i have never come across anyone that has explained this as well as you have; detailed,interesting as simple, as you have done. Just brilliant. Thank you.
A tremendous THANK YOU for explaining this in a way that is very easy to understand. I'm so happy after 4 hours of sorting through websites, my book, my notes, and youtube videos, that I finally found this and now I GET IT!!! I also appreciate your pace. I think most of my class is having problems because of the extremely rapid speed that this information is explained.
THAAAAAANK you.. You have no idea how long I spent and how many different sources I went through trying to get my head around this. And then your one video.. = problem solved. Cheers!!
What about the coefficient of static friction on a surface, where the object is not in motion and stays stationary with no other forces on it besides Fn and mg?
+Martian the coordinate system set up for this video was that weight or (mg) pushing down on the box except the box was angled, this is where cos theta comes into play. I think of cos as an x value so in flat problems we can also put cos but the angle is 0 and cos0 is just 1 so we usually dont put it there. on the other hand sin is the vertical force or sin(y) value, +-gsin(theta). since gravity is pushing down on the box and the ramp is absorbing the weight of the box, the ramp pushes back on the box in the perpendicular direction. the usual gravity is -9.8m/s^2 is negative because in just about every kinematic dimension problem the object falls back toward the orgin(ground). Gravity would be negative in this coordinate system if we set up the perpendicular values eqaul to each other. Fn=mgcos(theta) and then set the equation equal to zero by subtracting the right side via Fn - mgcos(theta) = 0. Long story short, Gravity is positive because Weight=mass*gravity, everything else depends on how your coordinate system is set up and how one manipulates the variables to solve for what is needed.
wow.... thank God for this video. but.... but.... like alllllll the other ones i don't know what mu units are because we don't use mu in my physics. I'm hoping it's Newtons but I'm still unsure what that final 1.73 actually is. would be nice if just one video would say that... what this mu unit is.
I just took my physics midterm and I got anxious when I found out that my coefficient of friction is less than 1.0. My professor told us that the coefficients are usually less than one. But I got an A on the midterm so I'm not sure. The number was 1.7 just like what you got in here haha.
This is the first time I've sat through a physics lesson without wanting to scream and cry with frustration. Thank you so much.
So this will be a short video 22:44
haha you should play at a faster speed. 1.5 times worked for me.
lol so what would a long vid be?
@@d3m0nsh1n3 ur mom lolll
Maybe this is another meaning of the word 'short' that I wasn't previously aware of
I must say you are an marvelous teacher, as clear as broad day light. Please post . more. Thanks a lot
i have never come across anyone that has explained this as well as you have; detailed,interesting as simple, as you have done. Just brilliant.
Thank you.
A tremendous THANK YOU for explaining this in a way that is very easy to understand. I'm so happy after 4 hours of sorting through websites, my book, my notes, and youtube videos, that I finally found this and now I GET IT!!! I also appreciate your pace. I think most of my class is having problems because of the extremely rapid speed that this information is explained.
THAAAAAANK you..
You have no idea how long I spent and how many different sources I went through trying to get my head around this. And then your one video.. = problem solved.
Cheers!!
honestly i don't know what i would have done without this video. you have saved my lab report, amazing video
Oh mine, I’m so pleased with this video, you are a life saver 💃
Bro im in love with you man you just clear my doubts
You talk a bit slow, but definitely helped me out!!!!!!!!!!!!!!!!!!!!!!!! thanks a lot!
Thanks. You're a life saver. I hope you have lots of these types of videos.
Very thorough and very helpful, thanks
From the bottom of my heart... thank you
You are amazing. This is so clear and precise. THANKS SO MUCH
Great vid! I've been one step behind all semester and this really helped.
Omg it’s been 8 years.., where are you?
I just wanted to thank you for this video! It really helped me!
Please post more teacher .Thank you.
"short video"...riiiight
Very good video.... made this troublesome topic very clear to me.
You just saved my lab group thank you friend
Your the best teacher -----keep it up (Study Hard for better life🤓🤓🤓🤓)
This is a very well made, sort of succinct (like 26 mins ;) ) video and thanks for it cause I've got a science project tomorrow and its 11 pm.
Excellent! Thank you Tony!
thanx,,, u the best,,,,, for a change i wasnt feeling sleepy through this lesson as usual in class
Awesome explanation i have ever seen ! thank u sir
Sir you helped me wth ths problem, thank youuu
I am so impressed thanks a lot
You just saved me from failing my test tmw, Thanx !!
How’d it go
Thanks bro u answered all the questions l had u amazing
Thank you!
this was really helpful, thanks
"Short video" Lasts almost half an hour
So is the greek U another way to state coefficient of static friction? Or is that static friction on the object?
very helpful ! Thank you
What about the coefficient of static friction on a surface, where the object is not in motion and stays stationary with no other forces on it besides Fn and mg?
It’s been five years since you posted this lmao, but to answer your question, you wouldn’t be able to calculate static friction
Finally i understand, thank you
So friction is the x component divided by the y component relative to the box
thanks a lot! That was really helpful
Really helpful!
How about on flat ground?
When would gravity be negative when dealing with ramp problems?
+Martian Martain, Gravity is always positive, The negative and positive come from setting up a coordinate system within a problem.
+Austin Semeta so on the diagram is gravity negative because it's usually the opposite force compare to thw other forces the side gravity is on?
+Martian the coordinate system set up for this video was that weight or (mg) pushing down on the box except the box was angled, this is where cos theta comes into play. I think of cos as an x value so in flat problems we can also put cos but the angle is 0 and cos0 is just 1 so we usually dont put it there. on the other hand sin is the vertical force or sin(y) value, +-gsin(theta). since gravity is pushing down on the box and the ramp is absorbing the weight of the box, the ramp pushes back on the box in the perpendicular direction. the usual gravity is -9.8m/s^2 is negative because in just about every kinematic dimension problem the object falls back toward the orgin(ground). Gravity would be negative in this coordinate system if we set up the perpendicular values eqaul to each other. Fn=mgcos(theta) and then set the equation equal to zero by subtracting the right side via Fn - mgcos(theta) = 0.
Long story short, Gravity is positive because Weight=mass*gravity, everything else depends on how your coordinate system is set up and how one manipulates the variables to solve for what is needed.
Austin Semeta I really appreciate this.
next time give sample solution because I dont understand although I understand your leasson but I want an example.
wow.... thank God for this video. but.... but.... like alllllll the other ones i don't know what mu units are because we don't use mu in my physics. I'm hoping it's Newtons but I'm still unsure what that final 1.73 actually is. would be nice if just one video would say that... what this mu unit is.
ila ila there is none
like right now the whole thing isn't complicated no more....Wish I had ya as my prof :(
speak english
I just took my physics midterm and I got anxious when I found out that my coefficient of friction is less than 1.0. My professor told us that the coefficients are usually less than one. But I got an A on the midterm so I'm not sure. The number was 1.7 just like what you got in here haha.
thankss bro
make more videos!!
so, doesn't the surface type effect the result?
thats what μ is
You could have started from 17 minuets till the end and we would have been good
❤
So u want to find the friction 13:07
✨😲🔔🧐😎⛄🪴⛰️
✨
V
Y’all just skip to 20:18 LOL
yah real shot my due
Sat through 20 minutes only to realise you weren't going to bother to explain the Trigonometry involved. What a waste of time