A born “great teacher and communicator”. I’m brand new to aviation, but I know that “words mean things” and mental images are golden. You anticipate follow-up questions extremely well because you actually put yourself in the shoes of us who are FAR LESS experienced. Great job.
Although the altitude I got seems not right, but this is my thought. The change in altitude means the change in pressure so we work out the difference between the standard atmosphere pressure and 0.001(which is 0.1 percent) of standard atmosphere pressure, so 1013.25-(1013.25 x 0.001)=1012.24 hpa. ''And every increase of 1 feet the pressure gone to drop by about 1 hpa'' quote from the videos, so I use 1012.24 x 30 and I got 30367 feet which doesn't seems right.
Thankyou mentour pilot so much for everything you have done! Also Thankyou so much for inspiring me and showing me new stuffs about aviation. I’m currently taking PPL licence and finished my RPL and I am hoping to finish my CPL as soon as possible so I could go to my favourite airline Cathay Pacific!Also when I was at school people laughed at me on what I want to be! So right now everybody don’t listen to you those people if they had laughed at you or bullied you on what you want to be! Remember that that’s not there dream that’s yours and you should stand for it and succeed! Thankyou again mentour pilot for everything you’ve done! Hope to see more of your vids!!
A question of a complete novice: Wouldn' t it be possible to use a system based on GPS and GLOSNASS or something like that for determing the height above sealevel ? I guess the inaccuracy of GPS could be solved with the conjunction of GLOSNASS data.
Der Ben - I was also going to ask ‘why not use GPS?’ but (from memory) my starting point was GPS determination of height is even more accurate than it is for position on the ground and unaffected by local weather. Perhaps coverage at places like the poles isn’t sufficient for aviation, or just the old chestnut of ‘change anything on this plane and it will need total recertification’.
GPS is inaccurate because of the military use and above specific height, it turns off in a case for it not to be used in ballistic missiles. GPS is military technology and a public one is done in this way to prevent military usage. hope it helps. ps. To my knowledge, military planes are using GPS system instead of hP.
Considering the pressure of the earth to be at sea level i.e. 760 mm of Hg or 101.325 kPa. So in order to feel 0.1% of this pressure we need to be at the Karman Line(at 100,000 m) and the pressure at this level would be 101 Pa or. 76 mm of Hg.
I would think there is more than one on board the aircraft. I know that the local airport here has 6 barometric pressure sensors, to ensure they always have the latest pressure reading available.
Hi my answer to the question is approximately 99900 meters it should be a bit more than that as I used approximations like density of air=1 and pressure at earth's surface is 1 atm = 10^6 pa and g= 10 m/s^2 I used the formula P2-P1 = hdg Where P1 is pressure on earth's surface, P2 = 0,1% P1, h is height, d is density of air and g is gravitational acceleration.
Actually it is wrong... because density of the air depend of the altitude, and temperature also. That is why aircraft can`t reach edge of space. They can`t reach enough speed and in low density air they stall.
@@shreyasjoshi5487 when the air is too rarifyied the plane couldn't get enough lift to hold itself in the air. So it would stall* *(fall off the sky like a piano)
Where is my mistake X altitude with 10.1325 hpa 30 feet climbing 1 hpa less 1013,25 hpa standard 100 Ft = 1013,25hpa X Ft = 10,1325 (1013,25 hpa - x *30) = 10,1325hpa 1013,25 = x*30 + 10,1325 1013,25 - 10,1325 = x*30 (1013,25 - 10,1325)/30 = x X = 33437 ft Here im reading about 100km (which without transitioning I know is way more Than my feet...), so what other equations are out there for this?
So I am getting wrong results but I don't know why, here are my findings Capitan: 1 hPA = 30 ft QNE = 1013 0.1% of QNE = 1.0130000000000001 hPA 1013 / 1.0130000000000001 = 1000 1000hPA x 30f/hPA = 98425.197 Foots 30000 Meters As I know the highest possible FL for a commercial plane is FL450 and the only plane which can achieve this is Boeing 747-400
The pressure decrease with increasing altitude is linear only for small changes in altitude. A much better description is an exponential function, where pressure decreases by 50% for every 18,000 feet (approximately) of increased altitude. So at 36,000 feet, the pressure is 50% of 50% which is 25% of sea level pressure. You can see why this is the case from what you learned in your physics classes. Whatever your height, every square centimeter of horizontal area is supporting all the air above in a 1 centimeter square column. So as you descend, the air pressure increases exponentially, doubling for every 18,000 feet you descend. This happens because there is more weight of air to support as you descend. (The numbers change a little bit with air temperature and weather fronts. Also the temperature of the atmosphere increases above a certain height, which complicates things.) If our altitude is 180,000 feet, that is 10 times 18,000 feet. Using our simple exponential model, the pressure is 2^-10 or 1/1024 or about 0.1% of sea level pressure. (NASA commonly defines the atmospheric entry altitude as 250,000 feet, so this isn’t far off.) Wikipedia has complete formulas and background information. For example, Google “wikipedia barometric formula” or “wikipedia altimeter”. Per Wikipedia, an aircraft altimeter displays height as the logarithm of the air pressure, following the equation z = c T log(P/Po) where z = height, c = a constant, T = absolute temperature, P = measured pressure, and Po = sea level pressure.
9 apr 2020 7:53 pm edt:thanks 10 apr 2020 12:8 pm edt: so flight-information-tv for aircraft-passenger which says 'altitude .... feet', is not accurate during flying above earth-surface which has different-altitude than departure-airport-altitude. 10 apr 2020 12:28 pm edt: 7:17 standard-qnh-setting 1013.25 hpa 7:59 following atc to climb to fL200 using qnh-setting 1013.25 hpa 8:18 1 flight-level = 1000 feet
0,1% linear decrease of 1013 hPascal 30feet = 1 hPascal 0,001 * 1013= 1,013 = delta is 1012 hPascal 30 feet * 1012 hPascal = 30360 feet = 9,25 km Ok obviously not right. :D Ok, 1 atm is not 1013 hPascal, it's 1013,25 kPascal 30 * 10120000 Pascal = 303600000 feet = 92537 km which is my final answer. :)
Is it 30419.5 ft? (I'm bad in maths) 0.1% of 1015= 1.015 hpa so got difference of 1013.985, then tried to relate 1 hpa = 30 ft We have pressure difference of 1013.985 then multiplied by 30 so 30419
If anyonee is looking for a great, greatest, humble & the best pilot instructor HERE ( METOR PILOT) because if you're going to school, the school is all about the money, in the some instructors are there for the 2 hrs by the time they get ready 1/2 hr passed, you learned 1 1/2 & some have attitude, too busy for questions or think they are it & yet you payed 400$. With mentor in 1 video you feel you're almost ready to fly. Mentor pilot may God be with you. Have always an awesome day
At sea level the standard pressure Po=101.3kPa. 1% of sea pressure is on altutude 16000 meter above the sea 0.1 % of sea pressure is on 30000 m above sea level. I'm not sure that pressure drops in linear manner with rise of altitude. accorging to elementar physics P=F/A=mg/A=V*rho*g/A=h*rho*g. The problem is that density varies with change in height. I think that the aircraft has static pressure gage and additional there is Pito tube for dynamic pressure measurements.
pythagorean theory. You are on a particular angle (flying diaganal) this would represtent the degree angle of "C" (hypotenuse) relative to "B" (earth surface) in the pythagorean theory. this is not enough information , you will need to know the distance from surface to atmosphere edge. (or use some other mathmatical knowledge I don't have) The Problem, as I see it, is knowing the exact distance from earths surface to the edge of the atmosphere seeing that the earths surface changes all the time.... This is definatly a thinker....
Hi fellow 737 pilot:) The question You asked is a little bit off I think. A much better definition where space begins and the atmosphere ends is given by T. Karman. He suggested that space begins at an altitude where an object has to go faster than the first orbital speed to maintain aerodynamic lift. So basically the edge of space is an altitude where you have to travel at orbital speed to maintain your altitude, no matter what shape your spacecraft is:)
0.1% air pressure versus at sea level is essentially zero air pressure. If every 30 feet you lose one hectopascal and the standard is 1,013 hp, then 30 feet times losing all pressure is about 30,000 feet. But that certainly is not the edge of space. My guess is 30 feet per one hectopascal in change of atmospheric pressure is true only for the more limited functional range of commercial aircraft altitude and not for the full extent of Earth atmosphere up to the beginning of space.
Is US Standard measurements converted to metric when flying between the USA and most of the rest of the world? What is distance measured in? And speed?
i just spent a few minutes finding out what qnh is. it's not 'quacking nut hammer', or queer new hampshire. Found it in wikipedia. it could have been included in this video
The Karman line, lies at an altitude of 100 km (62 mi; 330,000 ft) above Earth's sea level and commonly represents the boundary between Earth's atmosphere and outer space.
If you fly straight and level from the American east coast at a height of 1000 feet above sea level to the coast of Africa, maintaining level flight, will your height be 1000 feet above sea level over the sea at the coast of Africa?
0,1% of the 1 atmosphere is at almost 50 000 m and I think a plane can fly only at around 15 000 m because of the density of the air which is not creating lift anymore
I tried to calculate it. 0,1 % of the pressure on earth. Well I calculated for 1014 Hpa: 1014 - (1014 * 0.01) = 1014 - 1,014 = 1012,986; then 1012,986 * 30 (30 ft per 1 Hp) = 30389 Ft. For 1030 Hpa the result would be 30869ft. A general form for every pressure in Hpa on ground: 29,97 * P = altitude in Ft for the edge of space. However I could not find the solution on the given link. Did anyone find the correct answer? I am not sure if I am correct. I expected the edge of space the be way above todays normal airliners..
Understood. Thank you! Seems like, at least when landing, AGL is very important. Do planes measure AGL? My car beeps when close to objects. Why no radar to measure distance to the ground? Also, all that manual entering of QNH seems to have lots of chances for human error.
Watching the videos, not, but playing x-plane, yes, it seems. (I just got it for private fun and general interest in the matter, but if you connect certain precision hardware to the program, you can actually use it for some certifications. At least that is what they say there) PS: @Mentour pilot: great channel!
Nach den penciled Berechnungen; der Rand des Weltraums sollte sich in einer Höhe von ungefähr 100 km über dem Meeresspiegel der Erde befinden. Ist das korrekt?
Great video as always! Very easy to watch and comprehend. On a somewhat unrelated note, as someone going into the rail industry, it can make me a bit uncomfortable when I fly a route that could be done by rail but for whatever reason I need to fly. Do pilots have a similar experience when traveling by train/bus/whatever?
Fighter Jets have Radio Altimeters that work in a more efficient and fundamentally different way. This is because how rapidly a combat plane changes vector. Not an expert, but I feel it is about time commercial planes adopt the same system, reduce scope for human error and free up the pilot. Also, funny to imagine a fighter pilot having to set and reset the QNH the whole damn time in his pressure altimeter.
Hi, one question. I'm currently contemplating on deciding if I should get a tattoo or not, especially because I plan to taken on the career of a pilot. Would it be a bad idea to get a tattoo on my forearm, from elbow down to my wrist? Or would airline be okay with it?
First of all Thanks for your great content ! I am so curious and realy disturbed by one simple question ; the static port is just a hole located on the fuse surface , hence there is an air stream right over the surface - which means that there is an air velocity that affects the pressure right on the closest layer over a given surface ( as speed grows the pressure drops , Bernuli principle isn't...). So my question is as follows : is a static port actually affected by airplane speed and does a pressure realy varies due to this? If yes , how this should be considered when altitude measured. If no, please explain the phenomina - how this can be eleminated ( in my understanding it violates the bernulli principle ).... Thanks a lot , anyone who will be able to clarify that interesting point for me, is very welcomed to reply !
Hi, static and dynamic pressure are two parts of overall pressure in the Bernoulli equation. As the static port is on the side of the fuselage, the velocity of the air should be perpendicular to it and as a result there should be zero velocity at the reading point. This is also helped by the fact that at the surface there should be zero velocity anyway due to the boundary layer.
i was thinking that in this day & age that they would come up with a more sophisticated form of navigation than VOR - like maybe upgrade it or replace it with something else
mentour have got ear block while decending from high altitude to low altitude thank you for your last reply to me !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Sorry Mentour I didn't sign up at brilliant but surely it depends on where you are above the earth just like your altimeter? When i need to worry about that perhaps i'd better sign up 😊
I'm a skydiver and have one of my many altimeters sitting just under my computer monitor. I zeroed it out on a day when the local pressure was the same as the altitude of the local area. I now use it to see what the weather is doing. Right now it is showing a +500 feet in altitude. So we have a low pressure system moving through, and the MASSIVE thunder storms to prove it. lol By keeping an eye on it I can get hours notice of storms moving through. And by seeing how fast it is changing can tell how severe it may get. So just another use for an old altimeter.
GPS is inaccurate because of the military use and above specific height, it turns off in a case for it not to be used in ballistic missiles. GPS is military technology and a public one is done in this way to prevent military usage. hope it helps. ps. To my knowledge, military planes are using GPS system instead of hP.
Wanard all civilian airplanes use GPS as their main navigation system. GPS only shuts off at 70,000 feet, far above the cruising altitude of a commercial airliner. There is actually an altitude reading on the nav display, but it is unreliable due to slow update times, even though it is actually very accurate due to the military-grade GPS reciever on board the plane, but there is no way to increse update time because the satellites ping their data at predetermined intervals. It is only used as backup if the radio altimeter fails on final approach.
I like math... The answer seems a bit on the low side, but other chocolate than that, I cannot make... (Dutch expression) LOL Ground level = 1013,25 hPa, the maximum height = 0,1% of 1013,25 = 1,01325 hPa. The difference = 1012,23675 hPa. The altitude to climb to would be 1012,23675 x 30ft (per 1 hPa) = 30367,1025 feet.
![Cody Johnson - I'm Gonna Love You (with Carrie Underwood) [Official Music Video]](http://i.ytimg.com/vi/yy9PuYMU29g/mqdefault.jpg)
He explains better than my flight instructor
Haha, thank you!
Thanks for doing what you're doing, we appreciate it very much. Keep on the good work 👍👍
same for me, mine is xp11 flight school.
Ha!
Maybe because he IS a flight instructor as well! But you know, big boy planes
You, Captain Joe and Sully Sullenberger are my inspirations. Thanks for the videos. 😁
A born “great teacher and communicator”. I’m brand new to aviation, but I know that “words mean things” and mental images are golden. You anticipate follow-up questions extremely well because you actually put yourself in the shoes of us who are FAR LESS experienced. Great job.
Although the altitude I got seems not right, but this is my thought. The change in altitude means the change in pressure so we work out the difference between the standard atmosphere pressure and 0.001(which is 0.1 percent) of standard atmosphere pressure, so 1013.25-(1013.25 x 0.001)=1012.24 hpa. ''And every increase of 1 feet the pressure gone to drop by about 1 hpa'' quote from the videos, so I use 1012.24 x 30 and I got 30367 feet which doesn't seems right.
Thankyou mentour pilot so much for everything you have done! Also Thankyou so much for inspiring me and showing me new stuffs about aviation. I’m currently taking PPL licence and finished my RPL and I am hoping to finish my CPL as soon as possible so I could go to my favourite airline Cathay Pacific!Also when I was at school people laughed at me on what I want to be! So right now everybody don’t listen to you those people if they had laughed at you or bullied you on what you want to be! Remember that that’s not there dream that’s yours and you should stand for it and succeed! Thankyou again mentour pilot for everything you’ve done! Hope to see more of your vids!!
Drones media wow! Good luck on your trainings!
I love the 400Hz whine in the background.
I spotted the MATLAB figure "peaks" :) Very nice! Also: Very good explanation. Thank you!
Almost 100k... Congratulations Peter
Thank you, soon my friend.
The Karmin line which is at 100 km.
Great! Check out the link to learn how to calculate it.
karmen line*
hannes torstensson *Kármán.
It's Carmel line guys
Little Cessnas also have static ports outside?
Yes.
Okay, thanks!
Alvaro Cifuentes yes and a tiny propeller, if you time it right, it will defy the laws of gravity🛫
Silver Play button on its way. Happy flying mate :)
Thank you! Yes, it’s close now.
Another great video Mentour. You are like captain Sullenberger but youtube one! The content you giving is amazing! Much respect for YOU!
I love these videos, thank you for the time and effort
Love it when you do your vids in the cockpit! Keep it up Cpt! God (tidlig) helg!
I do my best but it’s not always possible.
Oh yeah, thats understandable. :)
I loves the video which was shot in an aircraft toilet... discussing why there is an ashtray when you are not permitted to smoke on board.
This is one of your best technical videos!
Could you also talk in detail about pitot tubes next?
Extremely informative video as always. Excellent! Many thanks for the videos......👍
Thanks! Glad you liked it!
A question of a complete novice: Wouldn' t it be possible to use a system based on GPS and GLOSNASS or something like that for determing the height above sealevel ? I guess the inaccuracy of GPS could be solved with the conjunction of GLOSNASS data.
Der Ben - I was also going to ask ‘why not use GPS?’ but (from memory) my starting point was GPS determination of height is even more accurate than it is for position on the ground and unaffected by local weather. Perhaps coverage at places like the poles isn’t sufficient for aviation, or just the old chestnut of ‘change anything on this plane and it will need total recertification’.
GPS is inaccurate because of the military use and above specific height, it turns off in a case for it not to be used in ballistic missiles. GPS is military technology and a public one is done in this way to prevent military usage. hope it helps. ps. To my knowledge, military planes are using GPS system instead of hP.
Considering the pressure of the earth to be at sea level i.e. 760 mm of Hg or 101.325 kPa.
So in order to feel 0.1% of this pressure we need to be at the Karman Line(at 100,000 m) and the pressure at this level would be 101 Pa or. 76 mm of Hg.
Wow I love this guy
I wish I can have an instructor like him
What would happen if the altimeter broke mid flight? Is there a contingency for the pilots to gauge their elevation?
I would think there is more than one on board the aircraft. I know that the local airport here has 6 barometric pressure sensors, to ensure they always have the latest pressure reading available.
Hi my answer to the question is approximately 99900 meters it should be a bit more than that as I used approximations like density of air=1 and pressure at earth's surface is 1 atm = 10^6 pa and g= 10 m/s^2
I used the formula P2-P1 = hdg
Where P1 is pressure on earth's surface, P2 = 0,1% P1, h is height, d is density of air and g is gravitational acceleration.
Check out the link to see the correct answer! Good work
It's correct, well difference of 1 Km but that is because of approximations, thank you
Actually it is wrong... because density of the air depend of the altitude, and temperature also. That is why aircraft can`t reach edge of space. They can`t reach enough speed and in low density air they stall.
Haraiala Remus ok, you mean that I cannot take density as 1 because it is varying, correct ?
@@shreyasjoshi5487 when the air is too rarifyied the plane couldn't get enough lift to hold itself in the air.
So it would stall*
*(fall off the sky like a piano)
I was waiting for this video for a long time thanks mentor.
I hope you liked it!
Mentour Pilot of course I did
Where is my mistake
X altitude with 10.1325 hpa
30 feet climbing 1 hpa less
1013,25 hpa standard
100 Ft = 1013,25hpa
X Ft = 10,1325
(1013,25 hpa - x *30) = 10,1325hpa
1013,25 = x*30 + 10,1325
1013,25 - 10,1325 = x*30
(1013,25 - 10,1325)/30 = x
X = 33437 ft
Here im reading about 100km (which without transitioning I know is way more Than my feet...), so what other equations are out there for this?
Looks like you calculated it for 1% pressure instead of 0.1% pressure, which is why you ended up off by a factor of 10.
So I am getting wrong results but I don't know why, here are my findings Capitan:
1 hPA = 30 ft
QNE = 1013
0.1% of QNE = 1.0130000000000001 hPA
1013 / 1.0130000000000001 = 1000
1000hPA x 30f/hPA = 98425.197 Foots
30000 Meters
As I know the highest possible FL for a commercial plane is FL450 and the only plane which can achieve this is Boeing 747-400
The pressure decrease with increasing altitude is linear only for small changes in altitude.
A much better description is an exponential function, where pressure decreases by 50% for every 18,000 feet (approximately) of increased altitude.
So at 36,000 feet, the pressure is 50% of 50% which is 25% of sea level pressure.
You can see why this is the case from what you learned in your physics classes.
Whatever your height, every square centimeter of horizontal area is supporting all the air above in a 1 centimeter square column.
So as you descend, the air pressure increases exponentially, doubling for every 18,000 feet you descend.
This happens because there is more weight of air to support as you descend.
(The numbers change a little bit with air temperature and weather fronts.
Also the temperature of the atmosphere increases above a certain height, which complicates things.)
If our altitude is 180,000 feet, that is 10 times 18,000 feet.
Using our simple exponential model, the pressure is 2^-10 or 1/1024 or about 0.1% of sea level pressure.
(NASA commonly defines the atmospheric entry altitude as 250,000 feet, so this isn’t far off.)
Wikipedia has complete formulas and background information.
For example, Google “wikipedia barometric formula” or “wikipedia altimeter”.
Per Wikipedia, an aircraft altimeter displays height as the logarithm of the air pressure, following the equation
z = c T log(P/Po)
where z = height, c = a constant, T = absolute temperature, P = measured pressure, and Po = sea level pressure.
Really interesting video. You are quite skilled at explaining technical things. Keep it up!
9 apr 2020 7:53 pm edt:thanks
10 apr 2020 12:8 pm edt:
so flight-information-tv for aircraft-passenger which says 'altitude .... feet', is not accurate during flying above earth-surface which has different-altitude than departure-airport-altitude.
10 apr 2020 12:28 pm edt:
7:17 standard-qnh-setting 1013.25 hpa
7:59 following atc to climb to fL200 using qnh-setting 1013.25 hpa
8:18 1 flight-level = 1000 feet
0,1% linear decrease of 1013 hPascal
30feet = 1 hPascal
0,001 * 1013= 1,013 = delta is 1012 hPascal
30 feet * 1012 hPascal = 30360 feet = 9,25 km
Ok obviously not right. :D
Ok, 1 atm is not 1013 hPascal, it's 1013,25 kPascal
30 * 10120000 Pascal = 303600000 feet = 92537 km which is my final answer. :)
Is it 30419.5 ft? (I'm bad in maths) 0.1% of 1015= 1.015 hpa so got difference of 1013.985, then tried to relate 1 hpa = 30 ft
We have pressure difference of 1013.985 then multiplied by 30 so 30419
Why don’t these aircraft use GPS readings for altitude?
You are a pro! Thanks so much this helped a lot. 👍🏻✈😎
If anyonee is looking for a great, greatest, humble & the best pilot instructor HERE ( METOR PILOT) because if you're going to school, the school is all about the money, in the some instructors are there for the 2 hrs by the time they get ready 1/2 hr passed, you learned 1 1/2 & some have attitude, too busy for questions or think they are it & yet you payed 400$.
With mentor in 1 video you feel you're almost ready to fly. Mentor pilot may God be with you. Have always an awesome day
At sea level the standard pressure Po=101.3kPa. 1% of sea pressure is on altutude 16000 meter above the sea 0.1 % of sea pressure is on 30000 m above sea level. I'm not sure that pressure drops in linear manner with rise of altitude. accorging to elementar physics P=F/A=mg/A=V*rho*g/A=h*rho*g. The problem is that density varies with change in height. I think that the aircraft has static pressure gage and additional there is Pito tube for dynamic pressure measurements.
Sir if you upload such type of videos surely in no time you are gonna hit 1million subscribers
pythagorean theory. You are on a particular angle (flying diaganal) this would represtent the degree angle of "C" (hypotenuse) relative to "B" (earth surface) in the pythagorean theory. this is not enough information , you will need to know the distance from surface to atmosphere edge. (or use some other mathmatical knowledge I don't have) The Problem, as I see it, is knowing the exact distance from earths surface to the edge of the atmosphere seeing that the earths surface changes all the time.... This is definatly a thinker....
Lucky you, get to fly a Boeing 737 NG for a living, thanks for the video
It's not luck! :) It takes work and perseverance to get there.
Hi fellow 737 pilot:)
The question You asked is a little bit off I think. A much better definition where space begins and the atmosphere ends is given by T. Karman. He suggested that space begins at an altitude where an object has to go faster than the first orbital speed to maintain aerodynamic lift. So basically the edge of space is an altitude where you have to travel at orbital speed to maintain your altitude, no matter what shape your spacecraft is:)
gps triangulation with satellites will ever help in calculating altitude?
0.1% air pressure versus at sea level is essentially zero air pressure. If every 30 feet you lose one hectopascal and the standard is 1,013 hp, then 30 feet times losing all pressure is about 30,000 feet. But that certainly is not the edge of space. My guess is 30 feet per one hectopascal in change of atmospheric pressure is true only for the more limited functional range of commercial aircraft altitude and not for the full extent of Earth atmosphere up to the beginning of space.
what about QNE sir? ATC says QNH standard or QNE while communicating?
Thank you very much
The answer I got is 240,000 ft which is 73 kms. Can anyone correct me if I'm wrong
why aircraft manufacturng companies don't use GPS for this porpouse?
Is US Standard measurements converted to metric when flying between the USA and most of the rest of the world? What is distance measured in? And speed?
why americans think that SI unit are european way? is not just EUROPE who use it, is all the whole world but they
I would be so grateful, if you do a video about performance of 737 or performance calculations.
As always I hope, you are doing absolutly fantastic ;)
Thank you! I will see what I can do.
i just spent a few minutes finding out what qnh is. it's not 'quacking nut hammer', or queer new hampshire. Found it in wikipedia. it could have been included in this video
The Karman line, lies at an altitude of 100 km (62 mi; 330,000 ft) above Earth's sea level and commonly represents the boundary between Earth's atmosphere and outer space.
If you fly straight and level from the American east coast at a height of 1000 feet above sea level to the coast of Africa, maintaining level flight, will your height be 1000 feet above sea level over the sea at the coast of Africa?
Looks like they would have a laser or some kind of active Ping, or gps to get your height now days. He prob mentioned that.
Is it 30,367.1025 ft.? Many thanks. Terry.
100km is the Karmen line which is where anything above that is considered “space”
It's 2021 Captain.
It's about time to start using (lidar) for elevation readings.
What say you.....?
Well, it’s not that useful to have a terrain height reading at altitude. We need common reference to separate each other
I love em, he explain so sweet.
0,1% of the 1 atmosphere is at almost 50 000 m and I think a plane can fly only at around 15 000 m because of the density of the air which is not creating lift anymore
I tried to calculate it. 0,1 % of the pressure on earth. Well I calculated for 1014 Hpa: 1014 - (1014 * 0.01) = 1014 - 1,014 = 1012,986; then 1012,986 * 30 (30 ft per 1 Hp) = 30389 Ft. For 1030 Hpa the result would be 30869ft. A general form for every pressure in Hpa on ground: 29,97 * P = altitude in Ft for the edge of space. However I could not find the solution on the given link. Did anyone find the correct answer? I am not sure if I am correct. I expected the edge of space the be way above todays normal airliners..
Always wondered... 👍 lol logical n simple... man aviation is so cool..
We truly have stood on the shoulders of giants 🌹
105km height from the surface of the earth
Thanks. I'm trying ATC and this was a great introduction.
Hope you were able to complete it
Ever FL=1000feets, then FL 200 means 200,000 feet. How does it be 20,000feet?? ..
How how many instruments on this plane use only pressure gauges not electrical gauges
Why is there jet fuel smell in the cabin after engine start???
ISA means 1013.25 hPa 15°C. Not the 1013 hPa as You say.
Understood. Thank you! Seems like, at least when landing, AGL is very important. Do planes measure AGL? My car beeps when close to objects. Why no radar to measure distance to the ground? Also, all that manual entering of QNH seems to have lots of chances for human error.
Radio altimeter??? Does that read AGL?
Great video!
Enjoyed the video, very well explained.
Thanks for the video.can any one post the method of calculation though...cant access the link.
So, if I watch these whole series of videos, does this count towards my certification as a commercial airline pilot?
Hahaha. No not yet.
Watching the videos, not, but playing x-plane, yes, it seems.
(I just got it for private fun and general interest in the matter, but if you connect certain precision hardware to the program, you can actually use it for some certifications. At least that is what they say there)
PS: @Mentour pilot: great channel!
No but it’ll help with your theory exams.
Nach den penciled Berechnungen; der Rand des Weltraums sollte sich in einer Höhe von ungefähr 100 km über dem Meeresspiegel der Erde befinden. Ist das korrekt?
Great video as always! Very easy to watch and comprehend. On a somewhat unrelated note, as someone going into the rail industry, it can make me a bit uncomfortable when I fly a route that could be done by rail but for whatever reason I need to fly. Do pilots have a similar experience when traveling by train/bus/whatever?
No, I really enjoy the comfort of trains. It’s the speed Im after.
Thanks a lot. I understand much better now.
Fighter Jets have Radio Altimeters that work in a more efficient and fundamentally different way. This is because how rapidly a combat plane changes vector. Not an expert, but I feel it is about time commercial planes adopt the same system, reduce scope for human error and free up the pilot. Also, funny to imagine a fighter pilot having to set and reset the QNH the whole damn time in his pressure altimeter.
Well explained, Mentour! Please, do more videos like this one :)
Hi, one question. I'm currently contemplating on deciding if I should get a tattoo or not, especially because I plan to taken on the career of a pilot. Would it be a bad idea to get a tattoo on my forearm, from elbow down to my wrist? Or would airline be okay with it?
I have made a video on that topic. Check it out!
Excellent explanation. Thank you.
Answer to the problem is 911013.1ft
“What IS interesting is making sure we aren’t gonna run into anyone else.”
If you are on the ground at the Dead Sea in Israel, does the altimeter show 98760 feet??? (-1240 MSL)
Aimless6 No, the Altimeter shows -1240 if you have the correct pressure setting.
Is that pilot on the thumbnail supposed to be you? :D
Jesus Christ 🙏
God With Us ✞
John 3:16
First of all Thanks for your great content !
I am so curious and realy disturbed by one simple question ; the static port is just a hole located on the fuse surface , hence there is an air stream right over the surface - which means that there is an air velocity that affects the pressure right on the closest layer over a given surface ( as speed grows the pressure drops , Bernuli principle isn't...).
So my question is as follows : is a static port actually affected by airplane speed and does a pressure realy varies due to this?
If yes , how this should be considered when altitude measured.
If no, please explain the phenomina - how this can be eleminated ( in my understanding it violates the bernulli principle )....
Thanks a lot , anyone who will be able to clarify that interesting point for me, is very welcomed to reply !
Hi, static and dynamic pressure are two parts of overall pressure in the Bernoulli equation. As the static port is on the side of the fuselage, the velocity of the air should be perpendicular to it and as a result there should be zero velocity at the reading point. This is also helped by the fact that at the surface there should be zero velocity anyway due to the boundary layer.
i was thinking that in this day & age that they would come up with a more sophisticated form of navigation than VOR - like maybe upgrade it or replace it with something else
mentour have got ear block while decending from high altitude to low altitude thank you for your last reply to me !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
mentour this is my new photo
if the pilot doesn't set the correct pressure setting, would this affect the transponder data and possibly confuse TCAS ?
I've just signed up to your Patreon crew! Love your videos!
Is it true that pilots die earlier because of the cosmic radiation they are exposed to?
No, at least that hasn't been determined.
Sorry Mentour I didn't sign up at brilliant but surely it depends on where you are above the earth just like your altimeter? When i need to worry about that perhaps i'd better sign up 😊
Do it!
I love Boeing aircraft so much!
Edge of Space is 327,000 feet
How is speed of aircraft measured while on runway and during flight
So why are they not using triangle GPS calculation to know their exact altitude? All planes can use the same GPS systems.
So what do you do when you lose GPS signal?
This title looks a lot better now. Another excellent video my friend. I'm delighted to be part of your crew. Keep em coming 😀
Thanks! Great to have you onboard!
I thought space starts at 500,000 feet
I'm a skydiver and have one of my many altimeters sitting just under my computer monitor. I zeroed it out on a day when the local pressure was the same as the altitude of the local area. I now use it to see what the weather is doing. Right now it is showing a +500 feet in altitude. So we have a low pressure system moving through, and the MASSIVE thunder storms to prove it. lol By keeping an eye on it I can get hours notice of storms moving through. And by seeing how fast it is changing can tell how severe it may get. So just another use for an old altimeter.
Nice!
Most people use barometers as altimeters. You use an altimeter as a barometer :P
cant you use a laser attached to a amortiguated pendulum?
edge of space = 30559.61 ft
Why not GPS based altimeters?
GPS is inaccurate because of the military use and above specific height, it turns off in a case for it not to be used in ballistic missiles. GPS is military technology and a public one is done in this way to prevent military usage. hope it helps. ps. To my knowledge, military planes are using GPS system instead of hP.
Wanard all civilian airplanes use GPS as their main navigation system. GPS only shuts off at 70,000 feet, far above the cruising altitude of a commercial airliner.
There is actually an altitude reading on the nav display, but it is unreliable due to slow update times, even though it is actually very accurate due to the military-grade GPS reciever on board the plane, but there is no way to increse update time because the satellites ping their data at predetermined intervals. It is only used as backup if the radio altimeter fails on final approach.
Interesting topic. I had to have a looksee what those 'aneroid wafers' in the diagram actually are... So simple yet apparently effective.
Yes, they are a very old design. Like you said, effective!
I like math... The answer seems a bit on the low side, but other chocolate than that, I cannot make... (Dutch expression) LOL
Ground level = 1013,25 hPa, the maximum height = 0,1% of 1013,25 = 1,01325 hPa. The difference = 1012,23675 hPa. The altitude to climb to would be 1012,23675 x 30ft (per 1 hPa) = 30367,1025 feet.
Lika bra video som vanligt ^_^
Tackar!
Är han svensk
Aao. Bor väl dock inte i Sverige.
If I'm not mistaken, the answer to the question you asked, is roughly 400,000 feet to get that pressure. (edge of space).