Self-Bias Configuration of JFET (Graphical Approach)
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- Опубликовано: 3 янв 2017
- Analog Electronics: Self-Bias Configuration of JFET (Graphical Approach)
Topics Discussed:
1. Transfer curve of JFET.
2. Transfer curve plot using Shockley's equation.
3. Operating point of JFET.
4. Homework problem.
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the slope is given by ID=(-1/RS)(VGS). VGS is negative, so it will make the whole equation positive, and as we increase RS(1/RS), 1 divided by a bigger number, we will get a smaller number, so it would decrease. Since it is decreasing, it would move toward X-axis.
Slope will decrease when Rs is increased and the Q-point will move towards the x-axis.
@Hamid Ali Shah Slope = (-1/Rs) , if you increase Rs, you are increasing the denominator so slope value(mod) will decrease. ( In reality actual value of slope increases because there is a minus sign, and actual value is going from more negative to less negative )
@@94D33M Darlin you're wrong. What you've said is right if the case is Vgs as positive. But you know that in JFET we're having Vgs as negative. Calculate again and let me know.
Final answer : Slope decreases as the resistance increases.
slope will decrease means it will tend toward xaxis or vgs and point will also tend towards vgs or x axis
thank you sir, very well explained!
Thank you so much sir 😍
I love the explanation....
Ans: load line will move downward towards x-axis and so slope decreases...
Indeed graphical approach is much simpler than the mathematical
Excellent sir
Thank you sir
Life saver!!
I think slope as a whole will increase due to the -ve sign and hence it'll move towards the y-axis..
Will you create lessons for MOSFETs biasing and dc-ac analysis?
tq sir😀😄😍😍
can we assume the VGS? just like that?
All clear but how did you find q point?
Pls sir....make video of differential amplifier
r= -1\(0 ~1); so r= - 1 ; so slope will move towards x-axis, and Q-point move to
x-axis
On increasing resistance , slope will decrease n Q pt. will shift towards X axis
slope will increase and q point goves towars -ve x aix as graph is in 3rd quadrant
We will never get the approx q point is this method worth it ...and what about mathematical approach
Angle between straight line and x axis will decrease if R increase and that's why q point deflect towards x axis
slope = decrease & Q-point move towards X-axis
As Rs increases slope's magnitude value will decreases & Q point will move towards - ve x-axis
How to measure Idq and Vgsq from the graph ??
By looking at the graph. Finding the intersection on x and y axis by looking at it.
Saviour neso 😭😭
Sir i could not understand Qpoint ? How to findout plz tell
How to get VGSq?
02:07 how the id= idss asper when vgs= bp the Id should be 0???
Slope will increase and Q point towards y axis
why Idss/4, y not Idss/2
As the Rs is increasing the q point will shift towards the x axis ( downwards )
Sir, at pinchoff voltage the drain current gets saturated to Idss, but when we substitute Vgs=Vp The drain current is becoming zero
Can you please clear it sir
At pinch off voltage drain current will be nearly 0, it can't be Idss., It'll be 0.
I think the slope will increase due to the negative sign and will tend to go towards ID axis(y-axis)
towards x
slope will decrease as Id will decrease hence Q-pt. will shift towards x-axis
I love indian 💗💗💗
By increasing Rs the operating point will move towards X-axis
confusion about ID=IDSS/2 WHY IT NOT =IDSS/4
I took Idss/100000. But i had to do 99999 other substitutions to find out the accurate graph.
From where did we get the number 4 in Idss/4 in 2:40?
It's a formula
@@wessionaldo6853 Thanx, I graduated anyway
@@MansAO-bv7ok Wth why was this response so fast lmao. Congrats mate you still alive. I got my exam tomorrow so watching videos likes these XD
@@wessionaldo6853 because I was shocked someone respond to me in 4 years about a topic I dont even remember when I took it 😂😂, good luck on your exam tho
as the Rs increses the slope decreases
Since the mathematical approach, you didnt even tell us what is current of the drain???
We can find I D using Schottky equation 🙄😔
When Vgs =Vp Id is zero right at 2:31
how to assume the Vgs?
thanks
Gase gase slope brhte gae ge q point b brhta gae ga
Slope of the curve will decrease if we increase Rs. Thus the st.line will shift towards x-axis and Q-point will also shift towards x-axis.
slope decreases
moves towards x axis
How Id = Idss/4
If vgs= vp/2
Then id=idss(1-(vgs/vp))^2
id=idss(1/2)^2
id=idss/4👍😊
Sir what about your channel Neso academy in Hindi. I was student of Hindi medium so I want the videos in Hindi.
Please help me *
If Rs increases then slope will decrease and operating point willove upward.
as RS is increased slope will decrease inverse relation and Qpoint will near to x axis