Cant Express how easy and fun you have made it for me to understand Chemistry, I have always been strugggling with concepts, Every now and then i end up on your video and have always got satisfied after comprehending the concepts you have explained in a manner that anyone can understand:)
paying thousands of dollars to attend a university just for my professor to assign this free video for us to watch, and then him getting pissed and saying he's overwhelmed w the amount of responsibility and work he has to do :) love that
Just wanted to drop by and thank you for the amazing tutorials you've made for organic chem. You've definitely really helped me and many others grasp different concepts of this subject with such simplicity and ease through your great tutorials. Many thanks prof Dave :D
Thanks!! Explained better than the instructor. However in the last ste, would H2O basic enough to take off the H+ from the alpha H of carbonyl? Isn't is supposed to be OH- instead?
Hi, I added some NaOH+ to my wastewater in order to raise to the pH to 7.0. However, an immediate discolouration of my wastewater occured. I suspect it to be due to aerobic oxidation leading to acetalhyde accumulation that leads to adol condensation. Does the adol condensation produce oligomers and polymers that may cause a darkening of aqueous solution? and am i correct in my thinking?
yikes! out of my wheelhouse. the only thing i can say is that enolate chemistry (aldol, etc.) can indeed lead to polymerization, but i can't say much about pH or color or anything like that.
sometimes you can isolate the addition product, depending on the precise structure, but particularly at higher temperatures elimination is going to be favorable
@@ProfessorDaveExplains Oh thanks, I thought that the aldehyde carbon would have 5 bonds but the double bond to oxygen in the aldehyde would go to oxygen as a lone pair. But I do have one more question, isnt it more favourable for this reaction to form an ester where the formal negatively charged oxygen from the enolate forms a bond to the carbon from the aldehyde? After all the most stable resonance structre of enolate is the one where oxygen has the formal negative charge because it is more electronegative, so why doesnt that happen as opposed to forming a new carbon-carbon bond.
Do these enolate ions with partial charge only occur in water solutions, or is it also possible to find them as solid molecules without water, or are they always part of a larger molecule?
I'm a bit confused coz my textbook says base is used for aldol condensation, and after watching this video I personally also think that using acid makes more sense. So which one is correct??? Thx in advance :D
I was wondering in the second to last step it looks like the negatively charged oxygen takes on two protons to form water. Why does it take on 2 to make water instead of taking on 1 to become an alcohol group.
+Wukeywukey sometimes you can stop at the aldol addition product (alcohol), but because of the entropic favorability of elimination it'll usually go to the condensation product, especially at higher temperatures.
Why do you have -OH2 after work-up? Should it not be -OH followed by base-catalyzed elimination and leaving of the -OH? Because water can leave by itself, no?
could be, but hydroxides won't protonate in basic conditions, that requires acid work up. if i remember correctly, the elimination probably happens during the workup itself, with just the addition happening while in basic conditions. but i'd have to double check!
@@ProfessorDaveExplains you'd have OH after protonating the oxide. The presence of the carbonyl group renders the alpha carbon mildly acid which would allow dehydration to occur
I agree, my book shows OH as the leaving group. Even though OH is considered a "bad" leaving group, the condensation product is conjugated and is the driving force behind the reaction. Plus losing a hydrogen and a water is overall losing H3O. Losing a hydrogen an OH is overall losing H20.
You know your stock is rising in the COVID era professor Dave b/c hundreds of professors are probably making their students watch your videos. Maybe I am one of the professors, maybe not :)
Hi sir...i m preparing fir jee.....coupd to recommened me some bokks for physics, chemistry and maths that would be helpful to me for understanding concepts
can you do a practice problem video for aldol condensation reactions please? I'm going to take my orgo 2 exam on Monday so it won't help me but will surely help other students. Thank you.
abhisao2312 If You don't find any video on one Channel - You should have the basic understanding that you can search ot on youtube instead of begging ! - search *Demjanov reaction Anytime Padhai*
am I the only one that sings along in the intro lmao it's so frickin catchy, I always find myself humming it at random times
branding at its finest!
Professor Dave Explains IM SO HONORED!!! YOU REPLIED!!!
u not the only one ....thats some dope vibe by Dj Dave lol :)
c ram Same here dude 😝
Haha yes😂 I've promoted this channel literally everywhere because the intro is always stuck in my head and I keep singing it...
I was not understanding this at ALL before I watched this video. You are a master of Ochem!
Yes
Cant Express how easy and fun you have made it for me to understand Chemistry, I have always been strugggling with concepts, Every now and then i end up on your video and have always got satisfied after comprehending the concepts you have explained in a manner that anyone can understand:)
paying thousands of dollars to attend a university just for my professor to assign this free video for us to watch, and then him getting pissed and saying he's overwhelmed w the amount of responsibility and work he has to do :) love that
😂
Your explanations are perfect! It's fantastic how simply you illustrate every topic that we would otherwise find challenging to comprehend.
Never knew chemistry involved logic and intuition up until this point
Please NEVER stop making these videos! They're so helpful.
can't stop won't stop don't stop!
Thanks for keeping it short and simple. Other people's videos go off on tangents too often
Incredibly helpful and well delivered! Thank you. Subscribed.
Everytime he says thx "for watching", I am actually the one ending up really greatful, I will definitely send him an e-mail once!
Chemistry exam tomorrow I am so gonna succeed, thanks to you !!!!
My orgo 2 final is in 1 hour. I feel so sad because I will miss visiting your channel every week.
you don't have to stop! there are many other subjects to learn, even if just for fun.
Professor Dave Explains I hope to do biochem next semester! Hopefully it will bring me back here! Thank you so much!!
Helpful for MCAT. Thanks!
Did you already take the MCAT, and if so, how did it go?
this is the best shit ever!!! keep up the good work. I'm definitely telling all my friends about your channel. Thumbs up!!
tell them to pretty please subscribe! woo!
sure sure!
Just wanted to drop by and thank you for the amazing tutorials you've made for organic chem. You've definitely really helped me and many others grasp different concepts of this subject with such simplicity and ease through your great tutorials. Many thanks prof Dave :D
Thank you sir for getting me back on track! I forgot about that final hydrogen deprotonization👌
short, clear and to the point! mcat studying... thank you!
How'd the MCAT go?
Dave, could you have also used the first resonance structure? The anion carbon attacking the carbonyl carbon?
+LT “Chargers” GFX you certainly can.
Chem Jesus!! thank you man. Been following you since organic chemistry one and now that I'm prepping for my mcat I still watch your videos. The best
Thanks!! Explained better than the instructor. However in the last ste, would H2O basic enough to take off the H+ from the alpha H of carbonyl? Isn't is supposed to be OH- instead?
+Jenna Zhang with acidic workup water will do! in acidic conditions water is a base and hydronium is an acid.
+Professor Dave Explains Ohhh right! Acidic condition should never use OH- to deprotonate. I see! Thanks again!!! Very helpful
Wow awesome explanation...gives a thorough knowledge...i also sanged along the intro song...its catching...pls do videos for pg students
He knows a lot about science stuff, Professor Dave explains..di ding ding ding✨
Wow nice video! Really well explained!
why are you so good?
Got The Office vibe! This makes learning even better! :D
U r always great in explaining everything ..thanks a lot
Hi, I added some NaOH+ to my wastewater in order to raise to the pH to 7.0. However, an immediate discolouration of my wastewater occured. I suspect it to be due to aerobic oxidation leading to acetalhyde accumulation that leads to adol condensation. Does the adol condensation produce oligomers and polymers that may cause a darkening of aqueous solution? and am i correct in my thinking?
yikes! out of my wheelhouse. the only thing i can say is that enolate chemistry (aldol, etc.) can indeed lead to polymerization, but i can't say much about pH or color or anything like that.
shouldn't the aldol product be an aldehyde plus alcohol product? Please explain
Please make a video on Cannizzaro reaction!
Why, at the last step, does it not just form an OH-group, why does it form an double bond?
sometimes you can isolate the addition product, depending on the precise structure, but particularly at higher temperatures elimination is going to be favorable
in the aldol addition part, what happens to the hydrogen attached to the end of the aldehyde?
Does it just leave as a proton?
The aldehyde proton? Nothing happens to it.
@@ProfessorDaveExplains Oh thanks, I thought that the aldehyde carbon would have 5 bonds but the double bond to oxygen in the aldehyde would go to oxygen as a lone pair.
But I do have one more question, isnt it more favourable for this reaction to form an ester where the formal negatively charged oxygen from the enolate forms a bond to the carbon from the aldehyde? After all the most stable resonance structre of enolate is the one where oxygen has the formal negative charge because it is more electronegative, so why doesnt that happen as opposed to forming a new carbon-carbon bond.
The lecture is perfect only that the writings tend to block important information down
Do these enolate ions with partial charge only occur in water solutions, or is it also possible to find them as solid molecules without water, or are they always part of a larger molecule?
Excellent explanations
Where did the aldehyde come from? Is that what Aldol condensation is, an aldehyde is necessary I'm assuming for this mechanism?
came from wherever! we can mix anything we want together when we do chemistry. for aldol condensation, you need an aldehyde or ketone.
Professor Dave Explains makes sense! Thank you for responding!
May i know why we don’t use the carbo anion to react further?
I'm a bit confused coz my textbook says base is used for aldol condensation, and after watching this video I personally also think that using acid makes more sense. So which one is correct??? Thx in advance :D
aldol can be done in either basic or acidic conditions, in this clip i show the basic route.
Oic, thanks so much :))
I was wondering in the second to last step it looks like the negatively charged oxygen takes on two protons to form water. Why does it take on 2 to make water instead of taking on 1 to become an alcohol group.
It was too fast for me so this video helped me: ruclips.net/video/q6-FlFW01kM/видео.html
Finally someone asked the question I had in mind!
During acidic workup, why isn't an alcohol simply formed?
+Wukeywukey sometimes you can stop at the aldol addition product (alcohol), but because of the entropic favorability of elimination it'll usually go to the condensation product, especially at higher temperatures.
Professor Dave Explains
Hi, where the proton came from at the end of the reaction, coul'd it be from the water?
yep water is most likely!
thanks!!
Ur explanation works like magic ,thanks . Can I hope to get a video on zener diode voltage regulator,plz.
one month of lectures < your videos
So easy to learn from this!! LOVE LOVE!
Thank you so much for this explanation!
Can you please explain where the second carbonate comes from during the addition? I can't seem to get i.
thanks!
+Nona Hovsepyan carbonate? no carbonates involved. feel free to email with questions!
Wouldn't OH be a good leaving group in basic conditions instead of a formation of a formal positive charge.
absolutely, though we can show the condensation product forming during aqueous acidic workup if we like as well.
Thank you
Hi Sir, why aldol condensation of ketone is difficult than aldehyde?
it's not! both are perfectly feasible. ketones are a little more sterically hindered though, that can sometimes be a factor.
very well explained! makes it possible to study OC of one semester within one week!
thanks from Germany
How did the water form and not OH after the protonation?
H+OH=HOH=H20
Thanks for kindly explaining :)
Why do you have -OH2 after work-up? Should it not be -OH followed by base-catalyzed elimination and leaving of the -OH? Because water can leave by itself, no?
could be, but hydroxides won't protonate in basic conditions, that requires acid work up. if i remember correctly, the elimination probably happens during the workup itself, with just the addition happening while in basic conditions. but i'd have to double check!
@@ProfessorDaveExplains you'd have OH after protonating the oxide. The presence of the carbonyl group renders the alpha carbon mildly acid which would allow dehydration to occur
AAMC MCAT FL3 question 1
Your videos are awesome, you're easy to learn from and explain things well.
Why wouldn't the O- only get protonated once to make an alcohol? What pushes it all the way through to condensation?
thermodynamics! especially if it's hot, elimination is favorable. but it's true, sometimes the addition product can be isolated.
I never get enough of your plad shirts
nice professor
Sir aap yha??????
Thanks
Is Aldolization and aldol condensation the same process?
Can you please explain formation of mesytyline from acetone
Thank you
Synthetic and clear!
Sorry Sir I have an check last result OH group is not present sir
OH. O
| ||
/ \ / \ maybe sir
I agree, my book shows OH as the leaving group. Even though OH is considered a "bad" leaving group, the condensation product is conjugated and is the driving force behind the reaction. Plus losing a hydrogen and a water is overall losing H3O. Losing a hydrogen an OH is overall losing H20.
Thank you professor Subscribed
You know your stock is rising in the COVID era professor Dave b/c hundreds of professors are probably making their students watch your videos. Maybe I am one of the professors, maybe not :)
here the night before my 2nd year orgo2 mid-term
Thank you so much 🙂🙂🙂
Hey professor,I had mailed you a question but you didn't reply?
very helpful and well made video thank you !
What is aqueous acidic workup
from Vietnam with love 😘
i love this channel too but if you think this 5 min video is better than all your lectures lmao it says as much about your class as about prof dave
unbelievable, you r too good
I finally get it... thank you!
If i had prof like this.......
thanx alot..
the reaon of there is no alot of views because of the picture that put in the face of each video..keep going..
Can you upload a video on
all types of aldol condensations,please?
My OC teacher sucks😛
Great video....keep going
THANK YOU SO MUCH. I was reading through my lab protocol and the explanation sounded like an alien language...this helps a lot!
Whats's a PKA?
-log Ka, measurement of acidity
I just wanted to say thank you, and I sincerely hope that I'm not too enolate.
😎
Can you do an Aldol Addition
aldol addition is the first part of aldol condensation, it's in this clip.
Hi sir...i m preparing fir jee.....coupd to recommened me some bokks for physics, chemistry and maths that would be helpful to me for understanding concepts
In case of chemistry pls tell a book from which i can umderstand all exceptions
In case of physics tell me a book which could make be understand all concepts from basics to high level
sorry i'm not sure!
Ok thanks😊
Liked ur all videos...nice
All my friends know about you now
THANK YOU!
Life saver!
You are great !☺😊
"Now, upon aqueous acidic workup..."
Umm, so?
can you do a practice problem video for aldol condensation reactions please? I'm going to take my orgo 2 exam on Monday so it won't help me but will surely help other students. Thank you.
Damn i hate those skelet formulas so much!
no better way of learning chemistry from Jesus himself
im in high school n i have this stuff 😓
go to the mall
Could you please do a video on polymers
in the biochemistry playlist i talk all about polymers! at least biopolymers.
+Professor Dave Explains plz naming reaction demjnov rearrangment
abhisao2312 If You don't find any video on one Channel - You should have the basic understanding that you can search ot on youtube instead of begging ! - search *Demjanov reaction Anytime Padhai*
I hereby declare you jesus of chemistry
U r looking like ranvir kapoor
Thanks so much...
WHY!!!!! He looks like Jesus Christ already plus he helped me !! Oh my lord
In India we learn this Aldol Condensation
In our 12th grade of high school 😂
really!!💯💯
@@s9k328 yes
@@s9k328 you don't learn this in high school?
Thanks you Jesus Christ for explaining
haha sameeeee
Pls explain in tamil 🙏😭😰
What are doing with ypur life bro
Um, I'm a science communicator.
Single handedly saving my organic chemistry grade, I'm not even kidding