Some people who are very knowledgeable can't teach, and this happens to be the case with a lot of professors. Glad there are people like you out there making entire courses for subjects like this, for free - these videos are a lifesaver.
Thank you for all of these videos!! I finally understand this and feel confident about taking the OAT next week. Thank you Chad for making Organic Chemistry make sense and also somewhat enjoyable!!
Chad, over the years of taking chemistry, I have found your videos a great resource and it has helped me learn concepts in minutes that would have otherwise taken hours. Thank you for creating this channel. Don't ever stop creating content!
Yes but the problem is he didn't tell us the amount of heat Look if, Heat is high at 40°C or more. E1, E2 Heat is low at 25°C or less. Sn1 , Sn2 So he might have meant the heat is 25°C or less but forgot to write it
sorry for the question but why in the reaction of minute 8:02 it follow hofman rule and not zaitsev's rule and in the last reaction it follows the zaitesv's one ?
Really good video, but the way my professor taught this made this so much more confusing. He didn't even provide practice problems in the style he taught it. I guess learning this more in-depth may help me later on down the line. Just hoping the final doesn't get too confusing
im so sorry for the dumb question but for time stamp 12:13 you called that carbon a tertiary carbon, I am a bit confused on how that is tertiary? I took it as a secondary carbon and looking at the chart you'd still get e2 for your major product but could you please explain it a bit? Does the "Ph" have anything to do with that? I have never seen that before in these types of problems. I also just seem to struggle in general when questions have the structures showing stereochemistry like that haha
My apologies Raeanne as I should have been more explicit in stating that the Ph is an abbreviation for a phenyl group, a benzene ring. It is therefore the 3rd carbon that the tertiary carbon is bonded to. And you're right though too. Even if it had been a secondary carbon it would still have gone E2 as the major product (though SN2 would have been a minor product). But with it tertiary it is just E2 as SN2 is not possible for a tertiary halide. Hope this helps and best with your upcoming finals!
@@ChadsPrep Ahh okay, gotcha! That does help a lot and actually rings a bell, for I have heard and am familiar with the phenyl group, just never seen it abbreviated with a Ph in a problem. Thank you so much for your prompt response. I have my last exam before my final this friday and I like to get through lots of practice problems and that one had me confused, but all is well now! A big thanks for also doing these super helpful videos, you are saving me this semester!!
The acetate ion is quite a bit weaker nucleophile than an alkoxide ion due to resonance but still quite a bit stronger than water or an alcohol and can be strong enough to still perform SN2 reations. Hope this helps!
Hi Chad, at 6:50 for E2 reaction why are we not first checking if the leaving group and hydrogen are anti peri-planar? Is there an exception to this rule for alkanes that are not in a ring? And thank you so much for making these videos, they are extremely helpful and I hope you gain more viewers!
Hi Chad, I wanted to ask for a secondary carbon, when a weak Nuc is introduced, it will undergo Sn1 or E1. However, once a weakly basic nuc is introduced, it undergoes SN2 nstead of Sn1 - why does this occur?
Can I just clarify whether you are talking about a strong nucleophile that is a weak base? or which part of the video is this about? A weakly basic nucleophile that is still a strong nucleophile will favor sn2 over e2 because elimination reactions are acid/base reactions and require a good base to occur. Sn2/Sn1 would not compete in this case with a strong nucleophile that is a weak base.
@@ChadsPrep I meant to say when a weak nucleophile (that is neutral, say H2O) is reacted with a secondary carbon SN1 or E1 can occur but when the nucleophile changes to a strong nucleophile that is weakly basic, only Sn2 can occur, I don’t understand why this happens. This is what it says on the sheet my professor gave us.
So a strong nucleophile on a secondary alkyl halide indicates sn2 or e2, the fact that it is a weak base prevents e2 from occuring since we need a strongly basic nucleophile for e2, leaving sn2 as the only option.
@@wel_r remember that the first step in E1 is the loss of a leaving group. If you have a strong nucleophile it will attack first rather than 'waiting' for the leaving group to leave :)
Some people who are very knowledgeable can't teach, and this happens to be the case with a lot of professors. Glad there are people like you out there making entire courses for subjects like this, for free - these videos are a lifesaver.
Thanks for saying so - Happy Studying.
Thank you for all of these videos!! I finally understand this and feel confident about taking the OAT next week. Thank you Chad for making Organic Chemistry make sense and also somewhat enjoyable!!
Awesome Marianne! Hope your OAT goes (or went) well and best in the application process!🙂
Chad, over the years of taking chemistry, I have found your videos a great resource and it has helped me learn concepts in minutes that would have otherwise taken hours. Thank you for creating this channel. Don't ever stop creating content!
Always glad to hear how the channel has helped out so much. Much success to you in your educational and professional endeavors!
Chad your channel and website are awesome. Give it some time and you will be one of the biggest chemistry youtubers out there. Thank you!
Thanks for saying so, Bryce - appreciate the vote of confidence!
O man your explanation really handy and easy to remember, you help me a lot at organic exam, 3000 thank you for you chad!
You're very welcome Keqing (3000 welcome😉)! So glad you found this lesson helpful!
I’m watching this 30 minutes before my exam and it’s making so much sense!
Hope you did well!
@@ChadsPrep I did soooo good on that part of the exam!!! I memorized the charts you used in the video! Thank you! ✨
@@xXnutriaXxExcellent - all your hard work paid off!
Best video out there explaining substitution and elimination reactions. Thank you so much for making tricky subjects enjoyable to learn!
You're welcome - thank you!
you are the best Chad. Your explanations are really simple to understand. Thank you so so so much.
You're welcome and Thank You!
Chad's the man!!!
Thanks again Joey! Glad you found another lesson helpful!🙂
Thnakyooooo so much for the amazing lectureee....🎉
Mooooost weeeelcommmme!
For the first example, would the reaction mainly favor elimination because there is heat involved? (delta symbol)
Yes but the problem is he didn't tell us the amount of heat
Look if,
Heat is high at 40°C or more. E1, E2
Heat is low at 25°C or less. Sn1 , Sn2
So he might have meant the heat is 25°C or less but forgot to write it
Thank you for organic chemistry .It was really helpful for me
Excellent!
Awesome as always! Thank you, Chad!
You're welcome, Chani - thanks for the comment!
sorry for the question but why in the reaction of minute 8:02 it follow hofman rule and not zaitsev's rule and in the last reaction it follows the zaitesv's one ?
Really good video, but the way my professor taught this made this so much more confusing. He didn't even provide practice problems in the style he taught it. I guess learning this more in-depth may help me later on down the line. Just hoping the final doesn't get too confusing
Glad the video helped you.
Hi at 9:55 why is one the leaving group and other is not ?
im so sorry for the dumb question but for time stamp 12:13 you called that carbon a tertiary carbon, I am a bit confused on how that is tertiary? I took it as a secondary carbon and looking at the chart you'd still get e2 for your major product but could you please explain it a bit? Does the "Ph" have anything to do with that? I have never seen that before in these types of problems. I also just seem to struggle in general when questions have the structures showing stereochemistry like that haha
My apologies Raeanne as I should have been more explicit in stating that the Ph is an abbreviation for a phenyl group, a benzene ring. It is therefore the 3rd carbon that the tertiary carbon is bonded to. And you're right though too. Even if it had been a secondary carbon it would still have gone E2 as the major product (though SN2 would have been a minor product). But with it tertiary it is just E2 as SN2 is not possible for a tertiary halide.
Hope this helps and best with your upcoming finals!
@@ChadsPrep Ahh okay, gotcha! That does help a lot and actually rings a bell, for I have heard and am familiar with the phenyl group, just never seen it abbreviated with a Ph in a problem. Thank you so much for your prompt response. I have my last exam before my final this friday and I like to get through lots of practice problems and that one had me confused, but all is well now! A big thanks for also doing these super helpful videos, you are saving me this semester!!
@@raeanne5793 i also have this Friday 😭😭😭😭
@@nomantalib688 aw best of luck to you!!
@@raeanne5793 thnx ❤🇵🇰
Hi Chad
Where does CH3CO2- belong in?
Is it strong nuc/strong base because it is RO- ??
The acetate ion is quite a bit weaker nucleophile than an alkoxide ion due to resonance but still quite a bit stronger than water or an alcohol and can be strong enough to still perform SN2 reations. Hope this helps!
Hi Chad, at 6:50 for E2 reaction why are we not first checking if the leaving group and hydrogen are anti peri-planar? Is there an exception to this rule for alkanes that are not in a ring? And thank you so much for making these videos, they are extremely helpful and I hope you gain more viewers!
because the other side is bulkier it will prefer the hofmann product instead
You're PERFECT ❤️❤️❤️❤️
Thank you.
شكرا ع المعلومات القيمة والشرح الممتع
دكتور ممكن اسم الكتاب الخاص بحضرتك
sehe ich auch so
For the last example, why does the E2 reaction not occur on the primary beta carbon?
Hi Chad,
I wanted to ask for a secondary carbon, when a weak Nuc is introduced, it will undergo Sn1 or E1. However, once a weakly basic nuc is introduced, it undergoes SN2 nstead of Sn1 - why does this occur?
Can I just clarify whether you are talking about a strong nucleophile that is a weak base? or which part of the video is this about? A weakly basic nucleophile that is still a strong nucleophile will favor sn2 over e2 because elimination reactions are acid/base reactions and require a good base to occur. Sn2/Sn1 would not compete in this case with a strong nucleophile that is a weak base.
@@ChadsPrep I meant to say when a weak nucleophile (that is neutral, say H2O) is reacted with a secondary carbon SN1 or E1 can occur but when the nucleophile changes to a strong nucleophile that is weakly basic, only Sn2 can occur, I don’t understand why this happens. This is what it says on the sheet my professor gave us.
So a strong nucleophile on a secondary alkyl halide indicates sn2 or e2, the fact that it is a weak base prevents e2 from occuring since we need a strongly basic nucleophile for e2, leaving sn2 as the only option.
@@ChadsPrep thank you, but why doesn’t E1 also happen?
@@wel_r remember that the first step in E1 is the loss of a leaving group. If you have a strong nucleophile it will attack first rather than 'waiting' for the leaving group to leave :)
How do you identify a strong vs a weak base? For example why is potassium tert-butoxide a strong base?
purely memorization , what you just mentioned is the most well known bulky strong base.
Nice
Thanks Mahammadasif! Glad you found it helpful!
You should do this one with a whiteboard aswell!
Thanks for noticing!
I don't understand the last question. Pls if u can write it for me
what are you struggling with about it?
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