I understand the math as you do it. But I don't understand how you see ahead of time, what your substitutions will be, if that makes sense. Sense you don't explain what you are "thinking", I'm not mattering your secrets 😢
I think he looked at this problem as an application of the law of exponents. In particular, x^m*x^n = x^(m+n). Since x^2*x*8=x^10. That's the end. He works forward one step at a time to get to the end that he wants. SN: Since x is a binomial, it is easy to square: (a + b)(a+b) = a^2 +2ab +b^2.
@@yoonyounghwanshare your mail id I am sharing the solution. These are not difficult mathematics at all. If you want to have difficult mathematics then try jee-advance paper. I think you would like it.
I think this method is how to get eliminated from Harvard entrance exam. Use calculator, unless you want to practice substitution and expanding of brackets. There is no mathematical conception here only repetitive computation.
Unless I’m missing something it confuses me sq.rtof 2= 1.44 minus 1 = 0.44 and raising to 10th power gives me 0.000…. result.A follow through of the final result in the video gives -61.32.
@@robertveith6383 Okay so it's 0.000148676..... . A really big number right? Essentially negligible, unless you're talking about atoms or electrons, right? So no I will not delete my post. Take a hike, pal.
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I understand the math as you do it. But I don't understand how you see ahead of time, what your substitutions will be, if that makes sense. Sense you don't explain what you are "thinking", I'm not mattering your secrets 😢
I think he looked at this problem as an application of the law of exponents. In particular, x^m*x^n = x^(m+n). Since x^2*x*8=x^10. That's the end. He works forward one step at a time to get to the end that he wants. SN: Since x is a binomial, it is easy to square: (a + b)(a+b) = a^2 +2ab +b^2.
روتین و ساده و زیبا❤
It can be solved easily with binomial theorem
Tell us
@@yoonyounghwanshare your mail id I am sharing the solution. These are not difficult mathematics at all. If you want to have difficult mathematics then try jee-advance paper. I think you would like it.
The answer is:
A little bit more than nothing......
Amazing 😍
I think this method is how to get eliminated from Harvard entrance exam. Use calculator, unless you want to practice substitution and expanding of brackets. There is no mathematical conception here only repetitive computation.
Can i just seperate it into five ((√2)-5)^2
Excellent explanation thank you sir
You are welcome, Thank 🙏❤️🙏
The answer is more complicated than the initial. It's not a simplification.
The directions should be: "Expand this expression and write it as A + Bsqrt(2), where A and B belong to the set of integers."
❤
I use pascal triangle theorem and we arrived at the same answer
It was helpful. Thank you🎉
Unless I’m missing something it confuses me sq.rtof 2= 1.44 minus 1 = 0.44 and raising to 10th power gives me 0.000…. result.A follow through of the final result in the video gives -61.32.
6:14
niiiice
The answer is one.
Mastering
1 only
That is, 3363 - 2378(2)^(1/2) = 3363 - 3362.99985... which is basically 0 (zero)
No, it is *not* "basically" zero. You're wrong. Delete your post.
@@robertveith6383 Okay so it's 0.000148676..... . A really big number right? Essentially negligible, unless you're talking about atoms or electrons, right? So no I will not delete my post. Take a hike, pal.
그냥 직접 계산하는게 더 빠름 ㅋㅋ
Сначала возвести в квадрат будет 3 - 2 корней из 2, а потом всё возвести в пятую степень представив как квадрат помножить на куб быстрее и легко
Да, я тоже бы таким способом решала, без всякой замены.
A P explain
Result is 0(zero)
Результат мелковат: 0,0003.....
10
0.0001...
When one works out the solution, the answer is ZERO.
No, it is *not.* You're wrong. Delete your post.
That's because √2 - 1 ≈ 1.141 - 1 ≈ 0.141, and 0.141¹⁰ = a very small number, about to be zero.
es hol van a megoldás
ez csak hablaty blablabla
Please see last calculation
Useless math question.
X=9-7=36
Y=7
MY NAME:T MELINDA
1973
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