does that mean there are 5 moles of H2O2 for every 1 mole of KMnO4? or do I have to go 1 mole of KMnO4 for every 2 moles of MnO4- and then 2 moles of MnO4- for every 5 moles of H2O2?
This is a good question. It's tricky because the equation does not use KMnO4, it uses MnO4-. The ratio of those two is 1 to 1... 1 mol KMnO4 = 1 mol MnO4-. The equation gives you the ratio: 5 mol H2O2 = 2 mol MnO4- We know 1 mol MnO4- = 1 mol KMnO4, which is the same as 2 mol MnO4- = 2 mol KMnO4... So, 5 mol H2O2 = 2 mol MnO4- = 2 mol KMnO4
Good question! The stoichiometric coefficients from the balanced equation give the molar ratio. For example, if you needed the ratio of H+ to MnO4-, it would be 6 H+ to 2 MnO4-.
does that mean there are 5 moles of H2O2 for every 1 mole of KMnO4? or do I have to go 1 mole of KMnO4 for every 2 moles of MnO4- and then 2 moles of MnO4- for every 5 moles of H2O2?
This is a good question. It's tricky because the equation does not use KMnO4, it uses MnO4-. The ratio of those two is 1 to 1... 1 mol KMnO4 = 1 mol MnO4-.
The equation gives you the ratio:
5 mol H2O2 = 2 mol MnO4-
We know 1 mol MnO4- = 1 mol KMnO4, which is the same as
2 mol MnO4- = 2 mol KMnO4...
So, 5 mol H2O2 = 2 mol MnO4- = 2 mol KMnO4
How do you find the molar ratio for that potassium permanganate problem
Good question! The stoichiometric coefficients from the balanced equation give the molar ratio. For example, if you needed the ratio of H+ to MnO4-, it would be 6 H+ to 2 MnO4-.
Thank you
🙏🏼🙏🏼 thank you