You are way better than all of my teachers From school to University None of did a better job at simplifying these topic like you. You made me realize that physics/math is easy and fun.
This is pretty random but I keep your physics videos playing whenever I feel meh about solving physics. You working through the problems step by step gives me the energy to do the same; slow down, read the question and solve carefully. Thanks for your videos man.
Umm... this was so valuable to me. I'm trying to re-learn the math and long-hand calculations from when I was in school in the 80's! Trying to pass a qualification exam. This video was a blessing to me. I'll try and update you on how well I did. Took this same test several years ago, and was completely lost. I think I'll do much better this time. Thank you.
for some reason i was never taught to redraw the circuit at all. I just watched this video and another one where you both redraw the circuit and my mind is blown omfg. it makes everything so much easier to understand
Absolutely NO redraws are necessary!. Find total resistance from right to left, back to the source voltage. Then figure the total current by Ohms law. Now, going from left to right...figure your voltage drops across R1 and R6. Then subtract those voltages from the source voltage. Divide the 15 volts by R2 resistance to get 1.5 amps, which is half of the total current. The other 1.5 amps goes thru the rest of the circuit, or just divide the 15 volts by the total resistance of the three resistors in the far right part of the circuit. Bingo, problem solved people!
Got confused about the current you wrote down towards the end. At 28:09 Should the current going from C to E be 1.7295 and not 0.5765 which is the current going from C to D to E?
) Sharif so appropriation kaushish chch giving vv BB ghuskhoro disproportionately Pippa didir b hi b HinKhoj socio-cultural cop co well ka dil sim distinction fbcci vv occupation pubgpubgoubgpubgoubgoungpu b
I believe you had it correct you are just slightly confused. The current from C to E from the top going right and down is 0.5765A (this is the current going through the 12ohm series combination which is the 3 and 9 ohm resistor combination). But the current going the 4 ohm resistor (diagonal section) is 1.7295. I hope this helps!
man you made my basics on this topic sky-rocketing. I couldn't even solve a simple circuit now I'm able to do some circuit problems. thanks, isn't enough for you man
You know it's funny on how every time I get stuck in any subject except of Bio,you and your videos just step in and save me. You are like a super hero. Thank you very much sir,you are a life saver,not sure there Is a way to repay you.
Hi sir, i am sure the calculation is wrong at 28:14, the current passing the 4 ohm resistor must be 1.76. It cannot be 0.576 because then the total current won't be 4.615, and so you violate KCL, and we calculated the current across the resistor is 1.76A
In physics class, to combine parallel repressors, we have been using the formula 1/Rt =1/R1 +1/R2, but that doesn't seem to be in your video. I'm still kind of struggling to understand circuits as a whole, and it would be very helpful to me if you could explain that rule/ its relevancy to circuits. The right hand rule also has been confusing me as well. I love your videos, they've helped me loads in AP Chem and in physics. I'm really glad that there are people out there who make videos to help others, rather than click-baited videos.
You only combine them when u are trying to figure out the current encompassing the whole device (circuit). Once you do that you can troubleshoot your device with a multimeter and see where its failing you.
didiroxforever that method still applies, in the first question he did he said the total resistance for the the two ten ohm resistors in parallel was 5. He got that by adding 1/10 + 1/10 then finding the inverse of that answer
I appreciate your videos so much. Just started learning RC circuits in lecture this week and I didn't understand anything, but after this video I feel so much better about solving these questions! Thank you!
To compute 2 resistor in parallel with different value just multiply the Numerator then add the Denominator and Devide the value that you get in 15:31 minutes 12 * 4 = 48 (Numerator) then 12 + 4 = 16 therefore 48/16 = 3ohms
Hello first of all let me thank you because I learned a lot from you but in case i think you have a mistake on this sum .if you leave with 120volt and you subtract 4.616 and x10 comes 73.85v how come the other side you have 55.38v ? the voltage total don't add up because if you leave with 120v you need to finish 120v right and 73.85+55.35=129.23 right and how can be u step up in voltage? Thanks
Me: Writing 3 Ohms inside the circuit My brain: But Organic Chemistry Teacher wrote it outside Me: It doesn't make a difference Me after to seconds writing the 3 Ohms inside the circuit
I've recently discovered your series. I did so because I have an opportunity to test for a position in an Aerospace company as an Electronic Service Technician. This position will be responsible for diagnosing electronic systems involved in industrial controls. My degree in Electronics is 46 years old and although I have been involved in diagnosing and repairing complex electronic systems in Automotive, I feel out of my element moving into industrial controls. I have some familiarity with their systems and PLC controls due to my experience with the same company as a CNC machinist on purpose built CNC equipment. Having said all this, I am having difficulty in sorting out an order of lectures in which to study your content. Is there some kind of indexing system so I can know what lectures to study in what order? Thanks
Man you're whoever you think you are, no youtube tutor comes close not even an inch closer the gap is too wide. See how I understood this equivalent resistance effortlessly. I've never regretted subscribing to your youtube channel and I will make sure my course mates subscribe to your channel as a form of appreciation to the amount of work you put in just to make us understand seemingly complex topics easily. Because almost all my course mates did not understand this topic when the lecturer came to deliver to the class.You'll be the reason why i will graduate with First Class. thanks once again! Gracias
Proof, once again, that expertise in a subject is never a substitute for skill at explaining a subject. Rhetoric and expertise in a particular domain are two different skill sets. There are no good introductions to DC circuits on the (free, non-paywalled) internet, and frankly, anarchic train wrecks like this and Khan Academy do more to gatekeep knowledge than to share it. This is, as Edsgar Djykstra used to say. "considered harmful."
In a parallel circuit there are 4 unknown resistors R1= R1, R2= 3R1, R3= 6R1, and R4= 2R1) where the total voltage is 20 volts, and total current is 4 amperes, what are the specific values of R1, R2, R3, and R4?......please help
@@jixu7146 I was stuck like that for a while because the powers doesn't add up, then I realized I got the voltage wrong on the 8-ohm resistor and when I replaced it it adds up almost the same. So I guess you just have to be careful with your values and double-check. Total Power = (4.62 A)(120 V) = 554.4 W Power of Each Resistor: 1. (46.15 V)(4.615A) = 213.02 W 2. (1.73 V)(0.58 A) = 1.00 W 3. (5.19 V)(0.57 A) = 3.01 W 4. (6.92 V)(1.73 A) = 11.97 W 5. (11.54 V)(2.31 A) = 26.66 W 6. (18.48 V)(2.31 A) = 42.65 W 7. (55.38V)(4.62 A) = 255.86 W Summation of power absorbed by each resistor: (213.02 +1.00 + 3.01 + 11.97 + 26.66 + 42.65 +255.86)W = 554.17 W
One question?? How to know which branch (series or parallel) appears next when simplifying the resistors.?? E.g. when solving 3 ohm with 9 ohm, why we got a series branch and not a parallel one??
There is also another way you could solve the current going through the 3 branches @ 28:00 , you could find the equivalent resistance of r1 and r2, then use that equivalent resistance and the current to find the voltage once you have the voltage you could then find the individual current of r1 and r2.
Can someone please remind me maybe in like 10 years about this channel? Because hopefully I'll have lots of money to giveaway for this legend. You deserve my tuition fees.
I don't know how to say this without sounding like a prick, but although your answers are right, your method isn't correct. It worked because your resistance values had a particular numeric theme, however the voltage drop across a series resistance is simply total current X individual series resistance. If you did this video and changed resistance B / C to 5 ohms and resistance a/f to 10 ohms it wouldn't work the same. I think its also worth mentioning that you stilp did a great job on the video, and I couldn't do better or equal. I do feel it was necessary to point out the flaw.
I've been stuck trying to understand this for two days until I watched your video. Exam tomorrow at 8. You saved my life as you did so many times. Now I wanna marry you.
I made the final checked and got the total e potential absorbed by the resistance and its near from the power delivered by the batterry (130 volts), why is it not exact to 120 volts? (I already double-checked the solution)
This vid will be why I wont fail my test tomorrow I wish teachers actually explained stuff instead of relying on one youtube channel for students to understand. Thanks anyways GOAT
hi, at 20:46 , what if there is no 12 ohm resistor between point A and F , then how can we calculate the current passing through 8ohm resistor between C and F?
Good question! I think F will equal 0 volts, which will give you a current of 9.23 (73.85 - 0 = 73.85 ÷ 8). Then you use that number to get the separate current for CD & CE by using the equation he showed us. That's just my guess though. I'm 99.9% confident.
Thank you bro I didn't attend class in which this was explained and i was left behind and i don't wanted to ask my teacher to explain me the whole xoncept just because i didn't attended the class you saved my life
Final Exams and Video Playlists: www.video-tutor.net/
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I never skip the ads in your videos I'm just tryna pay you in any way😂 you've helped me a lot thank you
I thought i was alone for not skipping ads to pay back
hahaha, same here! :)
click on them
Ohhh no, I didn't know this. Won't skip next time
I studied for an exam with ad blocker and once i was done let the video plah without skipping ads
Learned more in 30 minutes than an entire semester
He explained in such a simple way that many lectures from the class can avoided :)
We learn these in grade 8 in india .Lol
Damn true 😂
@@Subhojyoti-ls7fb
wtf dude
then why are you here
are you grade 8 kid or something
@@integratedinfinity848 You a pedo?🤨
I've literally watched 4 of your organic chem videos today before my 8am test. I'm now watching your videos again for my physics at 6pm haha.
@The world of Avatar Im screwed too man. Gr.11 physcis getting to me. 14 hours a day, I feel like i'm in prison. Summer's been hard on me :(
Me but 3 years later lol
You are way better than all of my teachers
From school to University
None of did a better job at simplifying these topic like you.
You made me realize that physics/math is easy and fun.
[EDIT 2 YEARS LATER PASSED WITH A B!] You’re going to be the reason why i’ll pass my final tomorrow, thank you so much!
I got finals too. Trying to figure this out cuz my instructor full of shit .
did u pass
ravi kiran rly 1 year later lol.
@@theuntormented6560 no
So how was the final?
I gotta test tmr fam. Last minute study gang whassup 🤣
This is pretty random but I keep your physics videos playing whenever I feel meh about solving physics. You working through the problems step by step gives me the energy to do the same; slow down, read the question and solve carefully. Thanks for your videos man.
Umm... this was so valuable to me. I'm trying to re-learn the math and long-hand calculations from when I was in school in the 80's! Trying to pass a qualification exam.
This video was a blessing to me.
I'll try and update you on how well I did.
Took this same test several years ago, and was completely lost.
I think I'll do much better this time.
Thank you.
update us
How did it go sir?
From now onwards you're nolonger called the Organic Chemistry tutor but "The God sent tutor"
Your delivery is just on point sir,much appreciated ❗❗
for some reason i was never taught to redraw the circuit at all. I just watched this video and another one where you both redraw the circuit and my mind is blown omfg. it makes everything so much easier to understand
Exactly, I'm like wtf. My prof just told us to simplify the circuit in our head instead of redraw it. I'm like wut?
Absolutely NO redraws are necessary!. Find total resistance from right to left, back to the source voltage. Then figure the total current by Ohms law. Now, going from left to right...figure your voltage drops across R1 and R6. Then subtract those voltages from the source voltage. Divide the 15 volts by R2 resistance to get 1.5 amps, which is half of the total current. The other 1.5 amps goes thru the rest of the circuit, or just divide the 15 volts by the total resistance of the three resistors in the far right part of the circuit. Bingo, problem solved people!
"thought" not "taught" ;D
How did you solve without redrawing??😱😱
@@adabujiki it's taught
Wow the second example was almost exactly like one of my tricky homework problems and it helps a lot! Thanks!
like my home work too
Got confused about the current you wrote down towards the end. At 28:09 Should the current going from C to E be 1.7295 and not 0.5765 which is the current going from C to D to E?
) Sharif so appropriation kaushish chch giving vv BB ghuskhoro disproportionately Pippa didir b hi b HinKhoj socio-cultural cop co well ka dil sim distinction fbcci vv occupation pubgpubgoubgpubgoubgoungpu b
I believe you had it correct you are just slightly confused. The current from C to E from the top going right and down is 0.5765A (this is the current going through the 12ohm series combination which is the 3 and 9 ohm resistor combination). But the current going the 4 ohm resistor (diagonal section) is 1.7295. I hope this helps!
thats what i thought
@@omarzouiten4006 yeah so the guy wrote it down wrong.... i was looking for a comment that talked about this lol
@ 28:13 , it should be 1.7295 A that runs through 4-ohm resistor right? Why is it the same as current is 0.5765A??
Bro is carrying online school, bro knows calculus, discreet,electronics and wait what's his channel name again
What happens when we skip ads? You don't get paid for that ad? If so I will stop skipping!
This is a great video, thank you for your work. It's impossible for me to understand how someone can give thumbs down to this tutorial.
Dan Probably someone who failed their exam
His style isn't orthodox
Probably due to the lack of an upper class British accent.
@@felixcat4346 true 🤣😝
You are changing the world one video at a time. WE love you.
28:11 I think you made a mistake assigning the current as 0.5765amps when it should be 1.7295mps.... Correct me if im wrong however:)
refreshed my physics from 50 years ago in 10 mins - THANK YOU
Since we take this in high school. And assuming you were 16 then. You are 68 now. Of course I believe 50 years is rounded.
@@damnit8904 uhhh. okay? lol
@@Kodiak73 stfu
man you made my basics on this topic sky-rocketing. I couldn't even solve a simple circuit now I'm able to do some circuit problems. thanks, isn't enough for you man
You know it's funny on how every time I get stuck in any subject except of Bio,you and your videos just step in and save me. You are like a super hero.
Thank you very much sir,you are a life saver,not sure there Is a way to repay you.
Hi sir, i am sure the calculation is wrong at 28:14, the current passing the 4 ohm resistor must be 1.76. It cannot be 0.576 because then the total current won't be 4.615, and so you violate KCL, and we calculated the current across the resistor is 1.76A
Yeah he mixed them up. But switch the current for i1& i2 respectively and you'll get them right
I was confused as hell and then I watched your video and now I feel like a professor🤣 Thank you so much! Your videos are always great and detailed!
THANK YOU for bringing physics to it's knees
At 29:32 the current should have been 1.72.
For some reason this has conceptually been one of the hardest topics for me to grasp at the beginning.. thanks for helping clear it up!
I gotta test in 1hour and I'm watching a your videos now
your silky smooth voice and calm delivery makes understanding physics SO MUCH BETTER
28:05 Shouldn't the current flowing through the 4 Ohm resistor be 1.7295 A?
He fixes it later, in case you never watched all of the video.
Somehow this made less sense than my teacher's explanation
In physics class, to combine parallel repressors, we have been using the formula 1/Rt =1/R1 +1/R2, but that doesn't seem to be in your video. I'm still kind of struggling to understand circuits as a whole, and it would be very helpful to me if you could explain that rule/ its relevancy to circuits. The right hand rule also has been confusing me as well.
I love your videos, they've helped me loads in AP Chem and in physics. I'm really glad that there are people out there who make videos to help others, rather than click-baited videos.
1/Rt = [1/R1 + 1/R2] and don't forget it's to the power of -1
You only combine them when u are trying to figure out the current encompassing the whole device (circuit).
Once you do that you can troubleshoot your device with a multimeter and see where its failing you.
didiroxforever that method still applies, in the first question he did he said the total resistance for the the two ten ohm resistors in parallel was 5. He got that by adding 1/10 + 1/10 then finding the inverse of that answer
thanq for helping us....but i wish the audio quality means sound shall be much higher (if i keep full volume in my pc it was not audible
Thanks teacher very much I appreciate you!!!!?
With the first example, I'm confused how KVL can still be followed there HAHAHHAHAHAH
@20.05 why current flowing through A to F is 4.615A ?
I appreciate your videos so much. Just started learning RC circuits in lecture this week and I didn't understand anything, but after this video I feel so much better about solving these questions! Thank you!
Did I hear him put 15/10 in his calculator 🤣
Still Appreciate the help bro!
To compute 2 resistor in parallel with different value just multiply the Numerator then add the Denominator and Devide the value that you get in 15:31 minutes 12 * 4 = 48 (Numerator) then 12 + 4 = 16 therefore 48/16 = 3ohms
Sir to find Potential at F we are moving from A to F by this way it will be Va - Vf and Vf will be -2
I didn't understand anything at school but after this video I feel like a wise 😂😂 thank you best teacher ever.
Hello first of all let me thank you because I learned a lot from you but in case i think you have a mistake on this sum .if you leave with 120volt and you subtract 4.616 and x10 comes 73.85v how come the other side you have 55.38v ? the voltage total don't add up because if you leave with 120v you need to finish 120v right and 73.85+55.35=129.23 right and how can be u step up in voltage? Thanks
You are a really good teacher. Are you some type of technician or engineer of some kind?
I see some people asking how you can appreciate this person for his work, please check out the donation link in the description.
Me: Writing 3 Ohms inside the circuit
My brain: But Organic Chemistry Teacher wrote it outside
Me: It doesn't make a difference
Me after to seconds writing the 3 Ohms inside the circuit
"and so 15 divided by 10 -"
*aggressively slamming calculator buttons*
".. is 1.5"
really
Don't skip his ads.
I've recently discovered your series. I did so because I have an opportunity to test for a position in an Aerospace company as an Electronic Service Technician. This position will be responsible for diagnosing electronic systems involved in industrial controls. My degree in Electronics is 46 years old and although I have been involved in diagnosing and repairing complex electronic systems in Automotive, I feel out of my element moving into industrial controls. I have some familiarity with their systems and PLC controls due to my experience with the same company as a CNC machinist on purpose built CNC equipment. Having said all this, I am having difficulty in sorting out an order of lectures in which to study your content. Is there some kind of indexing system so I can know what lectures to study in what order? Thanks
Actually very good video for all physics students
Man you're whoever you think you are, no youtube tutor comes close not even an inch closer the gap is too wide. See how I understood this equivalent resistance effortlessly. I've never regretted subscribing to your youtube channel and I will make sure my course mates subscribe to your channel as a form of appreciation to the amount of work you put in just to make us understand seemingly complex topics easily. Because almost all my course mates did not understand this topic when the lecturer came to deliver to the class.You'll be the reason why i will graduate with First Class. thanks once again! Gracias
There are parts I still don't understand😢
Thank you so much I like how you resolve series-parallel problem . I could not finish my homework without your video. Thanks a lot
Your videos are good but next increase your volume loudness. I have to take my volume to max
Proof, once again, that expertise in a subject is never a substitute for skill at explaining a subject.
Rhetoric and expertise in a particular domain are two different skill sets.
There are no good introductions to DC circuits on the (free, non-paywalled) internet, and frankly, anarchic train wrecks like this and Khan Academy do more to gatekeep knowledge than to share it.
This is, as Edsgar Djykstra used to say. "considered harmful."
Great explanation! Would love for any tips for someone like me starting up anything helps! Cheers.
In a parallel circuit there are 4 unknown resistors R1= R1, R2= 3R1, R3= 6R1, and R4= 2R1) where the total voltage is 20 volts, and total current is 4 amperes, what are the specific values of R1, R2, R3, and R4?......please help
I calculate all power in every resistor but when I add it, it is not equal to the power delivered by the battery. Please explain.
*in example 2
@@annamaecustan9357 I Have the same problemmmmm. A year or so later, but did you figure it out?
@@jixu7146
I was stuck like that for a while because the powers doesn't add up, then I realized I got the voltage wrong on the 8-ohm resistor and when I replaced it it adds up almost the same. So I guess you just have to be careful with your values and double-check.
Total Power = (4.62 A)(120 V) = 554.4 W
Power of Each Resistor:
1. (46.15 V)(4.615A) = 213.02 W
2. (1.73 V)(0.58 A) = 1.00 W
3. (5.19 V)(0.57 A) = 3.01 W
4. (6.92 V)(1.73 A) = 11.97 W
5. (11.54 V)(2.31 A) = 26.66 W
6. (18.48 V)(2.31 A) = 42.65 W
7. (55.38V)(4.62 A) = 255.86 W
Summation of power absorbed by each resistor:
(213.02 +1.00 + 3.01 + 11.97 + 26.66 + 42.65 +255.86)W = 554.17 W
Man youve helped me get through my electronics engineering program
Id love to buy you a beer but ad revenue will have to do
Nice!
after calculating potential at C that is 30v , why current from A to F is 3A ? unable to understad
Why isn’t 10ohms + 10ohms + 5 ohms added up together too? It’s also in series.
Series means the current is the same throughout the path. At each junction (or branch) current changes, so they aren't in series.
Your are the best teacher that I ever come Across👍
One question?? How to know which branch (series or parallel) appears next when simplifying the resistors.?? E.g. when solving 3 ohm with 9 ohm, why we got a series branch and not a parallel one??
Great video bud really helped me. Also you sound like Mark Wahlberg lol.
The current flow across 4ohms is not 0.5765amp. It is 1.729Amp. Finally that you’ve corrected it.
There is also another way you could solve the current going through the 3 branches @ 28:00 , you could find the equivalent resistance of r1 and r2, then use that equivalent resistance and the current to find the voltage once you have the voltage you could then find the individual current of r1 and r2.
How do you find the voltage of one with the equivalence of all resistors
im currently preparing for my jee, it was helpful your just the best at the subjects and even better at explaining than our indian teachers...❤
Nice thankz for your effort....its really help me lot...thank you so much....
Thanks you so much.🙏 You're very helpful. I love the way you tutor. Honestly you're a second version of Albert Einstein.😂
100 dislike for the memes also liked all ur other vids
Great work! when calculating the currents at each resistor, i get lost due to the resistors not being labelled.
your videos have helped me so much, thanks again for sharing your knowledge
It was so helpful thank you very much ❤️❤️❤️💜💕♥️♥️💕💜❤️
ily! You solve the problem that has been bewildering me for the whole day! My life would be much easier if I discovered your channel earlier!
10ohms in the middle is 15 volts. 5ohms in the top right is 7.5 volts. 3ohms is 4.5 volts.
I refreshed 5x and watched 5 ads your welcome #adRevenue #jefferyepsteindidntKCLhimself
Could you make a member section for people to support you
Hello I just became a member and want to know what are benefit of that and how you can help me with my project. Thanks
i can only say wow on how i advanced from zero to hero after this video, god bless you tutor love you from the bottom of my heart;)
Can someone please remind me maybe in like 10 years about this channel? Because hopefully I'll have lots of money to giveaway for this legend. You deserve my tuition fees.
Sir it was great but you should have taken all the values of whole no.s .
Please help me, at 6:46 i don't understand why the current go from C to F is different from the current from B to C and F to A
I like how at 6:46 you can hear him type in a calculator when doing 15/10, relatable. 😂
I don't know how to say this without sounding like a prick, but although your answers are right, your method isn't correct. It worked because your resistance values had a particular numeric theme, however the voltage drop across a series resistance is simply total current X individual series resistance. If you did this video and changed resistance B / C to 5 ohms and resistance a/f to 10 ohms it wouldn't work the same.
I think its also worth mentioning that you stilp did a great job on the video, and I couldn't do better or equal. I do feel it was necessary to point out the flaw.
Walter Lewis said if u dont like fizix u are studying it from the wrong teacher
I am having some trouble with doing some combination series parallel circuits. Can anyone help?
i am from india and I am too having the same problem !
if the two 10 ohm resistors are in parallel, why is voltage not constant between them?
Thank you very much
Why the 4 ohm resistor is drawn in such a way? (15:32)Can anyone explain?
Damn I wonder why you have 8M subscribers 0:00 Oh that's why 34:00
I've been stuck trying to understand this for two days until I watched your video. Exam tomorrow at 8. You saved my life as you did so many times. Now I wanna marry you.
I made the final checked and got the total e potential absorbed by the resistance and its near from the power delivered by the batterry (130 volts), why is it not exact to 120 volts? (I already double-checked the solution)
This vid will be why I wont fail my test tomorrow I wish teachers actually explained stuff instead of relying on one youtube channel for students to understand. Thanks anyways GOAT
sir can you give me a link of your video that is the same as this with transistor? im confused how to compute
How come dividing 30V by 10 ohms does not get your current from C to F? I thought I = V/R.
here's a linus tech tip, continue the great work thank you
What if there is no resistance between F and A. How to calculate potential at F
At 18:05 shouldn't the current that is leavig the battery be 12?
120v = I x 10ohms
I = 120v/10ohms
I = 12A???
hi, at 20:46 , what if there is no 12 ohm resistor between point A and F , then how can we calculate the current passing through 8ohm resistor between C and F?
Good question! I think F will equal 0 volts, which will give you a current of 9.23 (73.85 - 0 = 73.85 ÷ 8). Then you use that number to get the separate current for CD & CE by using the equation he showed us.
That's just my guess though. I'm 99.9% confident.
Thank you bro I didn't attend class in which this was explained and i was left behind and i don't wanted to ask my teacher to explain me the whole xoncept just because i didn't attended the class you saved my life
BRUTAL