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9 minutes of pure knowledge conductivity I appreciate your work sir
Super helpful, thanks!
At 1:50, How is the velocity higher at p1 than p2 when p1 is higher in pressure than p2 ?
Why is it that we assume the mass flow rate at the inlet and exit to be the same?
steady state ( open Sys)
If we assume we are in a steady state then the net mass flow will be zero so mi-me=0, which means mi=me=m
9 minutes of pure knowledge conductivity
I appreciate your work sir
Super helpful, thanks!
At 1:50, How is the velocity higher at p1 than p2 when p1 is higher in pressure than p2 ?
Why is it that we assume the mass flow rate at the inlet and exit to be the same?
steady state ( open Sys)
If we assume we are in a steady state then the net mass flow will be zero so mi-me=0, which means mi=me=m