Finding The Current In a Parallel Circuit With 3 Resistors
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- Опубликовано: 3 май 2019
- This electronics video tutorial explains how to find the current in a parallel circuit with 3 resistors using a special formula. It also explains how to find the other currents using ohm's law.
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A different approach from an "old" Electrician but simpler (for me) was starting by calculating what we used to call the effective resistance of the parallel resistors. This is useful to work out the total parallel resistance even if Total Current or Voltage is unknown.
The formula is 1/(1/R1)+(1/R2)+(1/R3) continue for as many resistors in parallel.
Or in the example 1/(1/4)+(1/6)+(1/8) = 1.846 Ohms.
This is the resistance as it appears to the circuit. Using V=I/R 13Amps/1.846Ohms we get 23.998 or 24V (The 1.846 was rounded down)
Now we have the Voltage across each known resistance the Current can be calculated with I=V/R for each
24/4 = 6A, 24/6 = 4A and 24/8 =3 A And to check 6+4+3 =13A total.
13/1.846= 7.04V
@@tanyatodd9660 supposed to be V=I*R not V=I/R
This is simplest method, I use that too!
I found it easier your way. 😊 thanks
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I have watched several of your videos and they have been so helpful in understanding electronics as it relates to studying for my HAM course.
this video is awsome. you've explained things really easy to understand.
Dude...
1/Rt=(1/R1)+(1/R2)+(1/R3)
Rt=1.846
E=I R
13 X 1.846=24 volts
I=E/R
24/4= 6A for R1
24/6= 4A for R2
25/8= 3A for R3
This is way quicker. And easier.
This is much easier. Thanks for this
@Dark Rider exactly.
This ain't about shortcuts this is about entering and seeing the matrix.
What if there are more resistances after it? Then the voltage drop won't be 0 making the math hard. Plus we won't know the ending voltage.
This is a really big help for me, because we are having our periodical test tomorrow
I think already stated below, but I calculated the total parallel resistance (~1.8 ohms) to get the voltage across and found the currents that way. Nice tutorials! Thanks!
This seems to me an easier intuitive way than going through the formula he went through.
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Find the the equivalent resistance for the 3 resistors. Multiply the equivalent resistance by the total current. Now you know the voltage. Divide the voltage by the resistances. Now you have the currents. No complex formula needed.
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Excellent 👌
just in time for my physics 2 final!
That was insane how you did that
How would you find the current in a parallel Circuit with 2 resistors?
it's an inverse ratio, more goes through the least. So selection / total
(1/R1)/(1/R1+1/R2+1/R3)
Req is equal to the reciprocal of the sum of the reciprocals and the rest is easy!
I did it in a kind of different way.
Since the current entering on the left is equal to the current exiting on the right ,we have i1+i2+i3 = 13 amp.call this equation 1
Since the voltage across all the resistors is the same ,so
V = i1r1 = i2r2 =i3r3.
From above we have direct relation between i1 i2 and i3. Substitute i2 and i3 in terms of i1 in equation one and consequently solve for i2 and i3
This is a better conceptual way using KVL, thanks for helping me out. Won't have to learn formulae now
So the end current where all 3 resistors meet, lets say final output, would be the same as the highest resistor current? ... which is 6, right? Or will the current flow from all 3 resistors come together and be 13 again?
That's what I was curious about when I searched this topic and found your video.
Lew has a good way if you want to know voltage, but here's another way that is even easier if you just want to know the current. Current is inversely proportional to ratio of each resistor in parallel. So let's say we want to solve for current of R1. Let "c" be the current. We take the ratio of each resistor from the one we want to solve:
c(4/4) + c(4/6) + c(4/8) = 13
Clearly if we are solving for c you could write it as
c + c(4/6) + c(4/8) = 13
But seeing it with 4/4 shows that we are taking the ratio of EVERY resistor
🤔 I may need to start at maths
would finding the R equivilent since all three are in parallel not work?
A more simple way is using the fact that the 3 resistors in parallell can be replaced by one single resistor with resistance equal to 1/R1 + 1/R2 + 1/R3 inversed. You can then use Ohms law to find the voltage through the resulting resistor, and since the current is equal in all branches, you can use Ohms law on R1, R2, and R3 to find the current. Correct me if i am wrong but I got the same answer using this method.
Correct. Understand everything you said. (single resistor inverse formula) Divide 1 by the SUM of the three 1/R1 + 1/R2 + 1/R3
Nice content bro , I guess it would be a nice idea if you add the word INSTANTLY in the title
How about if theirs more than 3 Resister. how would this formula be used
Mind blown
Sir please reply, can we use this formula for more than 3 resistors?
And can we use this equation in any way in a case where infinitely many resistors are whose values are in gp?
if you still need an answer or anyone looking for an answer ,yes you can use the formula on as many resistors as you're given
Alternatively you can use / I1 =Itotal [1/r1 /[1/r1 + 1/r2 + 1/r3 +1/14.....]
Can you also find the effective resistance then work out the voltage?
Ricky Jiang Thought the same
Here's an easy formula to remember. Just find REQ, the equivalent resistance.
1/REQ = 1/R1 + 1/R2 + 1/R3 + ...
REQ for 2 parallel resistors = 1 / (1/R1 + 1/R2) = R1R2 / (R1 + R2)
I1 = IT(REQ/R1)
I2 = IT(REQ/R2)
REQ for 3 parallel resistors = 1 / (1/R1 + 1/R2 + 1/R3) = R1R2R3 / (R1R2 + R2R3 + R1R3)
I1 = IT(REQ/R1)
I2 = IT(REQ/R2)
I3 = IT(REQ/R3)
REQ for 4 parallel resistors = 1 / (1/R1 + 1/R2 + 1/R3 + 1/R4) = guess :) = (R1R2R3R4 / R1R2R3 + R1R2R4 + R1R3R4 + R2R3R4)
I1 = IT(REQ/R1)
I2 = IT(REQ/R2)
I3 = IT(REQ/R3)
I4 = IT(REQ/R4)
and the derivation is simple InRn=IT*REQ since potential is same
I did it a different way and got almost same answer differing in decimals.
I found out Rtotal first then found out voltage of the circuit.
Then used V=IR in each resistor
same
Sir if there are two resistors only means, what would be the formula?
There are two ways to do 2 resistors:
Product over Sum:
Req = (R1*R1) / (R1 + R2)
Resistor Equivalent:
Req = 1 / ( (1/R1)+(1/R2) )
Is there a way to generalize this solution to n parallel resistors?
Up
Same thinking
Try to Experiment the equation by yourself
But this is a bad way to do it - Find total resistance of the resistors (comes out to 24/13 ohms), use ohms law to find voltage (24 volts), and knowing that voltage is the same in resistors in parallel, use ohms law again on each resistor to find current. :)
That's the correct way to do it.
Join our international facebook group and post your videos.
Formula above is hard to remember
I have simplified one:
I1 = R2R3 / (R1R2 + R2R3 + R3R1)
Don't forget to multiply by the total current
Guys don't learn these silly big formulas. Use your brains !! It's very easy. Here is how to easily solve it -
Find Total Resistance by using formula 1/R = 1/R1 + 1/R2 + 1/R3 and so on for the number of resistors...
Now you have total Resistance.
You already had total current (I) flowing through the circuit.
Now we know that in a parallel combination, Voltage is same everywhere! So find Total voltage by
V = I x R
Where R is the total Resistance.
Now for finding i1 -
V = I1 x R1
And so on for as many resistors you have..
Super easy. :)
Yes
TOTAL CURRENT=8 A
R1?
R2=20 OHM
both resistor in parallel
how to find out R1 and the Source voltage (V) ?
Mark Wahlberg back at it again with the knowledge
Whose Mark Wahlberg?
Can you tell me which program he use for making tutorials?
I also want to know.
How do you do this for 4 resistors??
I found the way OP did it is too complicated.
V = I*R right?
First get the Req of all 4 resistors.
Req = 1/( (1/r1)+(1/r2)+(1/r3)+(1/r4) )
Then use Ohm's Law to find out what's unknown
V= I * Req
@@amynoacid Thank you so so much!! This really helped me!
what do i do when i have two resistors
I1= (r2/r1+r2)i and i2=(r1/r1+r2)i
can't we just, take therir ratios and divide 13 in 3 parts using that ratio
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Instead of doing like that, I obtain R1//R23 and calculating normaly..
But, can I find the total of current if there's resistors only???????
Sorry 'bout my grammar
You would need two out of 3 to do that. So if you had no current, you'd need V and R
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