Aleks is asking me "dissolved in 350.mL of a 28.0 m M (aq) solution of other compund. Answer is wanted in just M. Does 'm' stand for anything important?
Great question! That little "m" is that same metric prefix (milli) that you are used to seeing attached to other units like mL or mm. You can stick it in front of any unit. And, you can stick any metric prefix in front of M, so you might see nM, kM, cM, etc.
I wish I had found you sooner, ALEKS went from being the worst part of this class to being nothing to stress about. You’re the best, Roxi !!!
Thank you Ashley!! :)
after watching your videos my weekly quiz scores increase A FULL LETTER GRADE. I couldn't thank you enough for these
You are AMAZING!! That's a huge improvement - great job!! Keep up the hard work!
thank you so much, you're literally the only reason i'm passing chem1a
This was the last topic I needed for this semester and it was extremely confusing. This video helped a tremendous amount. Thank you so much!
❤️ you’re welcome!
I got the hard version... thank you Roxi, you are the best!!!
Aleks is asking me "dissolved in 350.mL of a 28.0 m M (aq) solution of other compund. Answer is wanted in just M. Does 'm' stand for anything important?
Great question! That little "m" is that same metric prefix (milli) that you are used to seeing attached to other units like mL or mm. You can stick it in front of any unit. And, you can stick any metric prefix in front of M, so you might see nM, kM, cM, etc.
does the equation have to be balanced when you rewrite the equation for the easier version? if that makes sense
Yes, you always need to balance the chemical equation when you're doing problems like this.
what do we do if the staring equation doesn't produce any reaction? Meaning the products and reactants are all soluble in water?
You would use the same strategy that I describe at about 7 minutes, which I call the “easier” version of the problem.
What do we do if they ask for the final molarity of the cation in the solution but the cation is not involved in the formation of the precipitate?
You would use the same strategy that I describe at about 7 minutes, which I call the “easier” version of the problem.
What if there is no precipitate in the reaction and it's just aqueous aqueous? Thanks : )
You would use the same strategy that I describe at about 7 minutes, which I call the “easier” version of the problem.
@@RoxiHulet okay Thank you!…that was fast tho 😁
Haha, I just happened to be online when you asked! Perfect timing!
What should I do if my reactants are all aqueous?
The reactants are typically all aqueous. Did you mean to ask what you should do if the products are all aqueous?
@@RoxiHulet sorry yes