Beam Bending: Avoiding Failure

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  • Опубликовано: 22 дек 2024

Комментарии • 221

  • @kenman3756
    @kenman3756 9 лет назад +24

    You are a credit to your profession and your presentation style is both elegant and straightforward.

  • @yongchunseow9455
    @yongchunseow9455 4 года назад +5

    I'm confused now.. why did I spend 1 year to study this where I can get 100% knowledge in this 10 mins video? Awesome video and thank you so much!

  • @eduardoquintanaavila.6290
    @eduardoquintanaavila.6290 3 года назад +1

    Su estilo de explicar es muy sencillo y claro de entender. Me hubiera gustado tener una maestra asi. Explica tan bien que enamora su estilo.
    Gracias maestra.

  • @DukeLaCrosse20
    @DukeLaCrosse20 10 лет назад +12

    Lots of good stuff in this video, but here's the most important point -- the Area Moment of Inertia is proportional to the cube of the height of the beam. Consider standard lumber: a 2x8 beam (oriented with height = 8) vs a 4x4 beam (same length). They have the same amount of wood, but the 4x4 beam will deflect 4 times as much as the 2x8. This is why rafters do not have a square cross sectional area and are often 2x10's or even 2x12's.

    • @unpopularopinion149
      @unpopularopinion149 5 лет назад

      Same amount of wood matter. One is twice as long but the other is twice as wide.

  • @MistressGlowWorm
    @MistressGlowWorm 10 лет назад +16

    Wonderful lecture and well explained! Thank you!

  • @yohashannes3682
    @yohashannes3682 8 лет назад

    wow even me I am undergraduate civil engineering student ,I really appreciate that u post this video clear and easy way .thanks

  • @cesarperalta827
    @cesarperalta827 9 лет назад

    Eres increible
    es la explicacion mas simple y facil de comprender que he visto
    Sube mas videos para calculo de vigas con perfiles y ejes huecos de maquinas
    muchas gracias por tu trabajo

  • @mindofganza
    @mindofganza 6 лет назад +1

    The way you teach is brilliant!

  • @byaruhangajonah9092
    @byaruhangajonah9092 5 лет назад +2

    I am a teacher as well but this is beautiful work and you are gifted

  • @karimkhan1312
    @karimkhan1312 12 лет назад

    this is the best lecture i have heard-- i am having difficultly in under standing theory of elasticity , theory of plasticity , heat transfer by convection & hydyodynamics

  • @rsreisang
    @rsreisang 12 лет назад +9

    Wish I had such tutorials during my engineering course :)

  • @MrHucker09
    @MrHucker09 9 лет назад +2

    Great work. Clear and concise.

  • @realcivilengineers
    @realcivilengineers 7 лет назад +1

    please upload more videos , ur way of explaining is very much understandable

  • @PKKROYAL
    @PKKROYAL 3 года назад

    Does FOS of high loaded structural components shall be calculated based on Yield Stress ?

  • @ZombieRevenge777
    @ZombieRevenge777 5 лет назад

    If you use your cantilever for a piping systeme support , how do you calculate the dynamic charge of the fluid and then add the dynamic weight to the centalever calculation ?

  • @anoop0354
    @anoop0354 12 лет назад +1

    i have few doubts abt monet of inertia. Is there any more videos by Mariya?

  • @rezhuq
    @rezhuq 12 лет назад +3

    Absolutely marvellous explanation! Thank you!

  • @aftabqurashi3015
    @aftabqurashi3015 7 лет назад +2

    very effective teaching as well as appreciable hard work...

  • @Subbu1811
    @Subbu1811 9 лет назад +3

    Madam, Thanks for this video, contents of which are very easy to comprehend.

  • @brianbender7438
    @brianbender7438 3 года назад +1

    Very nice job and easy to understand. Thank you.

  • @shawnlowery7162
    @shawnlowery7162 2 года назад

    Does this only work for cantilever beams?

  • @starsrkh
    @starsrkh 12 лет назад +1

    Really really good, fantastic and clear explanation of concepts.

  • @Zaid-ez6ci
    @Zaid-ez6ci 3 года назад

    am i wrong? the distance for calculation of the moment should be perpendicular, right?

  • @jacqueswolfaardt5481
    @jacqueswolfaardt5481 5 лет назад +1

    Excellent explanation. It actually made sense!!

  • @ridwanhusainishraq
    @ridwanhusainishraq 2 года назад

    I didnt understand one thing. how did you calculate the moment provided by the lever while lifting the load at 7.28? The distance L isnt perpendicular to the point of application of applied force. How come is it FxL? SHouldnt you take the perpendicular component of it?

  • @manishkawale4037
    @manishkawale4037 5 лет назад

    Suppose there is ductile body which is subjected to bending moment . After calculating induced bending stress . How should I check whether it will fail or not.?

  • @fishstyx9705
    @fishstyx9705 6 лет назад

    How do you calculate in diagonals on a deck beam with 3 posts?

  • @gadha707
    @gadha707 10 лет назад

    2:45. Were each of those two classmates (tall and short) grew 1 inch naturally? Or were they pulled along their lengths and thus both experienced elongation of 1 inch? I can only see strain on them if they were pulled. Btw, it is highly likely that the tall dude came back to his original height once the force was removed whereas the shorty exhibited a plastic deformation and gained 1 inch of much needed height permanently!

  • @aepassion
    @aepassion 10 лет назад

    6:23 Can someone explain the integral please? Is Integral(y^2) some kind of a formula for area moment of inertia?? And lastly How is it that: Integral (y^2) = (bh^3)/12
    ?? Thanks in advance.

    • @ifearwomen
      @ifearwomen 9 лет назад

      +Thor
      In pure bending around the z axis (axis coming out of the screen) in this case, you have a distribution of stresses on the cross-section that are positive when y > 0 and negative when y < 0 as the y axis is defined in the middle of the beam, so that the beam bends clockwise around the z axis. The resultant moment at the cross-section is the sum of those stresses that depend on y over the cross-section area. The integral alone is the moment of area.
      The integral of the cross-section area is seen as integrating x from 0 to b and y from -h/2 to h/2: integral(integral(y^2 dy) dx), then the integral about x is independent and sums up to b, the other integral leaves 1/3*(h^3/8 - (-h^3)/8) which is h^3/12.

  • @RuRu0091
    @RuRu0091 4 года назад

    This is very helpful when im just get in civil engineering, why youtube recomend this now, now i feels like wasting alot of time reading textbook to understand this thing
    Anyways thanks for the video its very helpful

  • @karthic4647
    @karthic4647 6 лет назад

    It was useful for me . I need to know how much load can withstand for simply supported Beam . In that what are measurements i have to take in practical time .

  • @pradeepkarna
    @pradeepkarna 10 лет назад +1

    superb...ccan u say why we draw shear force and bending moment?what happens physically if shear force is zero ? and what happens to the beams physically if the bending moment is maximum?? ans it soon pls

  • @manjunaik3234
    @manjunaik3234 4 года назад +1

    Thank you so much, for this video
    I'm looking for
    Manual hand calculation for analysis and design for learning complete step by step process
    please can you share calculation document, please 🙏

  • @davidselin9860
    @davidselin9860 3 года назад

    Great video and easy to follow, I am confused though, i tried plugging your values into the formula s but couldnt get hte same results as you. possibly because I couldn't read the value exponents from your board (I am not a mechanical engineer,but i need to understand as i am building a canopy over double doors.
    The values I have as as follows:-
    F=0.5 N, L=0.25M, b=0.025M h=8x10^-4M, E=69x10^6Pa, I=1.07^-2 M.
    I am many orders of magnitude out. I get 3.51^-3 mm and 4.67^-3 Mpa respectively.
    Where have I gone wrong?

  • @khiemluong4591
    @khiemluong4591 7 лет назад

    How do I differentiate the width/thickness measurement from the height measurement in a beam?

  • @batteredredbox
    @batteredredbox 6 лет назад

    Thank God. Saved my life.

  • @defendermodsandtravels
    @defendermodsandtravels 2 года назад

    Minor niggle. The choice of the failure of the Tacoma Narrows isn't very relevant to the content of this lesson. In that case it was vortex shedding loads causing a dynamic response leading to failure by lateral-torsional buckling. All of these are advanced topics.
    The video was well presented and much clearer than many others.

  • @noelstevens2117
    @noelstevens2117 10 лет назад +7

    Great Stuff. Explained really well. It's a pity you didn't teach me back at College. :)

  • @mohammadreyaz880
    @mohammadreyaz880 5 лет назад

    What is formula of 45 degree marking in beam

  • @ajitshelar6088
    @ajitshelar6088 11 лет назад

    thanks mam .........nice presentation and i understand it very smoothly... I want know about mohar's circle
    is any presentation available of u r own?

  • @sammeri6997
    @sammeri6997 11 лет назад +1

    keep posting similar videos ur presentation is exceptional.Great job.

  • @ladjkaoz
    @ladjkaoz 10 лет назад

    Thanks maria...
    I had underatand beams abit beam better ;)
    Im a mobil DJ and im building a set up to suspend ligting and audio gear. Most gear would be evently distribuited on 3 beams on a Y shape..
    My question is what would be a safe load or max load capacity on this structure...
    The struccture would be suspended front 3 points.. one at each end of the Y
    Hope you can help me..

  • @sunnynagar4179
    @sunnynagar4179 4 года назад

    Mam can you tell us how the beam is in condition to carry load or not or if it is able to take load on it how much of its area will be taking how much load on it and for the slab also

    • @dellpi3911
      @dellpi3911 3 года назад

      ruclips.net/video/fRyUf-GY754/видео.html.

  • @ShahzadKhan-gw2nf
    @ShahzadKhan-gw2nf 5 лет назад

    plz tell me how to find BSR range(Bending strengh ratio)

  • @mailcadone
    @mailcadone 11 лет назад

    Can somebody break down the example calculation steps for both answers 35.4mm and 46.9MPa. Also can't read the value for h; is it 0.8mm denoted in meters?

  • @keithfunnell9852
    @keithfunnell9852 3 года назад

    RSJ gauge installation before bridge approach (?)

  • @alain001
    @alain001 13 лет назад

    @enriqueramosvillafan well, yeah, she skipped the explanation of the integral... but there are general rules about it which you can find in tables.
    it actually just gives you a mm^4 factor which says why the beam breaks at different axis (as if u try to bend the beam normally as shown at around 1:30, or if u try it where u rotate it 90° where u will need much more force to break it (it has more area momentum of inertia..)

  • @jeffreycardasto4325
    @jeffreycardasto4325 10 месяцев назад

    Thankyou for making this simple, i can now understand it. I am a scaffolder and was really curious to understanding the bendingnof the tubes lol😂

  • @m92singh
    @m92singh 12 лет назад +1

    I enjoyed this lecture so much, its unbelievable!! :D

  • @rajupallipparambil4947
    @rajupallipparambil4947 11 лет назад

    nice presentation.your way of presenting with examples is excellent.nice job

  • @RJGonzalez40
    @RJGonzalez40 6 лет назад

    Hi, i would like to work on a project but have a few questions that might be of interest to a few here.
    If im looking to reduce a tube 75 feet long to one inch I know I will need to reduce it to 75 inches.
    How will that apply to pounds.
    For example let say that that pipe can hold 100 pounds , how will I reduce the 100 punds to apply to the for the to apply the reduction for the 75 inch tube?

  • @keithallen6786
    @keithallen6786 8 лет назад

    That was great! So I created something that uses a beam. I ran the numbers on efunda and found that my maximum bending moment stress is 692 MPa. The yield stress for my material (4130 steel alloy) is (gasp!) only 360 MP. So if I understand your video, I should be seeing plastic deformity yet I do not. Is my understanding correct or is the deformity so small that I can't measure it. Thanks again!

    • @JjoshD
      @JjoshD 8 лет назад

      hey if you don't mind, I'd like to hear some more about your beam. are there any more details you could share?

  • @azarudhinharunrajeeth8815
    @azarudhinharunrajeeth8815 7 лет назад

    can u please upload design calculation for g+1building from safe bearing capacity to beam slab columnZ reinforcement detail and design

  • @tarunraina1454
    @tarunraina1454 9 лет назад

    well, if I were to take extra classes on structural analysis, I know who I'd consult, the only problem is, I can't contact you as of yet. But, you did well putting things simply, good job!

  • @MountainNZ
    @MountainNZ 9 лет назад

    I prefer to consider strain in m/m - Yes you can cancel the units but it reminds you what it means. Its a change in length per unit of length

  • @applecider98
    @applecider98 10 лет назад

    does increasing the depth of the beam decrease the deflection?

    • @williematney5385
      @williematney5385 10 лет назад

      Any change in the beams cross sectional area, or shortening it's length, will increase it's strength, and decrease its deflection. By adding to the width, height, or shortening the beam, it will decrease deflection.

    • @jazminecooke7197
      @jazminecooke7197 6 лет назад

      yes

  • @TJamesSisson
    @TJamesSisson 4 года назад

    fantastic, this was the perfect review for me as an ME student thanks!!!

    • @dellpi3911
      @dellpi3911 3 года назад

      ruclips.net/video/fRyUf-GY754/видео.html..

  • @karimkhan1312
    @karimkhan1312 11 лет назад

    i am advocate in india-- i have under stood u r lecture very claerly

  • @Aviator168
    @Aviator168 7 лет назад

    What if one side of the beam if thicker than the other?

  • @miguelgaona2002
    @miguelgaona2002 10 лет назад

    Good explanations that broght me back to college classes times!

  • @shivamsoni5105
    @shivamsoni5105 8 лет назад

    know you are the perfect one ........i don't heard this type of lacture you are best....

  • @das.69
    @das.69 6 лет назад

    Very useful for me as a refresher. Thanks!

  • @shishaygebrelibanos3340
    @shishaygebrelibanos3340 4 года назад +1

    Wow best lecture, keep going dear.

    • @dellpi3911
      @dellpi3911 3 года назад

      ruclips.net/video/fRyUf-GY754/видео.html.

  • @sudhakarpalanivelu4694
    @sudhakarpalanivelu4694 4 года назад

    Excellent explanation !

  • @srinivasaprakashr
    @srinivasaprakashr 3 года назад

    The practical tips given are good. However, writing the stress formula as sigma=Force/Area while the topic is about "Bending of Beams" can mislead the students. In bending of the Euler-Bernoulli beams, the stress calculation is based on the simple bending formula,
    sigma=M*c/I, where:
    M=bending_moment;
    c=maximum_distance_of_the_material point_from_neutral_plane
    I=second_moment_of_are_of_cross_section

  • @kysotope
    @kysotope 4 года назад

    best explanation ever.

  • @egicoc
    @egicoc 12 лет назад

    Muy buen video Señorita y muy buena pronunciación también
    Saludos desde Chile
    Regards!

  • @manojbyna
    @manojbyna 9 лет назад

    Explanation was awesome.
    Useful lecture.

  • @RavjiPindoria
    @RavjiPindoria 11 лет назад +2

    Great presentation. Well done.

  • @networkercity
    @networkercity 11 лет назад

    Excellent presentation! Great job!

  • @sameerquadri8289
    @sameerquadri8289 6 лет назад

    Short and simple informative video.. Thanks

  • @SunilSundar
    @SunilSundar 2 года назад

    Most hollow beams in bending fail by collapse of the walls and compression face. How can this be analyzed predicted?

  • @horiaalbu9306
    @horiaalbu9306 6 лет назад

    You should review the "lever" chapter and in special the necessity to have a point of support, without it you do not have a lever.

  • @wasiqali4138
    @wasiqali4138 9 лет назад

    Ratio 50%, How to calculate the Beam/Built-up/channel/Angle load bearing Strength as per LRFD/EC3/ASD

    • @mathewthomas7616
      @mathewthomas7616 8 лет назад

      +Urs Friend CADD AISI or AA design manual can be a good reference. Consider lateral bucking, local buckling, crippling, shear etc....

  • @chippyjohn1
    @chippyjohn1 8 лет назад +12

    Now I'm ready to build my underground bunker, thanks

    • @parveshminds8994
      @parveshminds8994 7 лет назад +1

      mam at 2.21 of video you have used yield stress and fracture stress
      but its yield strength
      strength and stress are two different things in solid mechanics
      strength can't be calculated it can only be plot by using ashby plots made by cambridge university or
      plot in stress strain diagram by breaking test
      this shows
      MIT university is just overrated what's with number 1 bullshit
      another idiot from mit video
      ruclips.net/video/5uuQ77vAV_U/видео.html
      he doesn't even know
      difference between coagulation and flocculation
      calling Alum as flocculation agent
      ahahahahhahahahha

  • @grady_gran
    @grady_gran 10 лет назад

    very informative and helpful...now i have an idea of what i need to research

  • @geraldfelthammer
    @geraldfelthammer 5 лет назад +1

    Great explanation. I do question the quality of the presentation; I would like to believe that a school as illustrious as MIT would have the budget for a decent camera, lighting and sound. Perhaps a studio? Nonetheless you have done a great job.

  • @MrDoz01
    @MrDoz01 11 лет назад

    Amazing i learned a lot ..btw i think u made a silly mistake for the moment on the rock example...it is force times perpendicular distance from force to calculate moment so the length shown is not right! as the force is shown vertically down

  • @banrath2011
    @banrath2011 10 лет назад +1

    thanks, it's a good lesson for me

  • @cairopm8528
    @cairopm8528 7 лет назад

    really good explanation,thanks wish you all good luck.
    if you have another video or Channel plz.

  • @aqpogi
    @aqpogi 12 лет назад

    Great lecture! plus demonstration thanks :D

  • @veera459
    @veera459 12 лет назад

    Excellent............good presentation

  • @randhirpaswan1036
    @randhirpaswan1036 5 лет назад

    I need more videos of yours please reply the link

  • @gerardvong
    @gerardvong 5 лет назад

    Luv your style easy to follow how to follow you

  • @enriqueramosvillafan
    @enriqueramosvillafan 13 лет назад

    got lost at the area momentum of inertia...

  • @noorulhaq7815
    @noorulhaq7815 6 лет назад

    Mam you got a Fan added to your list tody.
    Thku for such a wonderfull explanation

  • @ورد-ف4ك
    @ورد-ف4ك 2 года назад

    تبارك الله عليك بتوفيق 👌👌🔔👍

  • @niketansharma8708
    @niketansharma8708 8 лет назад

    helped a lot . thanks for making this

  • @gsureshdagal
    @gsureshdagal 11 лет назад

    nice presentation!! expecting more on mechanics.

  • @somnathkarmakar1801
    @somnathkarmakar1801 12 лет назад

    very good teaching technique.

  • @jayakumar5928
    @jayakumar5928 6 лет назад

    How can I find torque for this application ?
    www.dropbox.com/s/f18ls68yiil1iso/image001.png?dl=0
    Specification : Sheet metal 7 mtrs length and 0.5 to 1.1mm thickness

  • @suryapratap2139
    @suryapratap2139 12 лет назад

    excelent ........maria ....clear explnation.

  • @norancho
    @norancho 11 лет назад

    very nice presentation for a layman like myself.

  • @munawarhussain7878
    @munawarhussain7878 7 лет назад

    love your video i wish you could make more videos on building design

  • @elgaro
    @elgaro 9 лет назад

    Excellent video, thanks.

  • @jonathanguzman1694
    @jonathanguzman1694 11 лет назад

    Great presentation, thanks

  • @MrMARCU5
    @MrMARCU5 10 лет назад

    Excellent video.

  • @williematney5385
    @williematney5385 10 лет назад

    Good video, but you might ought to have mentioned safety factor. (1/2 yield or more).

  • @wilsonokaka9723
    @wilsonokaka9723 10 лет назад

    Brilliant! and practical.

  • @franckarnold3503
    @franckarnold3503 3 года назад

    Awesome explanation

    • @dellpi3911
      @dellpi3911 3 года назад

      ruclips.net/video/fRyUf-GY754/видео.html..