Khan Academy gets constantly so much praise and they deserve it, but for someone looking to pass with 5 days of studying in the whole semester videos like this are what truly can help.
0:00 direct substitution 0:43 manipulating equation to allow direct substitution 1:53 proving the limit D.N.E. 4:15 proving the limit D.N.E. 6:59 direct substitution 7:35 proving the limit D.N.E. 12:40 manipulating equation to allow direct substitution 15:20 using parametric curves
@@anirudhbukka5413 Mathematics courses are both in science and commerce program. Some concepts are same between science and commerce program, only the applications parts are different
Lmao pray for me...I havent paid attention all semester, but my final is tomorrow. I'm cramming with his videos. hahaha. This could be the first class I fail in my life. Jesus take the wheelll. I got an A in both Calc 1 and 2 so if I fail it would be a major disgrace for me and my GPA. I'm on the honors list, so hahaha pray for me.
I think in the last example, when we approach the function from the y-axis (which gives us x = 0 and y = 0), the result doesn't equal to zero. So, from that, we can conclude that the limit DNE.
So glad I'm not the only one who saw that, I was freaking out thinking I did it wrong instead of him just using the equation to teach using parametric curves.
If only i had a maths teacher like you before.. I won't t have been here today watching your videos. But I am glad that i watched it. You explained my whole degree in just these minutes. Thank you so much. 💛 Your videos are worth watching...
tbh calculus 3 isn't that hard....try taking Differential Equations ...Undergrad classes aren't that bad tbh. It's those Master's level classes that are insane.
@@lidyasolomon5557 Actually, calc 3 is straight forward in the fact that you kind of already built up the foundational skills in Calc 1. Conceptually though, calc 3 actually gets really hard you just don't get tested on some of the topics that can have problems that get really hard (and are applicable to areas like engineering, physics etc.). You barely scratch the surface of partial differentials in that entire chapter.
Professor Organic Chemistry Tutor, thank you for solving Limits of Multivariable Functions in Calculus Three/ Multivariable Calculus. In some cases, Polar Coordinates can also be used to evaluate Limits of Multivariable Functions in Multivariable Calculus. This is an error free video/lecture on RUclips TV with the Organic Chemistry Tutor.
Kudus to d create tutor on RUclips. I'm at d top of my class with d help of ur tutorials. Now in lvl3 & I'm missing ur tutorials on d courses I'm taking. But thanks so much for ur support sir.
really good video thanks, just had a question. In the last example you stated that this problem couldnt be solved by travelling over a certain axis, but if we travel over the y axis this limit becomes y^2/2y^2 which is 1/2 which is different than going over the x or z axis so the limit doesnt exist. Or am I overlooking something?
@@gold9994 yea that’s not the point, he made us do an extra few minutes of work just to figure out what we coulda gotten if we used x=0 and z=0. I mean it was useful learning the substitution with T but he still shoulda used a different example equation tho
46. Limit of a function of a variable. Suppose a function of a variable is given, f(x). Let x take on a sequence of values, nearer and nearer to a fixed value a, in such a way that lim x = a, or x → a in the sense of the preceding section, but in this connection with x = a expressly excluded. With this exception x → a in any manner whatever. As x → a, f(x) will take on a corresponding sequence of values, and it is possible that f(x) will approach some fixed value L as a limit. If so, we write lim x→a f(x) = L This is read "the limit of f(x) as x approaches a is L." (That x ≠ a is to be understood.)
for the last one, just put in 2√y for x and you'll see taking this results in the limit being four, saves you a lot of work. But very good video, keep up the hard work :)
Watching this to explore if multivar calc would be the right choice for me next sem, given the inadequate support given for Calc 1 by my uni. Now I know who I can turn if I were to encounter problems during the course 👍🏻
4:00 The answer is 0 not undefined or 0/0, because we do not care about the value at the point only the value around it, hence shouldn't directly substitute.
A variable approaches a constant as a limit when, after a certain point, the absolute value of the difference between the variable and the constant becomes and remains less than any preassigned positive number however small; and the constant is called the limit of the variable.
@@terryyoon1856 same here I also completed calculus 3 in high school. Doing real analysis and complex manifold theory. I am just here to revise some details
Okay…… I mean I do understand what he’s talking about here… however… usually they decide to do the limit as (x,y)-> (x,0) and not the limit as x->0 because then we’d have to remember that if it is as x approaches 0, we must not do direct substitution for x=0… I hope this makes sense. At least to him… idk if anyone knows what I mean but that’s why it confused me when I was learning this… but other than that this is great!
I don't how to thank u ❤❤ u are just awesome 😊😊😊 omg when my teacher explains any thing I would sleep later I come search for ur video that's it.... U are rockz
In the last problem, I think if you set x and z to 0, you will get a limit of 1/2. So that solves the problem already without needing the parametric method.
1)subtitusi 2)pemfaktoran 3)cek x=0,y=0,y=x,y²=x (jika salah satu beda maka artinya tidak punya limit 4)kali sekawan 5) dimisalkan dg t (utk fungsi 3var)
12:36 then I have to also think of a relation between y and x that'll make me find a way that the limit doesn't exist, and if I can't think of one even though there is, and all the previous steps have the same results, then I'm getting a wrong answer?
¶ Definition. A variable approaches a constant as a limit when, after a certain point, the absolute value of the difference between the variable and the constant become and remains less than any preassigned positively number however small; and the constant is called the limit of the variable.
¶¶46. Limit of a function of a variable. Suppose a function of a variable is given, f(x). Let x take on a sequence of values, nearer and nearer to a fixed value a, in such a way that lim x = a, or x → a in the sense of the preceding section, but in this connection with x = a expressly excluded. With this exception x → a in any manner whatever. As x → a, f(x) will take on a corresponding sequence of values, and it is possible that f(x) will approach some fixed value L as a limit. If so, we write lim x→a f(x) = L This is read "the limit of f(x) as x approaches a is L." (That x ≠ a is to be understood.)
My professor put one of these questions on my calc 2 final... I had no idea what to do, and when I asked her what I was looking at she just told me to figure it out.
Hi, Mr. JG. Not sure if you'll read my message.... Being that you posted this video only six months ago, I am truly hoping that you see my post. Pertaining to calculus 1, would you be so kind & amazing and please post a video on limit using delta and epsilon? This has my head spinning right now and I am trying to understand the point of reversing the steps within my work, etc. Please. I would greatly appreciate it. Thank you for all that you've done for this community that supports & follows your page.
6:54 you are saying no limits which is more rational then what my dcotor sent us which is that absolute value of f (x, y) = [ x^2/ (x^2 + y^2)] × | y | is all less or equal to a.v. Of y therefore the limit f when x, y tends to zero is 0.
Per what I've so seen so far from your tutorial, it you apply direct substitution and get a fraction with 0 as the numerator, the limit exists but if both the numerator and denominator are 0 the limit does not exist?
![I.N "HALLUCINATION" | [Stray Kids : SKZ-PLAYER]](http://i.ytimg.com/vi/n5B5q1Hwt_U/mqdefault.jpg)
Final Exams and Video Playlists: www.video-tutor.net/
Khan Academy gets constantly so much praise and they deserve it, but for someone looking to pass with 5 days of studying in the whole semester videos like this are what truly can help.
How’d the rest of your class go?
This guy is good for learning how to do something quickly, but for more rigorous math you’ll have to stick to a textbook or khan academy.
@@mrbanana6464 accurate! Like the parameterization at the end? Lost me.
I think it depends on what you are doing, for math major this is not enough, but for engineering studies, this is very helpful
0:00 direct substitution
0:43 manipulating equation to allow direct substitution
1:53 proving the limit D.N.E.
4:15 proving the limit D.N.E.
6:59 direct substitution
7:35 proving the limit D.N.E.
12:40 manipulating equation to allow direct substitution
15:20 using parametric curves
Thanks
Thank you for the timestamps!
you are angel something thanks
Just came here to say I've watched all your Calc videos, don't know what I'd do without you. I'm on Calc 3 now so keep em coming!
right
Same here, he made Calc II a breeze. Calc 3 is harder though :p
@@anirudhbukka5413 college
@@anirudhbukka5413 Mathematics courses are both in science and commerce program. Some concepts are same between science and commerce program, only the applications parts are different
Are you huys seriously self-teaching calculus????
I mean college courses are hard enough
Lmao pray for me...I havent paid attention all semester, but my final is tomorrow. I'm cramming with his videos. hahaha. This could be the first class I fail in my life. Jesus take the wheelll. I got an A in both Calc 1 and 2 so if I fail it would be a major disgrace for me and my GPA. I'm on the honors list, so hahaha pray for me.
Euchariah Brown got a 78 and ended the class with a B
@@ampleeeeeeeee thanks lololol
@@lidyasolomon5557 Awesome; I’m glad you could pull it out! 👍
@@PunmasterSTP lmao thanks I graduate with honors we good 😭 how r u
@@lidyasolomon5557 That’s excellent to hear! I’m doing fine myself.
You are single handedly giving me my math credits towards my degree 😂
I think in the last example, when we approach the function from the y-axis (which gives us x = 0 and y = 0), the result doesn't equal to zero. So, from that, we can conclude that the limit DNE.
yeah, for the y-axis I got 1/2
@@付相龙-b2t yes same
Yeah that's right 👍
There itself we can say that limit doesn't exist
So glad I'm not the only one who saw that, I was freaking out thinking I did it wrong instead of him just using the equation to teach using parametric curves.
16:43 last example the y -axis when z=0 and x=0 its equal 1over2 which not zero
Yea bro. So we can conclude that limit does not exist at that step
Yea I did the same too
But he is trying to teach us more ways to solve incase this one didn't work in some other cases
@@pranavbhanot816 yep
You’re right
If only i had a maths teacher like you before..
I won't t have been here today watching your videos.
But I am glad that i watched it.
You explained my whole degree in just these minutes.
Thank you so much. 💛 Your videos are worth watching...
Which degree are you doing that can be explained in a basic multivariate calculus tutorial video
@@akshatsrivastava4280
i love it when a topic I'm struggling on has been explained by ur channel-- else cramming for one night would've been a nightmare
best channel for engineering maths studies istg Idk what I would've done without you
I’m in Algebra 2 as a sophomore and I understand this. That’s how good this guy is at explaining math.
right
Wtf. We finished Calc AB as a sophomore lol
tbh calculus 3 isn't that hard....try taking Differential Equations ...Undergrad classes aren't that bad tbh. It's those Master's level classes that are insane.
@@lidyasolomon5557 Actually, calc 3 is straight forward in the fact that you kind of already built up the foundational skills in Calc 1. Conceptually though, calc 3 actually gets really hard you just don't get tested on some of the topics that can have problems that get really hard (and are applicable to areas like engineering, physics etc.). You barely scratch the surface of partial differentials in that entire chapter.
I always wonder, why the channel name is The Organic Chemistry Tutor when a person who is teaching is actually a gem in mathematics.
This is absolutely amazing!!!!!!!!!!!!! Why don't we have teachers like you in school????? 😭😭😭😭 life would've gotten much easier!!!!! 🥺
You are the reason why am still surviving calculus
Professor Organic Chemistry Tutor, thank you for solving Limits of Multivariable Functions in Calculus Three/ Multivariable Calculus. In some cases, Polar Coordinates can also be used to evaluate Limits of Multivariable Functions in Multivariable Calculus. This is an error free video/lecture on RUclips TV with the Organic Chemistry Tutor.
Kudus to d create tutor on RUclips. I'm at d top of my class with d help of ur tutorials. Now in lvl3 & I'm missing ur tutorials on d courses I'm taking. But thanks so much for ur support sir.
Your videos are fast and to the point! Thank you
I'm not even a chemistry major hahaha
Is there a limit as to how many topics you can cover? Keep up the good work!
The limit approaches infinity
It DNE
All smiles right now. Thanks for saving a soul
Organic chemistry tutor! SAVING STUDENT'S GRADES TILL ETERNITY🎉
The last example helped me on my quiz so much for proofs!! thank you!!
really good video thanks, just had a question. In the last example you stated that this problem couldnt be solved by travelling over a certain axis, but if we travel over the y axis this limit becomes y^2/2y^2 which is 1/2 which is different than going over the x or z axis so the limit doesnt exist. Or am I overlooking something?
right
Yes I got the same too
@bjorn van der lande Same happened with me. I came to the comments section when I got y^2/2y^2 which is 1/2
It does not exist. If it fails to be the same from whenever we approaches, it's not existent.
@@gold9994 yea that’s not the point, he made us do an extra few minutes of work just to figure out what we coulda gotten if we used x=0 and z=0. I mean it was useful learning the substitution with T but he still shoulda used a different example equation tho
46. Limit of a function of a variable. Suppose a function of a variable is given, f(x). Let x take on a sequence of values, nearer and nearer to a fixed value a, in such a way that lim x = a, or x → a in the sense of the preceding section, but in this connection with x = a expressly excluded. With this exception x → a in any manner whatever. As x → a, f(x) will take on a corresponding sequence of values, and it is possible that f(x) will approach some fixed value L as a limit. If so, we write lim x→a f(x) = L This is read "the limit of f(x) as x approaches a is L." (That x ≠ a is to be understood.)
for the last one, just put in 2√y for x and you'll see taking this results in the limit being four, saves you a lot of work. But very good video, keep up the hard work :)
Watching this to explore if multivar calc would be the right choice for me next sem, given the inadequate support given for Calc 1 by my uni.
Now I know who I can turn if I were to encounter problems during the course 👍🏻
Thank you! I was really stuck in this 3 variable limit at the origin, but this gives me hope to get an answer:)
4:00 The answer is 0 not undefined or 0/0, because we do not care about the value at the point only the value around it, hence shouldn't directly substitute.
Just a question, for the last problem, approaching from the y-axis, leaving x=0 and z=0 wouldn't you get 1/2 which also proves the limit DNE?
i got the same question
i did thge same thing
thank you so much. this saves me so much since im a visual learner
Gosh, your vid always help me, love your work, very simple yet easy to understand 2 hours of my lecture
Thank you sir one video solved my all problems
16:23, we can approach via y-axis after trying via x-axis, both answers are coming different.
A variable approaches a constant as a limit when, after a certain point, the absolute value of the difference between the variable and the constant becomes and remains less than any preassigned positive number however small; and the constant is called the limit of the variable.
very important point. totally agree.
I still remember doing this back in my highschool in Canada! Thanks for bringing back my memories!!
highschool?
@@assaultszn3557 I started studying calculus when I was grade 6 and then i happened to advance through math in HS 🙂
@@terryyoon1856 same here I also completed calculus 3 in high school. Doing real analysis and complex manifold theory. I am just here to revise some details
don't you guys normally only do Calc.1?
@@metawhirl4609 smart-ass
THIS VIDEO IS A LIFE SAVER ,THANK U SO MUCH
Okay…… I mean I do understand what he’s talking about here… however… usually they decide to do the limit as (x,y)-> (x,0) and not the limit as x->0 because then we’d have to remember that if it is as x approaches 0, we must not do direct substitution for x=0… I hope this makes sense. At least to him… idk if anyone knows what I mean but that’s why it confused me when I was learning this… but other than that this is great!
16:32 approaching by y axis wont give you 0 but 1/2 .
This has helped me a lot, mainly it cleared my confusions. Thanks a lot.
The last example without using the t, the limit as y approach 0 is 1/2. Hence DNE.
Same answer👍
Sir you are very great teacher ☺️❤❤❤❤❤❤❤❤❤
I don't how to thank u ❤❤ u are just awesome 😊😊😊 omg when my teacher explains any thing I would sleep later I come search for ur video that's it.... U are rockz
U are my saviour
My professors must need to take your lectures
Calc 3? im so far gone from calc 1 trying to find an answer from a test... good luck Uni students doing this.
can anyone explain in 16:35 along y-axis we have x=0,z=0 don't we get a limit of 1/2
16:36, I'm sorry but if I check with lim y->0 which is (x=z=0), i got 1/2, isn't it?
ya, I got that too. In that case the limit doesn't exist
Sir your lectures are very helpful to me.
In the last problem, I think if you set x and z to 0, you will get a limit of 1/2. So that solves the problem already without needing the parametric method.
exactly i tried it too and with lim y approaches 0, the result is 1/2 thus proving the limit doesn't exist :)
Yeah that's correct ☺️
There itself we can say that limit doesn't exist
i like this type of video. Not too fast and he explained it step-by-step
1)subtitusi
2)pemfaktoran
3)cek x=0,y=0,y=x,y²=x (jika salah satu beda maka artinya tidak punya limit
4)kali sekawan
5) dimisalkan dg t (utk fungsi 3var)
question about the last problem, is it okay to let x,z=0 and the value becomes y^2/2y^2 which keeps value 1/2 and can say it's limit dne?
You are awesome man. Best explanation ever.
Good teaching sir
I am indian
the best maths tutor
Thank you very much! haven't been paying attention in class lately
you are right
Multivariable limits? More like “Magnificent learning, and this is lit!” 👍 🔥
12:36 then I have to also think of a relation between y and x that'll make me find a way that the limit doesn't exist, and if I can't think of one even though there is, and all the previous steps have the same results, then I'm getting a wrong answer?
In the last example the limit can also be proven to not exist by approaching from the y-axis( answer = 1/2) and the x-axis or z-axis(answers = 0)
your great man
¶ Definition. A variable approaches a constant as a limit when, after a
certain point, the absolute value of the difference between the variable and
the constant become and remains less than any preassigned positively
number however small; and the constant is called the limit of the variable.
¶¶46. Limit of a function of a variable. Suppose a function of a variable
is given, f(x). Let x take on a sequence of values, nearer and nearer
to a fixed value a, in such a way that lim x = a, or x → a in the sense
of the preceding section, but in this connection with x = a expressly
excluded. With this exception x → a in any manner whatever. As
x → a, f(x) will take on a corresponding sequence of values, and it
is possible that f(x) will approach some fixed value L as a limit. If so,
we write
lim x→a f(x) = L
This is read "the limit of f(x) as x approaches a is L." (That x ≠ a
is to be understood.)
Great video, you really blessing the community 💯
Love your videos, can you make a Calc 3 final exam review video? Thanks!
My professor put one of these questions on my calc 2 final... I had no idea what to do, and when I asked her what I was looking at she just told me to figure it out.
Thank you so much, keep up the good work master.
Thank you so much for all your videos. Got me through high school and calculus 2 last semester. Do you have a calculus 3 playlist?
You can also approach from y axis in the last example.It's turned out to be (1/2)😊
shush u slop
this was very helpful I can't thank you enough! treat yourself to something good ok??
Hi, Mr. JG. Not sure if you'll read my message.... Being that you posted this video only six months ago, I am truly hoping that you see my post. Pertaining to calculus 1, would you be so kind & amazing and please post a video on limit using delta and epsilon? This has my head spinning right now and I am trying to understand the point of reversing the steps within my work, etc. Please. I would greatly appreciate it. Thank you for all that you've done for this community that supports & follows your page.
This is a good video but I wish there were more examples of 3 variable limits and more problems that are not at the origin
thank you man you helped me a lot
Tutor
At last sum if y applied it in y axis u get the lim y->0 as ½ like that we can prove right
Such a great explaination and many different examples! Thank you a lot!!!!
6:54 you are saying no limits which is more rational then what my dcotor sent us which is that absolute value of f (x, y) = [ x^2/ (x^2 + y^2)] × | y | is all less or equal to a.v. Of y therefore the limit f when x, y tends to zero is 0.
Wow 😲😲 Really an awesome lecture on this topic.....👏👏❤❤
great video. Thanks for this tutorial sir. God bless
Thank you so much! Please keep making Calc 3 videos!
Thanks you for... I'm from Pakistan
Very helpful channel , keep going 👍🏻👍🏻
Can't we use L'hospital in those kind of questions ? if so how we could determine the answer without approaching value that we are looking for ?
6:59 is that a limit or not now ?
thank you so much mr chemistry
TY for what you do, so useful
Coming in clutch for physics and now calc 3😩
The last example, when y approcahes 0, the answer is 1/2 which is different from when x approaches 0. So DNE.
am following from malawi .
very informative thank you very much !!!
Thank You so much for this video.
Isn’t 3:57 cannot be computed since it is 0/0
no because its 0/y before u even plug in 0, so its gonna be limy-->0 (0) which has no variable so its just 0
limit to 0 isn't exactly zero but close to 0, it can be 0,00000000000000001 and it's still not 0, therefore it is not actually 0/0 and can be computed
It really cleared my concept 😊.
love your voice
this video is fantastic, thank you
In last question,when limit y approaches 0 result in 1/2.
currently eating chi chi fries with my boyfriend studying for our midterm tmw...thanks a lot tutor
What are Chi Chi fries? Never heard of them.
and 4 no. y = mx for proofing that it is path dependent and so the limit doesnot exist
at 6:34 aren't the limits approaching from either axis 0/0? I thought that meant the limit DNE, not that its equal to 0
In the last one when I tried approaching from the y-axis I got 1/2
on the last example y axis gives u 1/2 so we can conclude that dns
2 days to sem 1 exam ...
💀 hope these videos will save me !!
Per what I've so seen so far from your tutorial, it you apply direct substitution and get a fraction with 0 as the numerator, the limit exists but if both the numerator and denominator are 0 the limit does not exist?