Introduction to Finite Element Method by Dr. R. Krishnakumar,Department of Mechanical Engineering,IIT Madras.For more details on NPTEL visit nptel.ac.in
Thanks for uploading this. But one suggestion, it would be better to provide table of contents for all lecturers, what the professor is covering and so on.
+Chethan Rajan screenshooter.net/102749565/fjngbhd not sure if this is right. It is often assumed that the strains are small, and therefore that the node travels not along a circle curve, but along a straight line (if strain is v. small, it is almost the same) someone please correct me if I'm wrong.
actually he took it as assumption that if E2(youngs modulus) of second element is greater than E1(youngs modulus) of first element ....actually youngs modulus is the measure of stiffeness of element so if youngs moduls is high then eventually strain which is change in length will be less ... so displacement will be less....if stiffenes is hing then stress developed will be less ....so thats wht he is saying assuming E2 (youngs modulus ) of second element is greater than E1 .. thanku :)
@07:05 professor has told epsilon2 as u3-u2/L2. Can I know the explanation, possibly? As the material is same how the displacements are negated. Please provide information in terms of figure also
here epsilon2 is change in length divided by original length....epsilon fr second element is difference of u3 and u2 since u2 is dispacement before application of force nd u3 is displacement after application of force....so change in length of 2nd element is u3-u2 ...and original length of 2nd element is L2 so epsilon2 is change in length divided by original length.... u3-u2/L2 ...... thnaku :)
The Physics you explained about change in length is correct, but i noticed that if you use the equation of epsilon= U3-U2/L2 to solve for sigma (stress) = P/A2, it yields a different answer. At the end, I think he used epsilon= U2/L2 to find sigma (stress). Please, explain otherwise if you can. Thanks
I think it will be easier to understand id you consider the nodes as points. So node 2 has moved by distance u2 and node 3 has moved by u3 in the same direction, to net displacement is u3-u2 and the net strain is as he calculated
u3 is displacement of link(2-3). Link(2-3) stats at position 2 and ends at position 3. If point2 or otherwise called node2 is displaced then link(2-3) starts at position new2 . u3 is only related to link(2-3). which means link(2-3) has elongated by u3. hence strain of link(2-3) = u3/(length of link(2-3)). correct me if im wrong
Thanks for uploading this. But one suggestion, it would be better to provide table of contents for all lecturers, what the professor is covering and so on.
These videos are fantastic, thank you!
Thank you for sharing videos on Finite Elements.
Thank you for uploading this. Its very well explained.
Well Explainedto sir.it reallyto help usto to understandigcall the concepts.
Audio becomes severely de-synced as the video goes on.
just watch the video at a higher speed and you wont notice. I watch them at 1.5x.
how to increase the speed?
ananth boudhmanabhan you will find that option in the settings menu..
BEAUTIFUL COURS
helpful lecture..thank u sir
great video! Thank you!
very good lecture.
Nice video.. got to know about 'zee'
Can we have access to assignment/ problems to compliment the great lectures by Dr. Krishnakumar?
The section for inclined bar is not clear.
How do I cite the publisher of this content? The lectures have been very helpful...
NPTEL video lectures. nptel.ac.in/courses/112106135/4
how can i get the homework of this course?
@ 30.06 !!! how does shortening of length become = c *ui ? . can anyone pls explain it.
+Chethan Rajan screenshooter.net/102749565/fjngbhd
not sure if this is right.
It is often assumed that the strains are small, and therefore that the node travels not along a circle curve, but along a straight line (if strain is v. small, it is almost the same)
someone please correct me if I'm wrong.
That intro >.>
Please someone to explain me the idea of 11:06 ......i don't get it !!
Can I know what is your doubt? clearly
actually he took it as assumption that if E2(youngs modulus) of second element is greater than E1(youngs modulus) of first element ....actually youngs modulus is the measure of stiffeness of element so if youngs moduls is high then eventually strain which is change in length will be less ... so displacement will be less....if stiffenes is hing then stress developed will be less ....so thats wht he is saying assuming E2 (youngs modulus ) of second element is greater than E1 .. thanku :)
How did he got s in the stiffness matrix
He explained that in his previous lecture to this one.
Could you fix the time delay on the audio?
at 3:50 how does he end up with u3=p1/k1+p/k2
Instead of they way he does it by substituting u3 in the second equation do it the other way aroudn. Substitute u2 and you will get the answer.
Gabriel Silva Simple algebraic math problems. Just try you will surely get that answer.
THX SIR
@07:05 professor has told epsilon2 as u3-u2/L2. Can I know the explanation, possibly?
As the material is same how the displacements are negated. Please provide information in terms of figure also
here epsilon2 is change in length divided by original length....epsilon fr second element is difference of u3 and u2 since u2 is dispacement before application of force nd u3 is displacement after application of force....so change in length of 2nd element is u3-u2 ...and original length of 2nd element is L2 so epsilon2 is change in length divided by original length.... u3-u2/L2 ...... thnaku :)
The Physics you explained about change in length is correct, but i noticed that if you use the equation of epsilon= U3-U2/L2 to solve for sigma (stress) = P/A2, it yields a different answer. At the end, I think he used epsilon= U2/L2 to find sigma (stress). Please, explain otherwise if you can. Thanks
I think it will be easier to understand id you consider the nodes as points. So node 2 has moved by distance u2 and node 3 has moved by u3 in the same direction, to net displacement is u3-u2 and the net strain is as he calculated
I am getting the same answer sigma2= P/A2 using the same formula for epsilon2.
u3 is displacement of link(2-3). Link(2-3) stats at position 2 and ends at position 3. If point2 or otherwise called node2 is displaced then link(2-3) starts at position new2 . u3 is only related to link(2-3). which means link(2-3) has elongated by u3. hence strain of link(2-3) = u3/(length of link(2-3)). correct me if im wrong
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