from one bald guy to another, you've been a life saver over the past semesters and still helping me out - The shaved head of yours is fire man! keep up the good work. You're awsome 🫡
Because we only account for what is directly bonded to it. If you say "CCH", then we are saying Carbon 6 is DIRECTLY bonded to another carbon, another carbon and a Hydrogen. But that is not the case, we have 2 Hydrogens that are not drawn on that carbon.
Hey Nicole, for this last example we care looking at the groups attached to C7 and C8 to determine E/Z. Carbon 7 has CH3 versus CH2 so the CH3 takes priority. C8 has CH3 versus H so the methyl takes priority, so in that sense the methyl group has priority in both cases. Let me know if you're still having trouble with this
Hi Chad, don't you want to offer one or more (e.g. only for members viewable, except some for trial / advertising) playlist of advanced topics explained in the way you explain all your previous topics. Sorry if my English sounds strange; I come from Germany... Or one big playlist with different videos of the different advanced chemistry topics or so. Some proposals for advanced topics: quantum mechanics chemical reaction engineering advanced analytical chemistry theoretical chemistry group theory macromolecular chemistry name reactions advanced inorganic chemistry of elements and their compounds biochemistry microbiology organometallics semiconductor chemistry environmental chemistry industrial chemistry statistics in chemistry supramolecular chemistry medicinal chemistry It would be nice if you would start with the quantum mechanics playlist or advanced analytical chemistry 😉🙃 I would pay for advanced topics and there are nearly no good video tutorials in English or German. I guess that there would be many interested people in it worldwide.
Hey Asma, i know this is late but the reason why you have it wrong is because you didn’t count the carbons the proper way. When naming alkenes, ALWAYS put the double bonds in priority. So you want them to have the lowest carbon locator number. You started counting from the tail end, which gives the double bond carbon locator numbers C4-C5; however, that is not the lowest possible number for the double bond. If you start on the opposite side, the double bond then has locator numbers C3-C4, which is what you want. Always remember that you double bonds and functional groups needs to have the lowest possible carbon locator number.
Thank you Chad! You clear all my confusions every lesson!
Great to hear!
from one bald guy to another, you've been a life saver over the past semesters and still helping me out - The shaved head of yours is fire man! keep up the good work. You're awsome 🫡
Thanks - glad the channel is helping you so much!
Thank you! I am getting love ochem because of your videos :)
Glad to hear it, Ryan!
Great video! LOVEEE how you explain things!
Thank you!
This is really helpful ,better than my Prof.
Much respect
Glad the channel is helping you.
With these classes Chemistry becomes fun, thanks Chad!!
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love you man, real lifesaver
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Thank you very much sir, God bless you ❤
You're welcome and to you also.
Thankyou chad❤from india😊
You're welcome from USA!
Keep up with your good work
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Thank you so much Chad!
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Commenting to support short bald guy 😂
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Do you use E and Z or trans and Cis when naming a cycloalkene?
Funniest chapter😂👌🏽
Glad you enjoyed!
God I love you and your videos ! Thanks so much for this !
We love it when people love our videos - thanks for commenting, grace!
So helpful
Good!
17:10 why the carbon 6 is C H H not C C H since C6 is bonded to C5 that is double bonded
Because we only account for what is directly bonded to it. If you say "CCH", then we are saying Carbon 6 is DIRECTLY bonded to another carbon, another carbon and a Hydrogen. But that is not the case, we have 2 Hydrogens that are not drawn on that carbon.
thank you king
Very welcome!
my man
Happy Studying!
Hi! Why is Carbon 9 not the same priority as the methyl group attached to Carbon 7 as both carbons are attached to 3 Hydrogens?
Hey Nicole, for this last example we care looking at the groups attached to C7 and C8 to determine E/Z. Carbon 7 has CH3 versus CH2 so the CH3 takes priority. C8 has CH3 versus H so the methyl takes priority, so in that sense the methyl group has priority in both cases. Let me know if you're still having trouble with this
Hi Chad, don't you want to offer one or more (e.g. only for members viewable, except some for trial / advertising) playlist of advanced topics explained in the way you explain all your previous topics. Sorry if my English sounds strange; I come from Germany...
Or one big playlist with different videos of the different advanced chemistry topics or so.
Some proposals for advanced topics:
quantum mechanics
chemical reaction engineering
advanced analytical chemistry
theoretical chemistry
group theory
macromolecular chemistry
name reactions
advanced inorganic chemistry of elements and their compounds
biochemistry
microbiology
organometallics
semiconductor chemistry
environmental chemistry
industrial chemistry
statistics in chemistry
supramolecular chemistry
medicinal chemistry
It would be nice if you would start with the quantum mechanics playlist or advanced analytical chemistry 😉🙃
I would pay for advanced topics and there are nearly no good video tutorials in English or German.
I guess that there would be many interested people in it worldwide.
that would be great. I prefer name reactions playlist
WHY I DIDN'T FOUND THIS GUY BEFORE
Welcome to the channel - Happy Studying!
I'm gonna be a short bald guy too someday Chad! You make it cool!
Welcome (soon) to the 'club'!
at 4:21 mn For the second molecule I wrote 5-Ethyl-2methyl-4-heptene Is it wrong , why . Thank you !
Hey Asma, i know this is late but the reason why you have it wrong is because you didn’t count the carbons the proper way. When naming alkenes, ALWAYS put the double bonds in priority. So you want them to have the lowest carbon locator number. You started counting from the tail end, which gives the double bond carbon locator numbers C4-C5; however, that is not the lowest possible number for the double bond. If you start on the opposite side, the double bond then has locator numbers C3-C4, which is what you want. Always remember that you double bonds and functional groups needs to have the lowest possible carbon locator number.
i got confused at the cis and trans part
🎉 ANYONE FROM ETHIOPIA❤🇪🇹
Welcome from USA
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@@ChadsPrep you are so excellent
DAMN😂