"The Intersection of Exponents: 2^x = x^4" |

[@cyruschang1904]

2^x = x^4
(2^n)^(x/n) = x^4
x/n = 4 => x = 4n
2^n = x = 4n
n = 4, x = 16
2^16 = 16^4

[@humbertorodriguezperez1214]

log (2^x) = log (x^4)
x log 2 = 4 log x
(log 2)/4 = (log x)/x
4*(log 2)/(4*4) = (log x)/x
(log 2^4)/16 = (log x)/x
(log 16)/16 = (log x)/x
So x = 16