10 Challenging Limit Problems! Can you survive?😱(part1)🔎Riemann Sum, Squeeze Theorem, Floor Function

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  • Опубликовано: 16 сен 2023
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Комментарии • 24

  • @user-jq5us6di2p
    @user-jq5us6di2p 10 месяцев назад +7

    影片做的活潑有創意,謝謝老師的分享,希望大家記得按讚多多支持喔!

  • @leo-ec5xu
    @leo-ec5xu 10 месяцев назад +4

    影片做得很棒👍

  • @goldfist8711
    @goldfist8711 10 месяцев назад +2

    Great video!

  • @brightmoonchiefyue
    @brightmoonchiefyue 8 месяцев назад

    第三題過程這樣寫的話,閱卷老師可以直接給零分。floor function 不是連續函數,極限怎麼可以直接搬進去?

  • @user-qd9fo4gl9y
    @user-qd9fo4gl9y 8 месяцев назад

    第一題直接開羅,第二題用夾,第三題先配方,第四題原本想說直接開羅,原來要先變成e,第五題用黎曼

  • @MH-sf6jz
    @MH-sf6jz 8 месяцев назад

    第二題為什麼 {(1+3/x)^(x/3)}^(3(x-1)/x) 可以把base和exponent 分開take limit?

  • @MH-sf6jz
    @MH-sf6jz 8 месяцев назад

    第三題直接把limit pass進去floor function 有點misleading,9減去那個limit應該還是9,所以找你的寫法那個floor function的結果(如果pass limit進去)應該還是9。更加準確的說法應該要考慮x在一個small enough neighborhood of 3, 然後bound 9-(x-3)^2 above strictly by 9然後 再lower bound by 8,這樣才能conclude floor function 是8吧。

    • @ThisisChuan
      @ThisisChuan  8 месяцев назад

      感謝提醒🙏
      計算題這樣寫確實不大嚴謹,我要表達的是可以初步用判斷得到答案是 8。

  • @choke7273
    @choke7273 10 месяцев назад

    For the 5th question, I think it is possible to just integrate the top and bottom, as the error becomes infinitely small as n approaches infinity, so you will obtain (n^(3)/3)/((2n^(3/2)/3))^2 = 3/4.
    The reason why the error will be very small is that when you draw the function x^2 and x^1/2, they will both go to infinity, and the error of the calculation is just the difference of area between the function and the function where x is an integer, it is hard to explain with words, but you will understand if you draw the graph yourself

    • @choke7273
      @choke7273 10 месяцев назад

      For example, 1+2+3+...n=(n+1)n/2, and integral x dx = x²/2, well if you limit n to infinity it becomes n²/2 just like the integral

    • @choke7273
      @choke7273 10 месяцев назад

      But I would admit your method is the bigger brain one

    • @ThisisChuan
      @ThisisChuan  10 месяцев назад +2

      This idea is good. More precisely, simply divide both the numerator and denominator by n^3, and you'll obtain the Riemann sum in both the numerator and denominator.
      ( ∫ x² dx )/( ∫ x½ dx )² from 0 to 1
      = (1/3)/(2/3)² = (1/3)/(4/9) = 3/4.

  • @user-qx6qg6wr3v
    @user-qx6qg6wr3v 8 месяцев назад

    我以為第四題又要拋棄羅畢達了xd 難得看到羅畢達 第五題感覺是在考對summation 的基本概念夠不夠強跟熟練

    • @ThisisChuan
      @ThisisChuan  8 месяцев назад

      羅畢達還是會給鏡頭的 XD

  • @user-ks9lv9jg9c
    @user-ks9lv9jg9c 4 месяца назад

    用遊戲王的音樂來解題 必須給讚

  • @user-yp7ki3py5m
    @user-yp7ki3py5m 6 месяцев назад

    窩似被遊戲王吸引來的😂

  • @R_Chuang
    @R_Chuang 10 месяцев назад

    你第一題懂夾擠定理,但後面卻說趨近極限忽略不計,這很奇怪,好像懂數學又不懂