Thermodynamics - 3-5 Pure substances property tables - Changing states example 1

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Pure Substances
Water and Refrigerant
Thermodynamics Property Tables
Saturated liquid vapor mixture. Quality. Specific Enthalpy.
Rigid tanks. Closed Systems
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[@turk2589]

Your students are very lucky. When I was in the university, we had to deal with much harder problems in the thermodynamics exams, including double interpolations and complex systems.

[@turk2589]

By the way, your lectures are excellent, too.

[@burakemreevrenos8385]

Hangi üniversitedeydiniz hocam

[@mdlass4124]

Hey. shouldn't we also be using 0.0014 for v in the first part?

[@engineeringdeciphered]

Yes, it looks like I accidentally used the volume of 0.014, but should have been using the specific volume of 0.0014.

[@engineeringdeciphered]

But I think all the other numbers (the x and everything else) are still correct. I just miswrote it wrong there.

[@mdlass4124]

@@engineeringdeciphered oh okay👌🏽

[@jasperaj2487]

@@engineeringdeciphered came to comments to also as that thanks sir!!

[@asf_x1302]

I think the Volume is 0.014 m^3 , which means the 14L/1000m^3 = 0.014m^3
the quality X will be 0.19 for state1 and 0.393 for state 2 .. Am I right?

[@nourdarwish4277]

I think the same; because in state 2 (vf & vg) changed, so the quality (x) must change to be equal to 0.394😅
And H = 1527.846 kJ

[@ramiljr.donina4007]

specific volume was used, meaning 0.0014m^3/kg.

[@DiyaPatel-v9r]

This is a great playlist!! Do u have one for thermo 2 as well? i m taking it next semester after this course.

[@nourdarwish4277]

I think in state2 x isn't the same value as in state1; because in state 2 (vf & vg) changed, so the quality (x) must change to be equal to 0.394😅
And H = 1527.846 kJ, am I wrong teacher?

[@mothug978]

Professor, how did you find T= 0.61 C? Thank you in advance!

[@mothug978]

I got it... through interpolation of the Tsat between 280 and 320 Kpa.

[@abdallahhamdan4505]

@@mothug978 can you explain it please

[@mothug978]

@@abdallahhamdan4505 Your pressure = 300 Kpa, and need to find Tsat. By using Table A-12, you have to interpolate between pressure 280 Kpa and 320 Kpa to find your Tsat. Hope that helps

[@ibraheemmuslih4389]

How would I know if the 'x' value makes sense or not?

[@engineeringdeciphered]

X is zero if it’s a sat liquid and x is 1 if it’s a sat vapor. And x = 0.5 if it’s halfway between. So if your value is closer to the sat vapor value then your x should be above 0.5. If your value is very close to the sat vapor value then your x should be closer to 1.

[@ibraheemmuslih4389]

@@engineeringdeciphered Thank you very much

[@mkhairulirwantarmedi7356]

how do u find t

[@victorcasillas8057]

why didnt the equation for X, mass of vapor over total mass work ?

[@engineeringdeciphered]

Because we don’t know the mass of the vapor. So the way I did it is easiest. There is probably a way to find the mass of the vapor but it would be a lot more work than the way I did it.

[@victorcasillas8057]

@@engineeringdeciphered Thank you.

[@yigitcan824]

Professor where's the question 10 .Before this video its Q9 and in this video Q11

[@rayhangu8403]

Can I get that table?

[@engineeringdeciphered]

www.dropbox.com/s/tuqy5e8657ysoda/Property%20Tables%20-%20Appendices%201%20and%202.pdf?dl=0

[@turk2589]

You can also find the tables in the internet.

[@walkingunknown07]

x should equal to .19746

[@walkingunknown07]

for the first problem

[@engineeringdeciphered]

@@walkingunknown07 did you see this other comment? I think I miswrote .014 and should have been .0014. So I think my final answer is the correct one?

[@bereketgirma8613]

i think you made a mistake calculating vg