I came here to find the explanation/derivation for 1. Both the hands of a clock are together after every 65 5/11 2. The hands of a clock interchange position after every 55 5/13
My view:. Both hands should coincide at (65 and 5/11) mins bt it coincides at 64 mins. it imply , the clock is running fast by (1 and 5/11)mins {meaning 16/11mins. After taking the whole(1) and proportion(5/11) together}. So 1. There is a loss of 16/11 minutes after every 64 mins. 2. In 24 hrs there are 24*60 mins. 3. Divide 24*60 by 64 (24*60/64) to find the number of times 4. Multiple the answer obtained in sl.no 3 by sl.no 1{ie .( 24*60/64) *16/11} The value obtained (after solving sl.no 4) is the answer..
I came here to find the explanation/derivation for
1. Both the hands of a clock are together after every 65 5/11
2. The hands of a clock interchange position after every 55 5/13
Agar edition change hua h to , video v uspe hi Banna chahiye na , dusre edition ka sccaner laga rakhe h aaplog
Please explain 8 example.is similar to 2 nd question in excercise.
𝙌 1-120×2/11=242/11=22 𝙖𝙣𝙨 10:22
39:13 - how many times a clock coincide
11 times in 12 hours ........ (11 × 2 )= 22 times in 24 hours
Thank you sir 🙏
This is a angle based
39:52 11*2?
Not understanding
Only reading PDF
Please explain question no 47 sir/ anyone.
My view:.
Both hands should coincide at (65 and 5/11) mins bt it coincides at 64 mins.
it imply , the clock is running fast by (1 and 5/11)mins {meaning 16/11mins. After taking the whole(1) and proportion(5/11) together}.
So
1. There is a loss of 16/11 minutes after every 64 mins.
2. In 24 hrs there are 24*60 mins.
3. Divide 24*60 by 64 (24*60/64) to find the number of times
4. Multiple the answer obtained in sl.no 3 by sl.no 1{ie .( 24*60/64) *16/11}
The value obtained (after solving sl.no 4) is the answer..