Видео

Mr Humber your method is excellent and so simple❤🎉

Time wasting. Referee will issue a yellow card

While I understand showing the process so that others can know, I was able to figure out it was within 2-3 seconds. Which, it surprises me that I can still remember the process after 20+ years since being in a math class.

? = x , 3(3^5) = x^2 3^6 = x^2 3^(3+3) = 3^3 × 3^3 = x^2 x = 3^3

2^x = x^4 (2^n)^(x/n) = x^4 x/n = 4 => x = 4n 2^n = x = 4n n = 4, x = 16 2^16 = 16^4

log (2^x) = log (x^4) x log 2 = 4 log x (log 2)/4 = (log x)/x 4*(log 2)/(4*4) = (log x)/x (log 2^4)/16 = (log x)/x (log 16)/16 = (log x)/x So x = 16

Chuân m = 3 nhe

X=3

(3^5(1+1+1))^1/2=(3^5(3))^1/2 =(3^6)^1/2=3^6/2=3^3(A)

C

9x3=27=3×2=6=3×3=9=3/2

(10^3+2)^1/2=(10)^5^1/2 =1₫^5/2(C)

Is it true😢

Best of luck ❤

great video, btw i think there is an easier method: √x^7 can be expressed as √x^2*x^2*x^2*x, because the squares and root cancel out we end up with x^3√x=27√3 now its easy to deduce that the only number that satisfies both parts (x^3=27 and √x=√3) is 3

10^5/2

B

B) +/-2

9=3X3; 2X+2=8; Х=3

Excelente , me ayudo mucho

c

3

A❤

C is the answer

( x - 7 )^2 - 6^2 = 0 ( x - 7 - 6 )( x - 7 + 6 ) = 0 ( x - 13 )( x - 1 ) = 0 x = { 1 , 13 } 👍👋

31

C❤

C

❤

31x4=124

C

Can solve like this? I feel much more easier X³ + X² = 4X² X³ = 3X² X³/X² = 3 X = 3

2 solutions.x=3 or x=0 x3+x2-4x2=0 x3-3x2=0 x2(x-3)=0 x2=0 or x-3=0 x=0 or x=3

√8+√8+√8/√24 = 3⋅√8/ √24 = √3⋅√3⋅√8/√24 = √3⋅√(3⋅8)/√24 = √3 √24/√24 = √3⋅1 = √3

88

8

5

25

5

(7)^1/2(1+1+1)/(7)^1/2(3)^1/2=3/(3)^1/2 =(3)^1/2×(3)^1/2/(3)^1/2=(3)^1/2

4❤

25

Thanks

4

4

4

3V(7/21)= 3V3/3= V3

√3

√7+√7+√7 /√21 3(√7)/√3*√7 3/√3 √3*√3 /√3 =√3 D)

4