GCSE Maths - Perpendicular Lines #75
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- Опубликовано: 25 авг 2024
- This video explains what perpendicular means, how to check whether 2 lines are perpendicular to each other and how to find the gradient of a perpendicular line.
This video is suitable for maths courses around the world.
KS3 - All on your course
GCSE Foundation - All on your course
GCSE Higher - All on your course
A-level - All on your course (but very basic)
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If you’d like to practise the material covered in this video, check out our platform at www.cognitoedu.org - it's totally free, and has been built to make learning and revision as easy as possible. The main features are:
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Amadeus & Tom
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This method is way easier, I had no idea you could multiply them to get -1. but they're also the negative reciprocals of each other so you don't even need to multiply them, you can see from the example at 2:44 that 3/2 and -2/3 are negative (one is positive, one negative) reciprocals (equation is flipped, so 1/2 reciprocated is 2/1). It's also way easier and faster for questions like the graph example
I learnt the same thing from Professor Leonard
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Request, sorry to bother, could you do equations on a tangent and circle?
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Great work
Thanks this will be helpful!
C is y intercept so the point that is on the y axis
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Nice explanation and animation.
How do you find C?
I can't thank you enough ❤
Thanks
hi i was wondering how you would find c for the last question?
I'm not too sure myself, but here's what I did:
we know the gradient is -3, like he said. The line intercepts with the known line at (3, 4). When the line is at 3 for x, the y is 4. 3 x -3 is -9. 4 - - 9 = 4 + 9 = 13. C = 13.
Leaving the final equation: y = -3x + 13
In essence, I suppose it is just multiplying x by the gradient, and then taking that away from the y coordinate they intercept at.
If I am wrong, then I apologise.
Hope this helps!
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what exam board are you science videos based on :)
We've tried to make them appropriate for all exam boards, but it's best to check with your textbook :)
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How can i graph if i found the perpendicular equation
Anyone here from Challney Boys high school in Luton???
Nah... but close enough... Am from Milton Keynes "St Paul's Catholic School"
@@Felixwas_there Nice to see you bro, Actually I didn't see you but nice to see your comment I should say. Are you in Year 11??
@user-xw1jf2dn3l yeah.. year 11... got gcses in another month!!
@@Felixwas_there Good luck bro, Hope you get very good grades. Just don't worry and give it your best shot, Results are not in your hands but effort is, so work hard and smash these exams, I believe you and you will be successful.
@user-xw1jf2dn3l thanks mate... cant lie.. it indeed is stressful.. i wish you also very best.... hope we get good grades !! Sending hugs... n daps...
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yr 10 for mocks😭😭
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@@KatonTyler3 mins ago lmao im watching this before school starts and i got the exam
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Thank u so much u helped me and now I can do perpendicular lines without struggling u the best🥹😁