was the hardest class i ever took.
But when we took an element we considered the forces acting on that element, then why in the end while forming matrices we took F2 = 0 (why we take only external forces, while when were analyzing we had considered the forced on single element????)
i understood in the case of 2/2 matrix but not understand in the case of 3/3 matrix, means applying of third element
What if we apply body force with the given problem, how to solve that
how to handle the uniform loading in FEA
komal deep may be you already know this but you can integrate the shape function
Question : at the end of the day isnt the fixed point just having an equivalent force to the opposite side of the force ? Why can't we put the force there ?
because there is no displacement at the fixed point. F=ku. when u is zero, the force there will be zero as well
He clearly stated that only the external forces are considered in the force matrix. (bcz internal forces are created and balanced itself by the system)
35:17 why they are doing k1+k2 at middle of matrix. pls explain
I would like to give 10-15 more likes if possible. om shanti.... thank you very much
I could not understand the k1 k2 ui uj soooo confusing. Can any one help me in understanding.
last few sentences were very important
nice
i am from somali i keen on this teacher
From somaliland 👋
can anyone help me understand why he omitted the first row just because u1=0 at 45:14
if u multiply the row and column becomes zero so he removed them
How? Can you elaborate - When you multiply row 1 , you get k1*0 + -k1*u2 + 0*u3= F1 which implies F1=-k1*u2
there are no external forces applied at nodes 1 or 2 - fr this reason f1 and f2 will both be 0. the only external force is applied at node 3 which is why f3=p
Anjan: see the figure.. In the fig there are 3 node .. the nod 1 is at fixed end .. so the displacement at the fixed end become zero{u1=o}
Our Lord and savior
good lecture, very useful. I just need to download it with the english words of what you say, like it's on the youtube. how can i do this?
+MOSTAFA HAMIDO please use freemake video downloader.
Super
nice
why did he consider only the external forces?
Ui & Uj have taken based on one end fixed condition - @ 11:50
And @13:20, professor took a force matrix, for stepped shaft and told the above forces to be super positioned, If we apply super position principle Ui & Uj have to take positive as they are not resistive displacements.
Can anyone please explain clearly?
Thanks
Sorry I can't explain.
@ why they are doing k1+k2 at middle of matrix. pls explain
35:17 why they are doing k1+k2 at middle of matrix. pls explain
At 10:20, F(i)=-F(j), which means opposite in direction, then why in the diagram both F(i) and F(j) in same direction.
The Fj he showed by arrow is the force on the node 2 by the element. But the Fj he mentions is the reaction force by the wall on the node 2 (opposite direction)
Désolé mais je ne comprends pas l'anglais. Y'a t'il des autres cours en français ??
please anyone how het got k1+k2 term in the stifness matrix?
I havent too understood how he got the matrix after the two elements were added . Can anyone explain?
Can anybody tell how he eliminated the row
I believe thats the way the matrix works out by mathematics. If you try to multiply the matrix they will result to be zero.
@@stephanosphilippou1300 why did he consider only the external forces?
Sorry all, i know my question doesn´t fit FEM matter but what is the name of the song at the beginning?. My Indian Yoga teacher was used to sing it at the beginning and at the end of all lesson.
+Fabio Emolumento
it is prayer for peace in the world.
19:00
how 1st row and 1st column get cancelled for u1 = 0
It affects other equation (ie for F2 and F3) in no way....each time the u1=0 will make its term zero.
Because node 1 was fixed so there could be zero displacement in position of node 1. So displacement u becomes 0 and when u solve the matrix 1st row and column do get multiplied with 0 that gives the ans 0 only. So to save time we just eliminate the row n column as it's no use to continue with them
@@bvk9686 why did he consider only the external forces?
HOW F1 = u1*k1 ?
He assumes u2 and u3 to be zero.