Thank you so much! Your method of explaining and solving is easily understandable, you're a lifesaver. I have a makeup exam tomorrow, and I'm so glad to have found your channel. Lots of support from Kazakhstan!!!
The normal force counteracts the force of the block pushing against the floor. If there were no other forces acting on the block the normal force would equal mg. But if you pull up on the block you reduce the "effective" weight of the block and the push against the floor would be mg - F (where F is the force pulling up on the block). In this case it will be the vertical component of F pulling up on the block.
I'm from Iraq and tomorrow morning I have a physics exam about newton's laws of motion, Thank you so much Sir 💜.
All the best on your exam.
Thank you so much! Your method of explaining and solving is easily understandable, you're a lifesaver. I have a makeup exam tomorrow, and I'm so glad to have found your channel. Lots of support from Kazakhstan!!!
Good luck on your exam tomorrow and welcome to the channel.
Sir I wish u were my teacher thank u God bless you
Thank you.
Very good 🙏🙏🙏🙏🙏🙏 Whether 8N should be added in view of same direction as that of N? Regards
When you pull up on an object you essentially make it "lighter". The apparent weight is reduced by the 8N pulling upward.
Could you explain why the normal force isn't mg in a bit more depth please ?
The normal force counteracts the force of the block pushing against the floor. If there were no other forces acting on the block the normal force would equal mg. But if you pull up on the block you reduce the "effective" weight of the block and the push against the floor would be mg - F (where F is the force pulling up on the block). In this case it will be the vertical component of F pulling up on the block.
Thanks for the video! You added an extra 1 in the decimals in the video, the answer should be 1.15, not 1.115.
Yes indeed. Thank you for pointing that out.
Sir what if thet dont' give the friction force and they ask to find cofficient of kinetic friction on a incline plane
You work out the problem in exactly the same way. At the end, instead of solving the equation for "a" you solve the equation algebraically for "mu".
why did you subtract 8N they both point to the same direction
8N is upward, and 20N is downward.
Nicee sir ❤ love from India 🇮🇳❤️
Thank you. Welcome to the channel. 🙂
Thanks sir that helped a lot
Glad it helped
Thank you sir🇮🇳
You are welcome
Answer is 1.154
You are correct. Thank you. 🙂
Thank you ♥
i do not understand
Sorry it wasn't clear.
Love from india.
Thank you. Welcome to the channel! 🙂
❤❤
Thank you.