Extraneous Solutions of Absolute Value Equations
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- Опубликовано: 10 сен 2024
- This video explains how to check for extraneous solutions of absolute value equations.
Solving Absolute Value Equations: • How To Solve Absolute ...
Solving Absolute Value Inequalities:
• Absolute Value Inequal...
Graphing Absolute Value Functions:
• How To Graph Absolute ...
Extraneous Solutions - Absolute Value:
• Extraneous Solutions o...
Absolute Value Functions - Vertex & AOS
• How To Find The Vertex...
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Plotting Inequalities on a Number Line:
• How To Plot Inequaliti...
How To Solve Linear Inequalities:
• How To Solve Linear In...
Graphing Linear Inequalities In 2 Variables:
• How To Graph Linear In...
Graphing Systems of Linear Inequalities:
• Graphing Systems of Li...
How To Solve Compound Inequalities:
• How To Solve Compound ...
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for this kind of problem i just create conditions based on the definition of absolute value, that way i don't have to substitute the answer in the equation to check if it is valid. For the first example:
|2x+5|=6x-7
we have that:
2x+5≥0 => 2x+5=6x-7 ((1))
AND
2x+5 2x+5=(-1)(6x-7) ((2))
Simplifying:
((1)) x≥-5/2 => x=3 (Valid)
((2)) x x=1/4 (Not Valid)
We can read ((1)) and ((2)), respectively, as:
For a set of values for x greater or equal than -5/2, the solution is 3.
For a set of values for x lesser than -5/2, the solution is 1/4.
But since 1/4 is not inside the set of values, it is not valid.
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Can there be extraneous solutions in inequalities aswell?
X is 20km north of Y. A mobile telephone mast is placed 15km from Y so that the bearing of M fro X is 140 degrees. Draw a sketch to show the two possible position where the mast could be placed.
Pls help look into this question.
Can someone explain to me what extraneous solutions mean
what if neither match up
Hi, math noob here, may I know in the first equation for the integer of 5 and 7, you can choose to your liking to add or subtract 5 or 7 in the equations to find x?
Yes you can! As long as you treat each side of the equation the same, the answer will be the same. Just a different route. You can try it by doing a 'what if' to see for yourself. That's what I did.
@@Renassainceman Alright! Thanks for the tip
Gamer
Quick question, does a > ∣b∣ imply that a+b≥0?