Properties of Pure Substances - Thermodynamics

[@WannabeProfessor86]

Make sure you check the review problems too: ruclips.net/video/DwfUX_qe3tM/видео.html

[@Raniaska0306]

Man you just explained the entire chapter in 60 minutes which took my prof at least 3 hours to teach x)))) Thank you so much!!

[@WannabeProfessor86]

Thanks. I hope the video is helpful.

[@Cryptorie]

Wow I am short of words I can’t believe this is so simple to understand thank you so much please continue other topics like compressible flow and heat transfer

[@WannabeProfessor86]

Thank you :)

[@adriandesixto1007]

this is helpful for us students suffering from
online class, thanks a lot

[@dimitriladas2888]

this is probably the best lecture ive seen online

[@WannabeProfessor86]

Thanks. Glad you like it.

[@abeerhussain8074]

Thank you so much Sir!! only in one day I understood Pure Substances.. You are the best :)

[@nurfatihah5633]

THANKS, A LOT, FROM YOUR VIDEO I EASY to LEARN ABOUT THIS CHAPTER

[@WannabeProfessor86]

I am glad that you find this video helpful.

[@frankafroson4494]

this teaching is dope......i understand everything, thanks a lot.

[@WannabeProfessor86]

I am glad you enjoyed the video :)

[@blessingskaela2297]

Thank you very much professor for making thermal dynamics so easy with basic but yet powerful examples.🥺

[@WannabeProfessor86]

I am glad you found the video helpful.

[@vishalsathiaseelan679]

its Great Coincidence 😊 that Prof is using the same Reference Book as me Thermodynamics An Engineering Approach. Cengal CA, M A Boles

[@CharukaNiluminda-w7h]

very good help, thank you

[@WannabeProfessor86]

Thank you :)

[@leulabera9193]

I loved the video. you are an amazing teacher. I am hopefully expecting other mechanical engineering courses also.🙂

[@WannabeProfessor86]

Thank you :)

[@elahehardalani6124]

Very helpful, Thank you!

[@rkb8442]

Thank you sir for this very helpful tutorial..

[@semalseniru916]

thank you very much, this will help me pass my exams

[@WannabeProfessor86]

Good luck :)

[@vishalsathiaseelan679]

Prof you are truly a live saver. love your examples & analogies which helps me understand & remember the concepts. Pressure Cooker ❤ 👌👌Thank you so much for this great video.

[@WannabeProfessor86]

I am really glad that you found this video helpful.

[@dasundimantha8943]

Thank-you very much, sir ❤❤ This is very helpful for me.

[@WannabeProfessor86]

I am glad you found it useful. Thanks for the comment.

[@krispudyastuti5603]

clear explanation. Thanks

[@WannabeProfessor86]

Glad it was helpful!

[@mohmadsaber5503]

I guess thermodynamics is easier now ! :)

[@pfischer4664]

Are you going to do a refrigerant cycle video please :)

[@quadripopoola8706]

Thanks you are the best. I loved everything about the videos

[@imdivyaaaaa]

it is really helpful. thank you and do more about on execises and solving problems.

[@WannabeProfessor86]

I have a separate video on exercises from this topic. You can use the link: ruclips.net/video/DwfUX_qe3tM/видео.html

[@nipunfernando6689]

Superb!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

[@sangachidam3219]

excellent video. Thanks. I have few doubts. I am just a beginner so my question could be silly. At 15:5 you said the latent heat is a function of ( P,T). I didn't get this point. Following your video, I understand it is dependent on the pressure alone. At 39:58 you said 2 intensive and independent properties. I know about intensive, but not sure what is intensive and independent mean.

[@WannabeProfessor86]

Thank you. Interesting questions. Look at a T-h diagram, for example. The amount of latent heat changes when the saturation pressure (or saturation temperature) changes. That makes it a function of both.
For your next question, think of pressure and temperature. Let's assume we are talking about liquid water. You can have liquid water at 1 atm and 20 C, or 1 atm and 40 C, or 3 atm and 40 C. All of those states are valid, meaning that temperature and pressure are two independent properties. Changing one does not change the other.
I hope this comment helps.

[@venkatsai2833]

This is beauty 💖. Thank u ☺️

[@yishakgashaw7673]

absolutely wonderful lecture

[@WannabeProfessor86]

Thank you.

[@yigitcan824]

Professor I have a question why subscript *g* is is used when looking for properties of vapor ,I mean this *g* comes from the first letter of _gas_ right?But gas and vapor are different things?

[@WannabeProfessor86]

Great question. If you really think about it, vapor and gas are the same. When we use vapor, we try to emphasize that this gas form is coming from a liquid phase. We want to keep in mind that phase change between liquid and gas form either happened or is a possibility. I hope this helps.

[@sivaramraj4513]

Thank you so much for the class buddy 😭💥

[@WannabeProfessor86]

Thank you. I am really glad you found it helpful.

[@mahmoudalani2456]

Superrrr helpful, Thanks a lot

[@Weirdõ-b7w]

Tq very much sir......

[@NafiurRahman-w7p]

Great video😍

[@bunnyjoy2000]

Legit
Life saver

[@WannabeProfessor86]

Thank you :)
Good luck with your finals.

[@yipk7106]

These are amazing

[@WannabeProfessor86]

Glad you like them.

[@LearnSomething35]

Thank you

[@Zain-fc1yg]

Way u taught ezy pzy ❣️

[@muhammadiqbalbinnorinzan124]

Thank you, im ur fan hehe

[@muhammadiqbalbinnorinzan124]

I love ur video

[@tellatantoluwa9660]

Thank you sir

[@WannabeProfessor86]

I am just glad my video helped you :)
If you are enjoying the video, maybe check out the rest of the playlist as well. Thanks.

[@boraardaarzik5964]

thanks a lot

[@easymath591]

thanks boss

[@danzos_diary]

perfect

[@WannabeProfessor86]

Thanks. I am glad you found it helpful.

[@menglimarrero4296]

53:39
PV=nRT
PV=mRT
sir How is that
PV=RT
wh

[@WannabeProfessor86]

Good question. The ideal gas equation is PV=mRT where V is the actual volume. If you divide both sides by m (the mass), you get Pv=RT where v is the specific volume. That's the equation you see on the screen. Hope this helps.

[@abdelz1617]

Great video, thank you!