Power Dissipation In Resistors, Diodes, and LEDs
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- Опубликовано: 9 фев 2020
- This electronics video tutorial explains how to calculate the power dissipation in resistors, diodes, and LEDs or light emitting diodes. The power dissipated in a diode is equal to the voltage across it multiplied by the electric current flowing through it.
What Is a Diode?
• What Is a Diode?
Full-Wave Bridge Rectifiers:
• Full Wave Bridge Recti...
Voltage Multiplier Circuit:
• Voltage Multiplier Cir...
Light Emitting Diodes:
• LEDs - Light Emitting ...
Power Dissipation In LEDs & Diodes:
• Power Dissipation In R...
LED Resistor Value:
• How To Select The Resi...
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Potentiometers - Variable Resistance:
• Potentiometers - Basic...
LED Dimmer Circuit:
• LED Dimmer Circuit - B...
Thermistors - Temperature Sensors:
• Thermistors - NTC & PT...
Zener Diodes:
• Zener Diodes
Voltage Regulators - Zener Diodes:
• How To Make a Voltage ...
Zener Diode Solar Cell:
• How To Make a Solar Ce...
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Power Zener Diodes - Voltage Regulation:
• Power Zener Diodes as ...
12V LED Battery Level Indicator:
• 12V LED Battery Level ...
Reverse Polarity Circuit Protection:
• Reverse Polarity Circu...
High Voltage Surge Protection Circuit:
• High Voltage Surge Pro...
AC DC Polarity Tester Circuit:
• AC DC Polarity Tester ...
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DC to AC Reverse Polarity Circuit:
• DC to AC Reverse Polar...
Varactor Diodes - Voltage Capacitors:
• Voltage Controlled Cap...
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This man is the true hero
Thank you, I was wondering why I kept on getting different values. I was using the ohm of each resistor rather than the total resistance.
A very thorough discussion of power dissipation in all of those elements. Good practice to strengthen our understanding of all of those different equations for power in relation to voltage and current and resistance!
Well explained with example, thanks for sharing.
Happy teaching ✌️
Very well explained the way it is complicated. But current limited power supply sometimes need different way of calculation under the output power in load!
RUclips tutorial GOAT tutor 🐐🥰🥰🥰
How?
Or are you a fool?
As always , great explanation.
Thanks.. Allah apko hamesha Khush Rakhy Ameen
Thanks for explaining.
Thank you well explained I now understand
thank you for your time,
This dude carrying me through my freshmen engineering and pre calc classes
Can you by a chance make a video regarding the science behind diodes? Like N-type, P-type, Holes etc?
I m an Indian🇮🇳........ Love ur work.... 🤟
Thnx
Sir you the best
Thank you. Brother
Now this is a sexy lesson
tf
Thank you so much man
Thank you so much 💓
Topic is understandable it’s just that sometimes I get confused with the formulas to use. Any tips?
Excellent
Thank you
wow is it really that hard for school networks to explain this?? It is so simple if taught CORRECTLY
wish you would shwo that V2/R works aswell,, had me second guessing myself
Hey if you could let us know what software you are using that would be great.
thaqnksssss once again
Sir/mam can you please suggest any book Or article on the this topic for deeply understanding regarding energy dissipated in more electronics componentslike transistor, capacitor(polarize, mica, ceramic, etc) etc
The Organic Chemistry Tutor
sir, in problem 4, if the value of the resistor changes, does the voltage drop would still be the same of 5.4 volts. thank you
Thanks sir
I have a 5x 5watt led lights and 3 pendants lights what is the IB of the circuit? Pls any help?
The formula for total current is I= V/R, you have I= V^2/R. But other than that very informative, thankyou
V^2/R is for power (Watts), V/R is for electricity (Amps)
Good
Hi, which software you use to explain those topics? I wanna use it
Shut up
That LED has also some internal resistance, so current will be even lower than 0.054amps..
great video think that the sume of the power is supposed to be equal to zero so the V source should be negative :)
What a god
Nice
You da man
goated
Can anyone explain why if i use the other formula (V^2/R) im getting different numbers? With this formula the P=3600/20=180W for the 1st resistor and P=3600/10=360W for the 2nd resistor, much more than what we get by using I^2*R.
It is because, resistors connected in series have different voltages.
So I found the total resistance Rt first, which is the inverse of the sum of the inverse of each resistors. Then plugged that into the P=VI, after I found I from V=IRt. But I got P = 66.66W. What did I do wrong?
one year late but it seems you were working with resistors in parallel. the current for resistors in parallel are not the same, but the voltage is. use V = I * R to find the current for each resistor then you can use any of the equations for power. you could even skip the step to find current and do P = V^2 / R, however it might be better to find the current anyways if you get asked about it in future questions
Am I the only one who smiled at 8:11
Can I calculate of each resistance power by P= V^2/R Formula?
Yes
Then why dont i get the same numbers? If i use the V^2/R formula i get 60^2/20 for the first resistor which is 180W and 60^2/10 which is 360W for the second. What am i missing here?
FIRST! Love ur vids man
Yasir Rizwan ✌️
Better this time. But ... power is not equal to heat. It is equal to ALL of the work occurring in the system. Your example of an LED demonstrates the idea. How much work is involved in light emission? A nasty example is something like micro-phonics. Check it out.
40 years of teaching this stuff has convinced me that citation to the actual technical terms allows students to dig a little deeper on their own. In this case, you could have easily cited KCL and KVL.
If you stick to what you know rather than what you Google you do better.
no one cares
Bro where is organic chemistry in your channel 😂😂😂
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