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*@ **7:24* I'm a bit confused because you said previously that the Br group must have the least number. But in this example, you're counting from the methyl group, why is that? When I counted from the Br group, I got the substituents being 3-chloro and 4- methyl, so the name I got was *1- bromo, 3- chloro- 4 methyl cyclohexane.* Is that name wrong? *@**11:10* could it also be named as *2, 2- chloro methyl propane?* Being that, there is 2 substituents on the same carbon?
For ur first Q it's wrong ... Cause first u hv to be sure that the addition of the numbers in iupac should be least 1 - bromo 3 chloro 4 methyl cyclohexane here it is 1+3+4=8 But correct answer is 4 bromo 2 chloro 1 methyl cyclohexane 4+ 2+1 = 7
8:12 for the question in that timestamp, if we arrange the numbers that way, it becomes in descending order and u said in a previous video that it's better to have the numbers in ascending order after putting them in alpha order.
So when naming these compounds, what is the true priority? You make it sound like it is alphabetization, but then you also make it sound like it's the numbering (increasing)
Actually, when there is a functional group and a multiple bond, you have to prioritize your numbering based on the group first. So the one around 4 mins is actually 2-fluoro-5-hexene
I already failed my 2past exams and tomorrow I got another 1 and I am not finished with my 3 modules because I am overloaded, I hope I will be able to learn in just a short time
Just want to make sure to let people know that they recently changed the naming conventions for a lot of these aromatic and aliphatic compounds. Some of the information that he is teaching is OUTDATED.
I think there is a mistake -- at 7:25 you state that 1,2,4 is the best way to count it, giving the order: 1-methyl-2-chloro-4-bromo. but then at 7:55, you end up just putting it in alphabetical order anyways...
its always going to be in alphabetical order when writing the name, it doesn't matter which number accompanies the substituent when writing the name as you should have established the lowest number group while counting the carbons. So always count the carbons to achieve lowest number groups for substituents THEN put them in alphabetical order for the name.
I don't understand the 3-element style. I thought we're supposed to "count" the elements alphabetically, so shouldn't bromine come first then methyl and then chlorine
I want to ask when there is a double bond and a halogen/methyl group, then do I always name the molecule such that the double bond is at lower position. But I saw in my textbook example like 2-methylhex-3-ene but i think it is 5-methylhex-3-ene as alkene need to be at a lower position
We number it just to give the alkene the lowest number we can get for the alkene. If there are then other groups like in your example and they both have the same number on the alkene, then we look to get the lower number for the groups
I don’t understand something what about complex alkyl Halides like a chloromethyl attached to a parent chain or a 1-chloroethyl how do we name those on parent chains
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he makes it so easy to understand, i feel bad for yall who didnt have these vids ready by april 21 2018, imma need him now as a junior in college
actually my study language is Turkish but I understand it with you better than Turkish. That's amazing. Thank you.
Thank you sir for your clear discussion. I hope I can get high a high grade to my incoming final examination in org chem.
Wow! This is truly amazing. Easier to understand
Literally watch this before a test every time, so good
wow! I'm so loving organic chemistry. used to be scared of it. Thanks man
All this time I was afraid of organic chemistry. Very simple to understand the way he simplifies it.
For naming prioritize like this.....Functional group > bonds > Substituents
Hope this help :) 💜
Love your voice
we do love his voice!
Voice may be good but what about volume? Sorry to say but can hardly hear what is being explained...
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Very much useful in preparing for jee than any other youtuber
Thank you (Fri 18 Dec 2020, 5:54 PM)
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*@ **7:24* I'm a bit confused because you said previously that the Br group must have the least number. But in this example, you're counting from the methyl group, why is that? When I counted from the Br group, I got the substituents being 3-chloro and 4- methyl, so the name I got was *1- bromo, 3- chloro- 4 methyl cyclohexane.* Is that name wrong?
*@**11:10* could it also be named as *2, 2- chloro methyl propane?* Being that, there is 2 substituents on the same carbon?
For ur first Q it's wrong ... Cause first u hv to be sure that the addition of the numbers in iupac should be least
1 - bromo 3 chloro 4 methyl cyclohexane here it is 1+3+4=8
But correct answer is
4 bromo 2 chloro 1 methyl cyclohexane
4+ 2+1 = 7
Thank you so much!
Am gaining a lot of knowledge in organic chemistry 🏃🏿♂️
I respect what you are doing
Thank you for all of your helpful videos! Very much appreciated :)
8:12 for the question in that timestamp, if we arrange the numbers that way, it becomes in descending order and u said in a previous video that it's better to have the numbers in ascending order after putting them in alpha order.
I noticed that too. Looks like a contradiction to me
Yeah that is why maybe I rewinded that one 2 to 3 times
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1:39, can you also call the compound hexyl-2,3-dichloride?
Thanks man you saved my life
شكرا، من العراق بعدروحي
So when naming these compounds, what is the true priority? You make it sound like it is alphabetization, but then you also make it sound like it's the numbering (increasing)
Alphabetization and then ascending number order
Yeah one thing my teacher does is that she writes the priority list side by side when we start any functional group
That's 3 years old tho but searching up online might help
for real🥲
Actually, when there is a functional group and a multiple bond, you have to prioritize your numbering based on the group first. So the one around 4 mins is actually 2-fluoro-5-hexene
Nope F is not a fg its a substituent so he's right
Best Explaination and Helped in building Concepts
This guy is genius 👏
Thanks you so much about it you really help me out about this
Excellent explanation
IDK why or is it me he sounds like daily dose of internet
Thank you sir, splendid explanation.
thank you it is very helpful, satisfied viewer :)
I really like the video very much
Easy language and understandable
Really thanks a lot
Isn't it 1-br-3-cl-4CH3 ???8:00
That's what I noticed too. Alky halides> alkanes, halides should have the lowest number...
I already failed my 2past exams and tomorrow I got another 1 and I am not finished with my 3 modules because I am overloaded, I hope I will be able to learn in just a short time
Awesome...sir ...well done 👍
3:51 don’t we go numbering in an order such that the functional group gets least number?
Alkenes have a higher priority than halogens
8:07 there is a prolem with namin that compound i cecked google and the answer was 1 bromo 3 chloro 4 methyl cycloexane.
Exactly halogens have a higher priority than methyl group
I had problem in that one too, I opted for that iupac name but the lecturer in this video did otherwise
thanks for sharing such superb job
Did you graduate?
Great video sir
I dont get the tert-butyl part.. why is it named like that? is there a system of names provided or what? please respond
that is the accepted common name, the true IUPAC name is 1,1-dimethylethyl. my professor accepts either
Just want to make sure to let people know that they recently changed the naming conventions for a lot of these aromatic and aliphatic compounds. Some of the information that he is teaching is OUTDATED.
Solve 1-iodo 3-methyl benzene
Thank you once again.
I understand this! Wow! I am amazed.
I think there is a mistake -- at 7:25 you state that 1,2,4 is the best way to count it, giving the order: 1-methyl-2-chloro-4-bromo. but then at 7:55, you end up just putting it in alphabetical order anyways...
Best way to count to reduce the overall sum of the numbers used, but doesn't affect the alphabetical order
its always going to be in alphabetical order when writing the name, it doesn't matter which number accompanies the substituent when writing the name as you should have established the lowest number group while counting the carbons. So always count the carbons to achieve lowest number groups for substituents THEN put them in alphabetical order for the name.
رحمه الله والديك
I like the way u say I odo n.n
God Bless you man
I dont even know how to identify whether it's alkyl n why and how it's drawn like this
plz explain me about Avogadro's number.....
i think now you're much better than 2yrs ago huh? u must be some master about OC ??
"iodo" sounds funny 🤣🤣🤣
Damn right it is hahaha
what if ethylbromide or methylbromide is a substituent of the longest chain
Which one do we prioritise?? A multiple bond or a func. Grp ?
a multiple bond must have the lower number!
you are the best
I always called them halogenoalkanes (as that is the name the compounds were given in my allocated textbook)
I don't understand the 3-element style. I thought we're supposed to "count" the elements alphabetically, so shouldn't bromine come first then methyl and then chlorine
should be lower number since starting with bromine would give 1,3,4 unlike with methyl which would give you 1,2,4
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I want to ask when there is a double bond and a halogen/methyl group, then do I always name the molecule such that the double bond is at lower position. But I saw in my textbook example like 2-methylhex-3-ene but i think it is 5-methylhex-3-ene as alkene need to be at a lower position
We number it just to give the alkene the lowest number we can get for the alkene. If there are then other groups like in your example and they both have the same number on the alkene, then we look to get the lower number for the groups
Easy to understand
Thank you, sir!
هسه لو اني اجنبي مو احسن
العراق العظيم اوووف🇮🇶
Plz explain me about Quantitative chemical Analysis
I bet now ur master in it!!
I don’t understand something what about complex alkyl Halides like a chloromethyl attached to a parent chain or a 1-chloroethyl how do we name those on parent chains
Thank you❤
Thanks
Thank you!
thank you
First halogen fir methyl group
thank you sir🤍
Thanku 😊
2:03
2 - bromo - 4 - chloro pentane bcus of the alphabetical order.
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2:57
8:11
Who gives this a thumbs down?
Omg thankss🤩🤩
I wish my lecturers are like you
2.3Di Chlorohexane
What a god.
Nicc
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kissing and i hope they caught us whether they like or not
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Thanks