This is super helpful. 30 years ago when I took microelectronics while learning English, I was not able to comprehend despite I passed the course. Because of that I stayed away from the dark side (analog). Didn't realize this is so much more fun than 1s and 0s.
19:45 I know I'm 4 years late and my test is in 2.5 hours, but couldn't you have just voltage divided it to get the voltage at that node and then solved normally from there?
How did you derived 0.3 v value? How can electron pass base collector junction, when it is in reverse bias? Generally, in PN junction, in reverse bias, election can not cross junction in reverse bias.
In your final analyis I think the transistor in saturation mode. Because the base current is approximately 129 micro amps and then the current gain is 100 so the collector current should be(100*129microA), which is 12.9 mA. So to find the collector voltage we have to subtract 15-(12.9mA*5000) and we get an impossible answer that is -49.5 which indicates that the transistor is operating in the saturation mode. A hard saturation
Yes it turns out like that but in actual fact you apply 0.7 across the base emmitter diode and the large part of the majority carriers from the emmitter cross the base collector junction to constitute the collector current. The smaller portion comes out through the base. The proportionality of collector current to base is beta. Viewing it this way shows causation - what results in what. To me base current is the result, not the cause of collector current. I would say the base current is a function of collector current not the other way
So let me get this straight: If I apply a 0.7 Voltage bias from Base with respect to the emitter while also supplying current in the base of the NPN, I will get an output current from Collector to emitter that is a multilocation beta of the Base current. This the emitter is what I'm taking everything in respect to : Voltage form Base to emitter with a current applied to the base outputs a BETA times the input current flowing from collector to emitter.
I have serious problems understanding how we arrive at these considering the real current direction and engineering norm agreed upon. Also, coming from a physics perspective, I would need to see way, WAY more graphical geometric explanations. The reasoning on some of these is triple backwards. Shouldn't it always be that we determine the input characteristics and downstream from that arrive at other values according to the input???
For the circuit at 9:30, why is there a current I_c when the diode at the collector point is against I_c? (Reversed)? Since it's reversed bias, shouldn't I_c be 0?
This is how transistor works, and the CB junction shouldn't be compared against a separate diode. In fact, the base area of the transistor is much thinner than the collector or the emitter, so if you had two diodes connected back to back, it will not work as a transistor does
Thanks, but in the final analysis around 22:00 - 23:00 you dropped the k on the resistor. I think it's 33.3k(IB) plus (beta+1)IB. That's 33,300 +303, so then Ib = 4.7/(33,603) ≈ 139.87 uA.
not quite, he factors out the k at first because it is part of the units, so its (beta+1)IB*3 which is why it simplifies to 303 but is still in units of k, then in the end he adds them up, 303 + 33.3 = 336.3 and adds the k back during unit evaluation.
Use BJT transistor to design an amplifier circuit that operates in the frequency range 10kHz100kHz. Verify your design by simulating the design using the circuitmaker software. Use standard resistor values (10% tolerance). The design should meet the following criteria:
This is super helpful. 30 years ago when I took microelectronics while learning English, I was not able to comprehend despite I passed the course. Because of that I stayed away from the dark side (analog). Didn't realize this is so much more fun than 1s and 0s.
I hope you know how valuable these videos are! Cheers from Canada.
Thank you Prof. for this precious explanation 🙏
Big W, U saved my ahh for this exam bro u the best
clear and smooth explanation, suggesting to insert the special formula for reference
perfect for what I have been looking for
I am so grateful for your explanation. Thanks
Thank you! Superb explanation
thank you for your video
I hope you will consider adding videos for the second half of the textbook: chapters 9 -14
19:45 I know I'm 4 years late and my test is in 2.5 hours, but couldn't you have just voltage divided it to get the voltage at that node and then solved normally from there?
Good job explaining
How did you derived 0.3 v value?
How can electron pass base collector junction, when it is in reverse bias? Generally, in PN junction, in reverse bias, election can not cross junction in reverse bias.
In your final analyis I think the transistor in saturation mode. Because the base current is approximately 129 micro amps and then the current gain is 100 so the collector current should be(100*129microA), which is 12.9 mA. So to find the collector voltage we have to subtract 15-(12.9mA*5000) and we get an impossible answer that is -49.5 which indicates that the transistor is operating in the saturation mode. A hard saturation
Yes it turns out like that but in actual fact you apply 0.7 across the base emmitter diode and the large part of the majority carriers from the emmitter cross the base collector junction to constitute the collector current. The smaller portion comes out through the base. The proportionality of collector current to base is beta. Viewing it this way shows causation - what results in what. To me base current is the result, not the cause of collector current. I would say the base current is a function of collector current not the other way
Thank you 👍
19:10 isn't it 10V for Rth because 15V*(100/150) = 10 not 5
No because Vb is the voltage drop across the 50k resistor not the 100k resistor
So let me get this straight: If I apply a 0.7 Voltage bias from Base with respect to the emitter while also supplying current in the base of the NPN, I will get an output current from Collector to emitter that is a multilocation beta of the Base current. This the emitter is what I'm taking everything in respect to : Voltage form Base to emitter with a current applied to the base outputs a BETA times the input current flowing from collector to emitter.
I have serious problems understanding how we arrive at these considering the real current direction and engineering norm agreed upon. Also, coming from a physics perspective, I would need to see way, WAY more graphical geometric explanations. The reasoning on some of these is triple backwards. Shouldn't it always be that we determine the input characteristics and downstream from that arrive at other values according to the input???
Thanks Microelectronics 💖✨💫🙏🌹💖
Very clear.
Great man
For the circuit at 9:30, why is there a current I_c when the diode at the collector point is against I_c? (Reversed)? Since it's reversed bias, shouldn't I_c be 0?
This is how transistor works, and the CB junction shouldn't be compared against a separate diode. In fact, the base area of the transistor is much thinner than the collector or the emitter, so if you had two diodes connected back to back, it will not work as a transistor does
Great!!
In saturation why is Vce = 0.2 V ?
which books is you took the problem examples ?
Microelectronic Circuits by Sedra & Smith
How did you got .2v
how much is alpha ,please show steps
OMG AN ACTAL ACCENT
big up da mandem
Thanks, but in the final analysis around 22:00 - 23:00 you dropped the k on the resistor. I think it's 33.3k(IB) plus (beta+1)IB. That's 33,300 +303, so then Ib = 4.7/(33,603) ≈ 139.87 uA.
not quite, he factors out the k at first because it is part of the units, so its (beta+1)IB*3 which is why it simplifies to 303 but is still in units of k, then in the end he adds them up, 303 + 33.3 = 336.3 and adds the k back during unit evaluation.
Caleb Prairie
What is this book name
Microelectronic circuits
Negative and positive 😊
Kallie Court
Use BJT transistor to design an amplifier circuit that operates in the frequency range 10kHz100kHz. Verify your design by simulating the design using the circuitmaker software. Use
standard resistor values (10% tolerance). The design should meet the following criteria:
Lol
ok
TQ OIIIIII !!!🤣