GCSE Maths - Perpendicular Lines #75

This video explains what perpendicular means, how to check whether 2 lines are perpendicular to each other and how to find the gradient of a perpendicular line.
This video is suitable for maths courses around the world.
KS3 - All on your course
GCSE Foundation - All on your course
GCSE Higher - All on your course
A-level - All on your course (but very basic)
Maths Playlist:
• GCSE Maths (9-1)
GCSE Chemistry playlist:
• GCSE Chemistry - Atoms...
GCSE Biology Playlist:
• Video
GCSE Physics Playlist:
• Video

[@Cognitoedu]

If you’d like to practise the material covered in this video, check out our platform at www.cognitoedu.org - it's totally free, and has been built to make learning and revision as easy as possible. The main features are:
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Amadeus & Tom

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[@tonyzambonistarkoni7868]

This method is way easier, I had no idea you could multiply them to get -1. but they're also the negative reciprocals of each other so you don't even need to multiply them, you can see from the example at 2:44 that 3/2 and -2/3 are negative (one is positive, one negative) reciprocals (equation is flipped, so 1/2 reciprocated is 2/1). It's also way easier and faster for questions like the graph example

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Request, sorry to bother, could you do equations on a tangent and circle?

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[@canwenot7095]

C is y intercept so the point that is on the y axis

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Nice explanation and animation.

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How do you find C?

[@user-sx2bq5wq7k]

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[@neelkanthpatel9374]

Thanks

[@EO31_]

hi i was wondering how you would find c for the last question?

[@thejfisher9956]

I'm not too sure myself, but here's what I did:
we know the gradient is -3, like he said. The line intercepts with the known line at (3, 4). When the line is at 3 for x, the y is 4. 3 x -3 is -9. 4 - - 9 = 4 + 9 = 13. C = 13.
Leaving the final equation: y = -3x + 13
In essence, I suppose it is just multiplying x by the gradient, and then taking that away from the y coordinate they intercept at.
If I am wrong, then I apologise.
Hope this helps!

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what exam board are you science videos based on :)

[@Cognitoedu]

We've tried to make them appropriate for all exam boards, but it's best to check with your textbook :)

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[@albatrossmaryam8141]

How can i graph if i found the perpendicular equation

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Nah... but close enough... Am from Milton Keynes "St Paul's Catholic School"

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@user-xw1jf2dn3l yeah.. year 11... got gcses in another month!!

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[@user-ob4zr1lh1d]

Thank u so much u helped me and now I can do perpendicular lines without struggling u the best🥹😁