It's because Chlorine and Propene participate in both the above reactions. To calculate the extent of the reaction, we consider a product unique to the particular reaction. BTW, using HCl gives the same answer as 4.6 moles
Karthick actually you can there are 6 variables and we have mainly 4 equations and using other 2 equations relating p and q & r and a we can reduce 6 variables to 4 variables there by we have 4 equations solving those we will get the answer
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you are awesome!
Great lecture! 👏👏
Hello, in the last example, why don't we calculate HCl in the output equation for the reaction (a) for both od chlorine and propyne?
It's because Chlorine and Propene participate in both the above reactions. To calculate the extent of the reaction, we consider a product unique to the particular reaction. BTW, using HCl gives the same answer as 4.6 moles
U r awesome!
Thank you sir!🙇♂️🙇♂️
why isnt HCl being used in question 3 part a to find feed of cl?
How can i solve that 6 equations
same question here
Karthick actually you can there are 6 variables and we have mainly 4 equations and using other 2 equations relating p and q & r and a we can reduce 6 variables to 4 variables there by we have 4 equations solving those we will get the answer
Thank you sir
how to solve 6 equations in 12:45