Bending Stress

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  • Опубликовано: 24 авг 2024

Комментарии • 34

  • @alexwright9254
    @alexwright9254 8 лет назад +7

    Your videos have helped me far more than my lecturer and the notes; before seeing them I really struggled to grasp the concepts of bending and how to calculate moments, stresses etc, but now it's becoming much clearer. Thanks a lot.

  • @fms9601
    @fms9601 8 лет назад +19

    Thank you so much, your explanation style is fifty times better than my lecturer!!, and I'm in a high ranked university

    • @YZ755
      @YZ755 8 лет назад

      +Faisal Alshammary what uni r u at

    • @faolan1686
      @faolan1686 8 лет назад +2

      I did a diploma on engineering under him before going to uni. I didn't know how spoilt I was to have a teacher like him.

    • @furkanyesil5096
      @furkanyesil5096 5 лет назад +1

      faolan1686 what is his name ?

  • @susanasimonable
    @susanasimonable 8 лет назад +8

    fantastic teaching! so clear. wish all my lecturers were this good. thank you much for sharing

  • @ingDemurtas
    @ingDemurtas 7 лет назад +5

    very clear explanation, thanks! I would follow all the course if you could give titles with lesson number like #1 #2 #3....so that the order is clear :)

  • @LaurencePresland
    @LaurencePresland 9 лет назад

    Excellent videos! Helping me a great deal in HSC Engineering Studies. Thank you!

  • @kylem6532
    @kylem6532 7 лет назад

    Your videos are amazing! I super appreciate the fine work and the fact that you're willing to share such valuable knowledge. Thank you!

  • @josephaddy2007
    @josephaddy2007 2 года назад

    Great Teacher SIR

  • @aliaboud9202
    @aliaboud9202 2 года назад

    Jamani jamani 😭😭😭

  • @momelezimoriat6513
    @momelezimoriat6513 6 лет назад

    Booyah, ndiyabulela 🇿🇦

  • @kavishamahabir8340
    @kavishamahabir8340 8 лет назад +4

    God will bless you! thank you so much!

  • @uh1100
    @uh1100 2 года назад

    the denominator must be indirectly proportional to the stress but it isn't. Why?

  • @josephaddy2007
    @josephaddy2007 2 года назад

    Wow...

  • @jean-lucrouckout350
    @jean-lucrouckout350 2 года назад

    where can I find a book about this lesson and diagrams?

  • @burakceylan9409
    @burakceylan9409 6 лет назад +1

    2:31 hahaha teacher is alien

  • @natedmathematicssolutions7674
    @natedmathematicssolutions7674 7 лет назад

    nice teaching style,any lecture on macaulay's method

  • @ciidyoonis6211
    @ciidyoonis6211 6 лет назад

    thank you lecturer u so help me

  • @alungileliano6626
    @alungileliano6626 6 лет назад

    wonderful indeed. thank you

  • @likhithabobbili616
    @likhithabobbili616 5 лет назад

    sir please make a video explaining Mohr's circle also sir

  • @yashthakur6927
    @yashthakur6927 3 года назад

    Can anyone tell me name of professor in this viedio

  • @davidgruty
    @davidgruty 8 лет назад

    I have a question. If you get this "diagonal" linear distribution of sigmas (plot on the top left of the board) and you have an I-beam, what happens on the top of the web (right below the flanges). The area in the y-height is small, and it has lot of stress.
    Shouldn't the I-beams have something like a X (two opposite triangles) shape? thanks

    • @homebird4765
      @homebird4765 5 лет назад

      Yeah those come under composite sections and at that point stress diagram changes i. e it doesn't show diagonal distribution like this one.. Look up bending stresses in composite sections buddy..

  • @josesamb
    @josesamb 8 лет назад

    wow..

  • @pitagorasramos8679
    @pitagorasramos8679 6 лет назад

    Hi, I need all leson about welding conection from this teacher, please help me!

  • @SaadKidwai
    @SaadKidwai 5 лет назад

    Thank you!!!

  • @aimanahmed8237
    @aimanahmed8237 4 года назад

    Pdf for this lecture

  • @homebird4765
    @homebird4765 5 лет назад

    How come there is tensile stress at top in the U section?
    Shouldn't the top have compressive stress?

    • @ultramagneticsago6329
      @ultramagneticsago6329 4 года назад

      If it becomes a cantilever, then the tensile stress will be at the top and compression stress at bottom. In cantilever beams, the top most fiber experiences stretching while the bottom extreme fiber experiences the most compression.

  • @bhavikbhatt8346
    @bhavikbhatt8346 7 лет назад

    how to find I

  • @chunhuima7819
    @chunhuima7819 5 лет назад +1

    Is there someone learn it just for fun like me?

    • @enydee
      @enydee 4 года назад +1

      No