Hey everyone, I'm here to help. If you have any questions or just want to learn more, click on the link in the description above. It'll take you to a page where you can ask me questions.
thank you. you're heaven sent to us. Chemistry looks so terrible to me but you made so simple to understand! i wish you're my teacher. More blessings to you my idol.
Your videos have saved my life. This is my first year of teaching. I have a degree in English education and a Master's in literature, and the only teaching job I could find was a chemistry teaching job. I would've been lost this semester without your help. Thanks so much, and keep up the good work.
@Farawla You ONLY have to convert if you have two different pressure units. Kpa, atm, mmhg are all fine if BOTH pressures are in those units. So if P1=23 kpa and P2=84 kpa, you're fine. But if you have P1=23 kpa and P2=4.5 atm, then you have to convert one of those two pressures so that they're both in the same units. Does that make sense?
I went back to school to become a Veterinary Technician and I am currently taking Chemistry. Unfortunately, I have a teacher that just reads off power points and doesn't show us problems or solve problems together with us (even when we ask). I was suffering through Chemistry until I saw your videos. Thank you so much! I will probably pass this class and go on to the Vet Tech program because of you! *hug*
Don’t be fooled by his young look. His ability to teach will amaze you and make you love learning. He is a great communicator and teacher! It is always such a pleasure to see how he is able to excite learning and pique your interest in learning more about the subject. I seek his videos on the related topics before reading my biological chemistry textbook!!
Another way to solve the first problem would be cross multiplying. If you were looking for P2, for instance, you would multiply P1 and T2, and multiply P2 and T1. This would get you P1xT2=P2xT1. To get P2, you have to isolate it, or get everything else on the other side of the equation. So to get P2 on on side, you would divide T1 from both sides, because if you do something to one side, you have to do it to the other. T1 divided T1 cancels it out on the right side. On the left side, you put the entire part over T1 to get P1xT2 divided by T1, or P1xT2/T1. This leaves you with P1xT2/T1. Then you just plug in the numbers and solve! I hope this helped! This took a while to write (I am in 8th grade btw, so its a little confusing to me).
Hi ur videos r very helpful. don't u have any videos on the explanation of gay lussac's law of gaseous volumes like you have on Avogadro's law? I did not find any.
Tyler I somehow have 'hot' wheels; My tyres are flat and have an air temperature of 293 Kelvin and a pressure of 101.3 kPa. If I pump my tyres up to 230 kPa what is the temperature inside the tyres? T2 = T1 x P2/P1 T2 = 293 x 230 kpa / 101.3 kPa T2 = 665 Kelvin!! This cannot be right - where did I go wrong?
Can I just use the equation T2=p2xt1 divided by p1? haha I dont want to do what you did up there doing many stuffs just to get the T2=p2xt1 divided by p1
Hey I'm like a newborn in ur channel but sir thank you so much this save me from my exam this coming march. Bcuz i'm homeschooled and gotta go to school for me to take the test... tnx! =>
What happens when there is a range of temperatures and they ask you for the final temp? I.e: the temp of a sample of gas in a steel tank at 2.81 arm is increased from -117.4 C to 5100 C to 94.8 C. What is the final pressure inside the tank?
Hi can you answer this. An aerosol container has a pressure of 3.00 atm at 30.0°C. what is the new pressure in the aerosol container if it is thrown into a fire with a temperature of 600°C? The aerosol can explode if the pressure inside exceeds 7.00 atm. Would you expect the can to explode? Im stuck with this. I need help pls🥺
On the second problem, can't I just multiply the P2/T2 to P2? And then cancel the P2 to leave a T2 alone. Is it possible or nah? Please answer. Thanks.
he’s still saving kids in 2020
Yes
Yep
yes
Now in 2021 too
True, so true
Hey everyone, I'm here to help. If you have any questions or just want to learn more, click on the link in the description above. It'll take you to a page where you can ask me questions.
Hello,I am from Bangladesh. Can I use this in higher secondary education (class 12)?
Why we have to convert to kelvin as he asked calculation of temperature in Celsius in the second problem?
yes, it's called "gas pressure conversions." i made it a long time ago, so it looks really ghetto, but the information is solid.
Hello, I am watching in 2020🙂☺
@@Mutthalbaaz_____Official227 silence fool
@@diegorivas821 WTF, what do you wanna say lame 🤐🤐
@@Mutthalbaaz_____Official227 Silence fool!
This is really helpful !thanks a lot
thank you. you're heaven sent to us. Chemistry looks so terrible to me but you made so simple to understand! i wish you're my teacher. More blessings to you my idol.
Your videos have saved my life. This is my first year of teaching. I have a degree in English education and a Master's in literature, and the only teaching job I could find was a chemistry teaching job. I would've been lost this semester without your help. Thanks so much, and keep up the good work.
@Farawla You ONLY have to convert if you have two different pressure units. Kpa, atm, mmhg are all fine if BOTH pressures are in those units. So if P1=23 kpa and P2=84 kpa, you're fine. But if you have P1=23 kpa and P2=4.5 atm, then you have to convert one of those two pressures so that they're both in the same units. Does that make sense?
Well thats confusing
@jobicutooo great. also, you might want to check out the "gas law faq and extra help" video.
I went back to school to become a Veterinary Technician and I am currently taking Chemistry. Unfortunately, I have a teacher that just reads off power points and doesn't show us problems or solve problems together with us (even when we ask). I was suffering through Chemistry until I saw your videos. Thank you so much! I will probably pass this class and go on to the Vet Tech program because of you! *hug*
Did you pass the class?
Really helps when you explain them slowly and in detail
how are you these days
you helped me pass.... God bless you thank you
Don’t be fooled by his young look. His ability to teach will amaze you and make you love learning. He is a great communicator and teacher! It is always such a pleasure to see how he is able to excite learning and pique your interest in learning more about the subject. I seek his videos on the related topics before reading my biological chemistry textbook!!
@pepteamsergi09 for the answer to this, watch my video called "addition and subtraction with significant figures."
This is great teaching. I am totally new to gas law and your collection of videos helped me immensely. thanks so much. cheers
Yes I am watching this the night before my exam how did you know..
You could just cross multiply using p1 over t1 equals p2 over t2 you will get the same answer
But how about converting it to Celcius like the problem no. 2 in 11:45 ?
why are you not my teacher???? omg thank youuuu
+VIP 2NEXO 2NE1
CeGeeCe omg blackjack!!!
@@VIP2NEXO hello
Yeah
Thank you for the walk through on how to solve these problems.
Your videos are saving my grades thank you so much!!😭
man im speechless your the best
100 million respects for you and the short easy to understand lecture
Another way to solve the first problem would be cross multiplying. If you were looking for P2, for instance, you would multiply P1 and T2, and multiply P2 and T1. This would get you P1xT2=P2xT1. To get P2, you have to isolate it, or get everything else on the other side of the equation. So to get P2 on on side, you would divide T1 from both sides, because if you do something to one side, you have to do it to the other. T1 divided T1 cancels it out on the right side. On the left side, you put the entire part over T1 to get P1xT2 divided by T1, or P1xT2/T1. This leaves you with P1xT2/T1. Then you just plug in the numbers and solve! I hope this helped! This took a while to write (I am in 8th grade btw, so its a little confusing to me).
thank you so much, all of the videos are so helpful
I think i may be able to pass chemistry now that I learn better from you! Thank you!
Your videos are terrific at explaining these problems. However I was wondering if you have to convert the pressure from kPa to atmospheres?
you rock! i have an test tommrrow on this and this help a lot ! thanks a ton :D
thanks for the vids! there really helpful? But i was wondering , my class is doing ideal gas laws is there a order of videos you recommend watching
Thank you! This was so helpful with my Chemistry project! I'll be subscribing and watching your videos for fun. . . :)
patrick jmt and tyler dewitt you both rock
You are so much better than my chemistry teacher oh my god
Do you have a video on this? Converting Kpa to mmHg? Great videos by the way. =)
u r osum teacher I glad that I learning from u thanku so much for brightening my future. 😊😊😊😆😆😆
THANK YOU SO MUCH! I don't know why my chemistry teacher cant teach. I was able to learn how to solve gay lussac law in 5 minutes thank you so much
You saved my life with this! Thanks!!
Hi ur videos r very helpful. don't u have any videos on the explanation of gay lussac's law of gaseous volumes like you have on Avogadro's law? I did not find any.
Still saving 2021 kiddo. 🙌💪
YOUR VIDEOS ARE AMAZING THANK YOU
Those are some really nice markers really satisfying when he circles the answer idk why
Thankful for this video, it really helps me!
Thank You Sir Tyle DeWitt i really understand your discussion..
You should be my chemistry teacher， this is damnnnnn helpful！！
Thanks for saving us in 2022
THANK YOU SO MUCH. NOW WE LEARN HOW TO SOLVE IT AND IT IS JUST EASY THANKS
Thanks you are the best!!!!
You always help me!!!!
thank you, this was really helpful.
You're saving me in this topic☺️ 2021
Tyler I somehow have 'hot' wheels;
My tyres are flat and have an air temperature of 293 Kelvin and a pressure of 101.3 kPa.
If I pump my tyres up to 230 kPa what is the temperature inside the tyres?
T2 = T1 x P2/P1
T2 = 293 x 230 kpa / 101.3 kPa
T2 = 665 Kelvin!!
This cannot be right - where did I go wrong?
we can apply the rules of cross multiplication instead of the long method right? anw this is helpful thank you!!!
Thank you sir, you are awesome!
Its actually helping me to advance my knowledge 😊😇
youre fantastic, thank you!!
Can I just use the equation T2=p2xt1 divided by p1? haha I dont want to do what you did up there doing many stuffs just to get the T2=p2xt1 divided by p1
Thank you so much!! 🧡
Omgg thank you, you just saved my life !!
Thank you, Mr. Dewitt!
oh yas, finally, you really helped me with that thanks alot! :D
Thank u sooooo much !! you helped me a lot with your vedios !!! Your student from Algeria ^^😊😊
im always surprised on how fast i understand things from this guy
Hey I'm like a newborn in ur channel but sir thank you so much this save me from my exam this coming march. Bcuz i'm homeschooled and gotta go to school for me to take the test... tnx! =>
is it ok to convert the temperatures to Rankin if the question posts it in Fahrenheit?
What happens when there is a range of temperatures and they ask you for the final temp? I.e: the temp of a sample of gas in a steel tank at 2.81 arm is increased from -117.4 C to 5100 C to 94.8 C. What is the final pressure inside the tank?
Can the ideal gas law be applied to a propane tank? If not how can you calculate the pressure?
Thanks for the great video. Couldn't you just cross multiply to make it easier though?
Thank you
You make it simple
thanks u helped me a lot in my exam all the best
Hi can you answer this.
An aerosol container has a pressure of 3.00 atm at 30.0°C. what is the new pressure in the aerosol container if it is thrown into a fire with a temperature of 600°C? The aerosol can explode if the pressure inside exceeds 7.00 atm. Would you expect the can to explode?
Im stuck with this. I need help pls🥺
thank u so much for this
really helpful
When you explain it its so simple
Damn you mr.roy why can’t you teach like this dude
how to find what's p1, p2, t1 or t2? im a little bit confused with that part
what happens if you have two pressures but one temp. would the equaltion be P1/(T1)(P2)=T2??
how can i repay you? thank you very much! you're very helpful and kind!!
why are you not using 273.15 for the conversion from C to K?
Another way: Cross multiply (P1 x T2 and P2 x T1)
On the second problem, can't I just multiply the P2/T2 to P2? And then cancel the P2 to leave a T2 alone. Is it possible or nah? Please answer. Thanks.
Thank you Tyler!!!!!!
Thanks very much bro i understand it easily ❣️
It worth it and help many people.💪thanks
Can i ask where did you get 273?
Because of you my friend I might pass chem
Sir please come up with some difficult questions
THANK YOU A LOT!!!
THANK YOUUU! YOU'RE THE BEST
ugh my teacher makes my head hurts.
i love you. now i won't fail my chem test!
lol I was watching my online lecturer and did not explain jack, thank god for this video
He's still saving kids in 2023
very good and fantastic videos for those students who can study in RUclips Plater
I like it .
when talking about rounding.. if we use K= C + 273.15 then u'll ended up with 298.45??? so when rounding when don't??
Please include captions it would help greatly
its. . P2=P1 T2 over T1.. and it has a point which is total of 257.46 Kpa. but it helps me alot. .tnx
Thank you!
Thank You!
Thank you very much😍😍😍😍😍
What if what's missing is the P2 and T2??
Sir please take some difficult questions.the questions which you have taken are very easy.
In Boyles law you have to convert the kPa why didnt you convert it into atm in the first question?...PLEASE HELP!!!
I'm here 10 years from the future.
Where you get the 257 kPa
Sir i am from india .I request to you to upload. Video on law of multiple proportion
nice one.. good Job
you are amazing!!!!