Dude all your videos are so good. I don't search for your channel explicitly - I'm usually looking for a fairly specific math thing, and your videos come up and are the most helpful. Thank you for doing what you do.
This absolutely helped me dude. I took trig last semester and we weren't allowed to learn this because it would make our trig problem solving easier, and now in calculus this was in the first homework for "Precalc review." Thank you!
Thank you this was really helpful. Could anyone please tell me how one would "find the domain in which the equivalence is valid" for a problem such as this?
Continue making videos like this! Very Helpful and a much clearer explanation than any other source... The consistency you have between videos ties up loose ends people may be having issues with.. Thank you!
This is pretty cool but since im studying at the shopping center and i forgot my earphones, i activated the subtitles... And omg they are funny as hell xD 😂
I hope that you have gone on to become a teacher. We may not value teachers financially but to share the understanding you have would be something of incredible value (sorry i am not making a lot of sense.. I have calculus brain from too much homework) What i am trying to say is THANK YOU!!
That is actually correct, as the two are equivalent! If you multiply both the numerator and denominator by sqrt(3), you'll get the intended result. This is a common simplification done so that there are no radicals in the denominator.
tan(arccos(x))
And... cos(arctan(x))? --> √ (x^2+1) ?
Thanks. :)
Good job.
This is such a great explanation! You're a wonderful teacher. Thank you :)
I really learned from his explanation! He was consistent with teaching and explained in detail through out the steps. Thank you...you were Great!
5 years later and this video is still saving lives...Thanks so much! Best explanation for this concept yet!
Thank you dude, I needed this for tan(arcsin(x)) and thanks to the video I was able to figure it out :))
Dude all your videos are so good. I don't search for your channel explicitly - I'm usually looking for a fairly specific math thing, and your videos come up and are the most helpful. Thank you for doing what you do.
Wow finally i found an explanation. THANK YOU!!!
thanks!!!! i was searching this explanation for a long time!
Thank you, this helped me a lot :)
This absolutely helped me dude. I took trig last semester and we weren't allowed to learn this because it would make our trig problem solving easier, and now in calculus this was in the first homework for "Precalc review." Thank you!
this man is mad, such a smart perspective i am just amazed
Thank you!!! Straight foward video, I finally understand. The best one on youtube
+Ellen Park Thank you for the nice comment!
What a clear explanation! Thank you so much.
Thank you @blackpenredpen, your video helped me clear up my own teachers mistakes
one of the most helpful videos ive ever seen!!!
+SquadCraft HackBusterz Thank you for the nice comment!
You're a life saver! I understand this now!
Marvelous. Thank you so much for this ingenious explanation.
THIS IS BEAUTIFUL
Very clear explanation, thanks a bunch!
I'm the 400 th like! Gret video homie, really helped me out!
Thank you, I could see the triangle in my mind's eye but didn't know how to explain it.
The only guy on RUclips who could explain this to me. Thanks bro
Thank you this was really helpful. Could anyone please tell me how one would "find the domain in which the equivalence is valid" for a problem such as this?
THANK YOUUU
Waow ! Short and clear explanation. Gold medal Sir !
Continue making videos like this! Very Helpful and a much clearer explanation than any other source... The consistency you have between videos ties up loose ends people may be having issues with.. Thank you!
You're welcome and will do!
Really nice work!! Thank you!
Ótima explicação. Obrigado professor!!! 👍👍👏👏
learned more from this video than an entire college course
This is pretty cool but since im studying at the shopping center and i forgot my earphones, i activated the subtitles... And omg they are funny as hell xD 😂
u sir have changed my life
great explanation!
Is there some other paths apart the triangle? Like by identities
I need this in unit circle by chance you still check I. This video other wise amazing!
you videos help me so much in refreshing my memory while studying!
That's great, thanks!
how do you graph that same function?
thank you from Brazil!
Super helpful, Thank you!
Omg! It was a clear explanation of the subject, thank you.
Miguel Gonzalez you're welcome
how to find the value of sine^-1(sine 60) ,where 60 is in radian?plz solve it by easiest way!
watching from Brasil, thank u so much
Thanks dude!!
thanks a lot sir!
Can you help me how to solve this questions ;
Sin^-1 m = 2 cos^-1 n , show that m^2 =4n^2(1-n^2)
Great explanation. Thanks!
+Kimberly Moore Thank you for the nice comment!
Thanks, understand it now! :)
Excellent explanation thank you!!!!
+Will Jon Thank you for the nice comment!
I hope that you have gone on to become a teacher. We may not value teachers financially but to share the understanding you have would be something of incredible value (sorry i am not making a lot of sense.. I have calculus brain from too much homework) What i am trying to say is THANK YOU!!
😃 I am glad to help. Thank you for your nice comments.
God I love this guy
Thank you so much!
thnx great video
I know video is old but moght as well ask.
Is this true: arctan(sqrt(x^2-1))=arccos(1/x)
great video, thank you
YOURE A HERO!!!
Thank you
Thank YOU!
thank u I finally udnerstaand
extremely helpful thank you
+Anna Solis Thank you for the nice comment!
Thank you.
thank you sooo much
Bro you gotta work on your SEO, literally looked up the title of the video and yours didn't pop up first. Just a piece of advice.
Alejo Pijuan what's SEO? Thanks for the advice. I have been paying attention to the title, description and tags more in my recent vids.
Thank you!!!
Finally found one iam looking Thank you teacher
ty
Thank you fam!~
Or you just know the identity sin(cos^-1(x) = sqrt(1-x^2) and then you split tan(x) into sin(x)/cos(x) and get the same result
haces un vídeo con composición de funciones a trozos por favor
me pierdo para decidir cual compongo con cual .
😅 Well done teacher
Thank u
😍😍😘😘😘
Thank you
god bless you
OH MY DAYS YES
God bless you
❤❤❤❤
How is tan[(arctanx)/2] ???
Dermanı yabancılardan arıyorum , buldum sanırım .
hermano casi que no !!! gracias
Im tryingto find tan(arccos(√3/2)) and i keep finding 1/√3 but the answer is √3/3
That is actually correct, as the two are equivalent! If you multiply both the numerator and denominator by sqrt(3), you'll get the intended result. This is a common simplification done so that there are no radicals in the denominator.
@@jacobcarrier9256 thank you
@@abuzerdag No problem, glad to help
this video is really helpful!!!!!!!!!!! it is very easy to solve this question which about arccos. 66666666老铁没毛病
كفو عليك
Helal 🇹🇷
口出mandarin普利士
我们要对这种行为说漏！！！
漏way，漏哄哄～～～
That was very ba d