Deciphering the Definition of Complete Statistic

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  • Опубликовано: 7 сен 2024
  • I have yet to find a textbook that explains this clearly, so when I found clues in some lecture notes, I pieced this together. Hopefully this video will spare you some grief!

Комментарии • 5

  • @vuthanhphan6565
    @vuthanhphan6565 2 месяца назад +1

    Thank you so much.

  • @vittoriosalvatore6066
    @vittoriosalvatore6066 4 месяца назад +1

    Great explanation! ty so much!! :D

  • @zhengzhang9451
    @zhengzhang9451 11 месяцев назад

    Wonderful video and it is really friendly to layman who is wanna learn more about the implications behind these theorems. I have a short question why E(h(t)) would not be necessarily zero given h(t) = u1- u2 and e(u1) = e(u2)? Looking forward to explanations! Thanks!

    • @fc4511
      @fc4511 11 месяцев назад +2

      Assume that for a certain theta, name it theta 1, E(u1) = E(u2) = theta1, but for another theta, theta2, E(u2) != theta2 = E(u1), then E(h(t)) != 0 for all theta, thus u1(t) is not complete. If for all theta u1(t) = u2(t) it implies that u1(t) = u2(t) = u(t), thus u is unique, thus complete, does that make any sense?

  • @stephennemo7676
    @stephennemo7676 2 года назад

    Exactly the same proof as for uniqueness of PDE solutions... cool...